如何将颜色在RGB格式转换为十六进制格式,反之亦然?

例如,将'#0080C0'转换为(0,128,192)。


当前回答

R = HexToR("#FFFFFF");
G = HexToG("#FFFFFF");
B = HexToB("#FFFFFF");

function HexToR(h) {return parseInt((cutHex(h)).substring(0,2),16)}
function HexToG(h) {return parseInt((cutHex(h)).substring(2,4),16)}
function HexToB(h) {return parseInt((cutHex(h)).substring(4,6),16)}
function cutHex(h) {return (h.charAt(0)=="#") ? h.substring(1,7):h}

使用这些函数来实现没有任何问题的结果。:)

其他回答

哇。这些答案都不能处理分数的边缘情况,等等。当r, g, b为零时,位移版本也不起作用。

这是一个可以处理r g b是小数的版本。它对颜色之间的插值很有用,所以我也包括了这段代码。但它仍然不能处理r, g, b在0-255范围之外的情况

/**
 * Operates with colors.
 * @class Q.Colors
 */
 Q.Color = {
    /**
     * Get a color somewhere between startColor and endColor
     * @method toHex
     * @static
     * @param {String|Number} startColor 
     * @param {String|Number} endColor 
     * @param {String|Number} fraction 
     * @returns {String} a color as a hex string without '#' in front
     */
    toHex: function (r, g, b) {
        return [r, g, b].map(x => {
            const hex = Math.round(x).toString(16)
            return hex.length === 1 ? '0' + hex : hex
          }).join('');
    },
    /**
     * Get a color somewhere between startColor and endColor
     * @method between
     * @static
     * @param {String|Number} startColor 
     * @param {String|Number} endColor 
     * @param {String|Number} fraction 
     * @returns {String} a color as a hex string without '#' in front
     */
    between: function(startColor, endColor, fraction) {
        if (typeof startColor === 'string') {
            startColor = parseInt(startColor.replace('#', '0x'), 16);
        }
        if (typeof endColor === 'string') {
            endColor = parseInt(endColor.replace('#', '0x'), 16);
        }
        var startRed = (startColor >> 16) & 0xFF;
        var startGreen = (startColor >> 8) & 0xFF;
        var startBlue = startColor & 0xFF;
        var endRed = (endColor >> 16) & 0xFF;
        var endGreen = (endColor >> 8) & 0xFF;
        var endBlue = endColor & 0xFF;
        var newRed = startRed + fraction * (endRed - startRed);
        var newGreen = startGreen + fraction * (endGreen - startGreen);
        var newBlue = startBlue + fraction * (endBlue - startBlue);
        return Q.Color.toHex(newRed, newGreen, newBlue);
    },
    /**
     * Sets a new theme-color on the window
     * @method setWindowTheme
     * @static
     * @param {String} color in any CSS format, such as "#aabbcc"
     * @return {String} the previous color
     */
    setWindowTheme: function (color) {
        var meta = document.querySelector('meta[name="theme-color"]');
        var prevColor = null;
        if (meta) {
            prevColor = meta.getAttribute('content');
        }
        if (color) {
            if (!meta) {
                meta = document.createElement('meta');
                meta.setAttribute('name', 'theme-color');
            }
            meta.setAttribute('content', color);
        }
        return prevColor;
    },
    /**
     * Gets the current window theme color
     * @method getWindowTheme
     * @static
     * @param {String} color in any CSS format, such as "#aabbcc"
     * @return {String} the previous color
     */
    getWindowTheme: function () {
        var meta = document.querySelector('meta[name="theme-color"]');
        return meta.getAttribute('content');
    }
}

一个简单的答案,将RGB转换为十六进制。这里颜色通道的值被限定在0到255之间。

function RGBToHex(r = 0, g = 0, b = 0) {
    // clamp and convert to hex
    let hr = Math.max(0, Math.min(255, Math.round(r))).toString(16);
    let hg = Math.max(0, Math.min(255, Math.round(g))).toString(16);
    let hb = Math.max(0, Math.min(255, Math.round(b))).toString(16);
    return "#" +
        (hr.length<2?"0":"") + hr +
        (hg.length<2?"0":"") + hg +
        (hb.length<2?"0":"") + hb;
}

我意识到这个问题有很多答案,但如果你像我一样,你知道你的HEX总是6个字符,带或不带#前缀,那么如果你想做一些快速内联的东西,这可能是最简单的方法。它不关心是否以散列开始。

var hex = "#ffffff";
var rgb = [
    parseInt(hex.substr(-6,2),16),
    parseInt(hex.substr(-4,2),16),
    parseInt(hex.substr(-2),16)
];

从HEX转换为RGB,其中RGB是0到1范围内的浮点值:

#FFAA22→{r: 0.5, g: 0, b:1}

我改编了@Tim Down的回答:


function convertRange(value,oldMin,oldMax,newMin,newMax) {
  return (Math.round(((((value - oldMin) * (newMax - newMin)) / (oldMax - oldMin)) + newMin) * 10000)/10000)
}

function hexToRgbFloat(hex) {
  var result = /^#?([a-f\d]{2})([a-f\d]{2})([a-f\d]{2})$/i.exec(hex);
  return result ? {
    r: convertRange(parseInt(result[1],16), 0, 255, 0, 1),
    g: convertRange(parseInt(result[2],16), 0, 255, 0, 1),
    b: convertRange(parseInt(result[3],16), 0, 255, 0, 1)
  } : null;
}

console.log(hexToRgbFloat("#FFAA22")) // {r: 1, g: 0.6667, b: 0.1333}

注意:rgbToHex的两个版本都期望r, g和b为整数值,所以如果你有非整数值,你需要自己做四舍五入。

下面将做RGB到十六进制的转换,并添加任何所需的零填充:

函数componentToHex(c) { var hex = c.toString(16); 返回十六进制。长度== 1 ?“0”+ hex: hex; } 函数rgbToHex(r, g, b) { 返回“#”+ componentToHex(r) + componentToHex(g) + componentToHex(b); } alert(rgbToHex(0, 51,255));/ / # 0033 ff

另一种转换方式:

函数hexToRgb(hex) { var结果= / ^ # ? (f \ d {2}) (f \ d {2}) (f \ d{2}) /美元i.exec(十六进制); 返回结果?{ r: parseInt(result[1], 16), g: parseInt(result[2], 16), b: parseInt(result[3], 16) }: null; } 警报(hexToRgb (# 0033 ff) .g);/ /“51”;

最后,rgbToHex()的另一个版本,正如@casablanca的回答中所讨论的,并在@cwolves的评论中建议:

函数rgbToHex(r, g, b) { 返回“#”+ (1 < < 24 | r < < 16 g | < < 8 | b) .toString (16) .slice (1); } alert(rgbToHex(0, 51,255));/ / # 0033 ff

2012年12月3日更新

下面是hexToRgb()的一个版本,它也可以解析一个简化的十六进制三元组,例如“#03F”:

function hexToRgb(hex) { // Expand shorthand form (e.g. "03F") to full form (e.g. "0033FF") var shorthandRegex = /^#?([a-f\d])([a-f\d])([a-f\d])$/i; hex = hex.replace(shorthandRegex, function(m, r, g, b) { return r + r + g + g + b + b; }); var result = /^#?([a-f\d]{2})([a-f\d]{2})([a-f\d]{2})$/i.exec(hex); return result ? { r: parseInt(result[1], 16), g: parseInt(result[2], 16), b: parseInt(result[3], 16) } : null; } alert(hexToRgb("#0033ff").g); // "51"; alert(hexToRgb("#03f").g); // "51";