下面是将HEX颜色值分别更改为红色，绿色，蓝色的Javascript代码。

R = hexToR("#FFFFFF");
G = hexToG("#FFFFFF");
B = hexToB("#FFFFFF");

function hexToR(h) {return parseInt((cutHex(h)).substring(0,2),16)}
function hexToG(h) {return parseInt((cutHex(h)).substring(2,4),16)}
function hexToB(h) {return parseInt((cutHex(h)).substring(4,6),16)}
function cutHex(h) {return (h.charAt(0)=="#") ? h.substring(1,7):h}

我正在使用XAML数据，具有十六进制格式的#AARRGGBB (Alpha，红色，绿色，蓝色)。利用上面的答案，以下是我的解决方案:

function hexToRgba(hex) {
    var bigint, r, g, b, a;
    //Remove # character
    var re = /^#?/;
    var aRgb = hex.replace(re, '');
    bigint = parseInt(aRgb, 16);

    //If in #FFF format
    if (aRgb.length == 3) {
        r = (bigint >> 4) & 255;
        g = (bigint >> 2) & 255;
        b = bigint & 255;
        return "rgba(" + r + "," + g + "," + b + ",1)";
    }

    //If in #RRGGBB format
    if (aRgb.length >= 6) {
        r = (bigint >> 16) & 255;
        g = (bigint >> 8) & 255;
        b = bigint & 255;
        var rgb = r + "," + g + "," + b;

        //If in #AARRBBGG format
        if (aRgb.length == 8) {
            a = ((bigint >> 24) & 255) / 255;
            return "rgba(" + rgb + "," + a.toFixed(1) + ")";
        }
    }
    return "rgba(" + rgb + ",1)";
}

http://jsfiddle.net/kvLyscs3/

rgb字符串到十六进制字符串的可读联机程序:

rgb = "rgb(0,128,255)"
hex = '#' + rgb.slice(4,-1).split(',').map(x => (+x).toString(16).padStart(2,0)).join('')

返回这里“#0080ff”。

function getRGB(color){
  if(color.length == 7){
    var r = parseInt(color.substr(1,2),16);
    var g = parseInt(color.substr(3,2),16);
    var b = parseInt(color.substr(5,2),16);    
    return 'rgb('+r+','+g+','+b+')' ;
  }    
  else
    console.log('Enter correct value');
}
var a = getRGB('#f0f0f0');
if(!a){
 a = 'Enter correct value'; 
}

a;

我遇到了这个问题，因为我想要解析任何颜色字符串值，并能够指定不透明度，所以我写了这个使用canvas API的函数。

var toRGBA = function () {
  var canvas = document.createElement('canvas');
  var context = canvas.getContext('2d');

  canvas.width = 1;
  canvas.height = 1;

  return function (color) {
    context.fillStyle = color;
    context.fillRect(0, 0, 1, 1);

    var data = context.getImageData(0, 0, 1, 1).data;

    return {
      r: data[0],
      g: data[1],
      b: data[2],
      a: data[3]
    };
  };
}();

关于context.fillStyle注意:

如果解析值导致失败，则必须忽略该值，属性必须保留其先前的值。

下面是一个你可以用来测试输入的Stack Snippet演示:

var toRGBA = function () { var canvas = document.createElement('canvas'); var context = canvas.getContext('2d'); canvas.width = 1; canvas.height = 1; return function (color) { context.fillStyle = color; context.fillRect(0, 0, 1, 1); var data = context.getImageData(0, 0, 1, 1).data; return { r: data[0], g: data[1], b: data[2], a: data[3] }; }; }(); var inputs = document.getElementsByTagName('input'); function setColor() { inputs[1].value = JSON.stringify(toRGBA(inputs[0].value)); document.body.style.backgroundColor = inputs[0].value; } inputs[0].addEventListener('input', setColor); setColor(); input { width: 200px; margin: 0.5rem; } <input value="cyan" /> <input readonly="readonly" />

我假设您指的是html风格的十六进制符号，即#rrggbb。你的代码几乎是正确的，只是顺序颠倒了。它应该是:

var decColor = red * 65536 + green * 256 + blue;

此外，使用位移位可能会让它更容易阅读:

var decColor = (red << 16) + (green << 8) + blue;