哇。这些答案都不能处理分数的边缘情况，等等。当r, g, b为零时，位移版本也不起作用。

这是一个可以处理r g b是小数的版本。它对颜色之间的插值很有用，所以我也包括了这段代码。但它仍然不能处理r, g, b在0-255范围之外的情况

/**
 * Operates with colors.
 * @class Q.Colors
 */
 Q.Color = {
    /**
     * Get a color somewhere between startColor and endColor
     * @method toHex
     * @static
     * @param {String|Number} startColor 
     * @param {String|Number} endColor 
     * @param {String|Number} fraction 
     * @returns {String} a color as a hex string without '#' in front
     */
    toHex: function (r, g, b) {
        return [r, g, b].map(x => {
            const hex = Math.round(x).toString(16)
            return hex.length === 1 ? '0' + hex : hex
          }).join('');
    },
    /**
     * Get a color somewhere between startColor and endColor
     * @method between
     * @static
     * @param {String|Number} startColor 
     * @param {String|Number} endColor 
     * @param {String|Number} fraction 
     * @returns {String} a color as a hex string without '#' in front
     */
    between: function(startColor, endColor, fraction) {
        if (typeof startColor === 'string') {
            startColor = parseInt(startColor.replace('#', '0x'), 16);
        }
        if (typeof endColor === 'string') {
            endColor = parseInt(endColor.replace('#', '0x'), 16);
        }
        var startRed = (startColor >> 16) & 0xFF;
        var startGreen = (startColor >> 8) & 0xFF;
        var startBlue = startColor & 0xFF;
        var endRed = (endColor >> 16) & 0xFF;
        var endGreen = (endColor >> 8) & 0xFF;
        var endBlue = endColor & 0xFF;
        var newRed = startRed + fraction * (endRed - startRed);
        var newGreen = startGreen + fraction * (endGreen - startGreen);
        var newBlue = startBlue + fraction * (endBlue - startBlue);
        return Q.Color.toHex(newRed, newGreen, newBlue);
    },
    /**
     * Sets a new theme-color on the window
     * @method setWindowTheme
     * @static
     * @param {String} color in any CSS format, such as "#aabbcc"
     * @return {String} the previous color
     */
    setWindowTheme: function (color) {
        var meta = document.querySelector('meta[name="theme-color"]');
        var prevColor = null;
        if (meta) {
            prevColor = meta.getAttribute('content');
        }
        if (color) {
            if (!meta) {
                meta = document.createElement('meta');
                meta.setAttribute('name', 'theme-color');
            }
            meta.setAttribute('content', color);
        }
        return prevColor;
    },
    /**
     * Gets the current window theme color
     * @method getWindowTheme
     * @static
     * @param {String} color in any CSS format, such as "#aabbcc"
     * @return {String} the previous color
     */
    getWindowTheme: function () {
        var meta = document.querySelector('meta[name="theme-color"]');
        return meta.getAttribute('content');
    }
}

我正在使用XAML数据，具有十六进制格式的#AARRGGBB (Alpha，红色，绿色，蓝色)。利用上面的答案，以下是我的解决方案:

function hexToRgba(hex) {
    var bigint, r, g, b, a;
    //Remove # character
    var re = /^#?/;
    var aRgb = hex.replace(re, '');
    bigint = parseInt(aRgb, 16);

    //If in #FFF format
    if (aRgb.length == 3) {
        r = (bigint >> 4) & 255;
        g = (bigint >> 2) & 255;
        b = bigint & 255;
        return "rgba(" + r + "," + g + "," + b + ",1)";
    }

    //If in #RRGGBB format
    if (aRgb.length >= 6) {
        r = (bigint >> 16) & 255;
        g = (bigint >> 8) & 255;
        b = bigint & 255;
        var rgb = r + "," + g + "," + b;

        //If in #AARRBBGG format
        if (aRgb.length == 8) {
            a = ((bigint >> 24) & 255) / 255;
            return "rgba(" + rgb + "," + a.toFixed(1) + ")";
        }
    }
    return "rgba(" + rgb + ",1)";
}

http://jsfiddle.net/kvLyscs3/

function hex2rgb(hex) {
  return ['0x' + hex[1] + hex[2] | 0, '0x' + hex[3] + hex[4] | 0, '0x' + hex[5] + hex[6] | 0];
}

基于@ michazperzhaakowski的回答(EcmaScipt 6)和他基于Tim Down的回答的回答

我写了一个转换hexToRGB函数的修改版本，增加了安全检查r/g/b颜色组件是否在0-255之间，而且函数可以接受数字r/g/b参数或字符串r/g/b参数，如下所示:

 function rgbToHex(r, g, b) {
     r = Math.abs(r);
     g = Math.abs(g);
     b = Math.abs(b);

     if ( r < 0 ) r = 0;
     if ( g < 0 ) g = 0;
     if ( b < 0 ) b = 0;

     if ( r > 255 ) r = 255;
     if ( g > 255 ) g = 255;
     if ( b > 255 ) b = 255;

    return '#' + [r, g, b].map(x => {
      const hex = x.toString(16);
      return hex.length === 1 ? '0' + hex : hex
    }).join('');
  }

为了安全地使用这个函数——你应该检查传递的字符串是否是真正的rbg字符串颜色——例如，一个非常简单的检查可以是:

if( rgbStr.substring(0,3) === 'rgb' ) {

  let rgbColors = JSON.parse(rgbStr.replace('rgb(', '[').replace(')', ']'))
  rgbStr = this.rgbToHex(rgbColors[0], rgbColors[1], rgbColors[2]);

  .....
}

My example =) color: { toHex: function(num){ var str = num.toString(16); return (str.length<6?'#00'+str:'#'+str); }, toNum: function(hex){ return parseInt(hex.replace('#',''), 16); }, rgbToHex: function(color) { color = color.replace(/\s/g,""); var aRGB = color.match(/^rgb\((\d{1,3}[%]?),(\d{1,3}[%]?),(\d{1,3}[%]?)\)$/i); if(aRGB) { color = ''; for (var i=1; i<=3; i++) color += Math.round((aRGB[i][aRGB[i].length-1]=="%"?2.55:1)*parseInt(aRGB[i])).toString(16).replace(/^(.)$/,'0$1'); } else color = color.replace(/^#?([\da-f])([\da-f])([\da-f])$/i, '$1$1$2$2$3$3'); return '#'+color; }

我发现了这个… http://jsfiddle.net/Mottie/xcqpF/1/light/

function rgb2hex(rgb){
    rgb = rgb.match(/^rgba?[\s+]?\([\s+]?(\d+)[\s+]?,[\s+]?(\d+)[\s+]?,[\s+]?(\d+)[\s+]?/i);
    return (rgb && rgb.length === 4) ? "#" +
        ("0" + parseInt(rgb[1],10).toString(16)).slice(-2) +
        ("0" + parseInt(rgb[2],10).toString(16)).slice(-2) +
        ("0" + parseInt(rgb[3],10).toString(16)).slice(-2) : '';
}