function hex2rgb(hex) {
  return ['0x' + hex[1] + hex[2] | 0, '0x' + hex[3] + hex[4] | 0, '0x' + hex[5] + hex[6] | 0];
}

看起来你在寻找这样的东西:

function hexstr(number) {
    var chars = new Array("0", "1", "2", "3", "4", "5", "6", "7", "8", "9", "a", "b", "c", "d", "e", "f");
    var low = number & 0xf;
    var high = (number >> 4) & 0xf;
    return "" + chars[high] + chars[low];
}

function rgb2hex(r, g, b) {
    return "#" + hexstr(r) + hexstr(g) + hexstr(b);
}

My example =) color: { toHex: function(num){ var str = num.toString(16); return (str.length<6?'#00'+str:'#'+str); }, toNum: function(hex){ return parseInt(hex.replace('#',''), 16); }, rgbToHex: function(color) { color = color.replace(/\s/g,""); var aRGB = color.match(/^rgb\((\d{1,3}[%]?),(\d{1,3}[%]?),(\d{1,3}[%]?)\)$/i); if(aRGB) { color = ''; for (var i=1; i<=3; i++) color += Math.round((aRGB[i][aRGB[i].length-1]=="%"?2.55:1)*parseInt(aRGB[i])).toString(16).replace(/^(.)$/,'0$1'); } else color = color.replace(/^#?([\da-f])([\da-f])([\da-f])$/i, '$1$1$2$2$3$3'); return '#'+color; }

Tim Down给出的最高评级的答案提供了我所能看到的转换为RGB的最佳解决方案。我更喜欢这个十六进制转换的解决方案，因为它为转换到十六进制提供了最简洁的边界检查和零填充。

function RGBtoHex (red, green, blue) {
  red = Math.max(0, Math.min(~~red, 255));
  green = Math.max(0, Math.min(~~green, 255));
  blue = Math.max(0, Math.min(~~blue, 255));

  return '#' + ('00000' + (red << 16 | green << 8 | blue).toString(16)).slice(-6);
};

左移'<<'和或'|'操作符的使用也使这成为一个有趣的解决方案。

短箭头函数

对于那些重视短箭头功能的人。

Hex2rgb

大卫的答案的箭头函数版本

const hex2rgb = h => [(x=parseInt(h,16)) >> 16 & 255,x >> 8 & 255, x & 255];

一个更灵活的解决方案，支持短十六进制或哈希#

const hex2rgb = h => {
    if(h[0] == '#') {h = h.slice(1)};
    if(h.length <= 3) {h = h[0]+h[0]+h[1]+h[1]+h[2]+h[2]};
    h = parseInt(h,16);
    return [h >> 16 & 255,h >> 8 & 255, h & 255];
};

Rgb2hex

const rgb2hex = (r,g,b) => ((1<<24)+(r<<16)+(g<<8)+b).toString(16).slice(1);

我发现了这个… http://jsfiddle.net/Mottie/xcqpF/1/light/

function rgb2hex(rgb){
    rgb = rgb.match(/^rgba?[\s+]?\([\s+]?(\d+)[\s+]?,[\s+]?(\d+)[\s+]?,[\s+]?(\d+)[\s+]?/i);
    return (rgb && rgb.length === 4) ? "#" +
        ("0" + parseInt(rgb[1],10).toString(16)).slice(-2) +
        ("0" + parseInt(rgb[2],10).toString(16)).slice(-2) +
        ("0" + parseInt(rgb[3],10).toString(16)).slice(-2) : '';
}