如何将颜色在RGB格式转换为十六进制格式,反之亦然?
例如,将'#0080C0'转换为(0,128,192)。
如何将颜色在RGB格式转换为十六进制格式,反之亦然?
例如,将'#0080C0'转换为(0,128,192)。
当前回答
下面是将HEX颜色值分别更改为红色,绿色,蓝色的Javascript代码。
R = hexToR("#FFFFFF");
G = hexToG("#FFFFFF");
B = hexToB("#FFFFFF");
function hexToR(h) {return parseInt((cutHex(h)).substring(0,2),16)}
function hexToG(h) {return parseInt((cutHex(h)).substring(2,4),16)}
function hexToB(h) {return parseInt((cutHex(h)).substring(4,6),16)}
function cutHex(h) {return (h.charAt(0)=="#") ? h.substring(1,7):h}
其他回答
一个完全不同的方法转换十六进制颜色代码到RGB没有正则表达式
它根据字符串长度处理#FFF和#FFFFFF格式。它从字符串的开头删除#,并将字符串的每个字符分割并将其转换为base10,并将其添加到其位置的相应索引中。
//Algorithm of hex to rgb conversion in ES5 function hex2rgbSimple(str){ str = str.replace('#', ''); return str.split('').reduce(function(result, char, index, array){ var j = parseInt(index * 3/array.length); var number = parseInt(char, 16); result[j] = (array.length == 3? number : result[j]) * 16 + number; return result; },[0,0,0]); } //Same code in ES6 hex2rgb = str => str.replace('#','').split('').reduce((r,c,i,{length: l},j,n)=>(j=parseInt(i*3/l),n=parseInt(c,16),r[j]=(l==3?n:r[j])*16+n,r),[0,0,0]); //hex to RGBA conversion hex2rgba = (str, a) => str.replace('#','').split('').reduce((r,c,i,{length: l},j,n)=>(j=parseInt(i*3/l),n=parseInt(c,16),r[j]=(l==3?n:r[j])*16+n,r),[0,0,0,a||1]); //hex to standard RGB conversion hex2rgbStandard = str => `RGB(${str.replace('#','').split('').reduce((r,c,i,{length: l},j,n)=>(j=parseInt(i*3/l),n=parseInt(c,16),r[j]=(l==3?n:r[j])*16+n,r),[0,0,0]).join(',')})`; console.log(hex2rgb('#aebece')); console.log(hex2rgbSimple('#aebece')); console.log(hex2rgb('#aabbcc')); console.log(hex2rgb('#abc')); console.log(hex2rgba('#abc', 0.7)); console.log(hex2rgbStandard('#abc'));
我正在使用XAML数据,具有十六进制格式的#AARRGGBB (Alpha,红色,绿色,蓝色)。利用上面的答案,以下是我的解决方案:
function hexToRgba(hex) {
var bigint, r, g, b, a;
//Remove # character
var re = /^#?/;
var aRgb = hex.replace(re, '');
bigint = parseInt(aRgb, 16);
//If in #FFF format
if (aRgb.length == 3) {
r = (bigint >> 4) & 255;
g = (bigint >> 2) & 255;
b = bigint & 255;
return "rgba(" + r + "," + g + "," + b + ",1)";
}
//If in #RRGGBB format
if (aRgb.length >= 6) {
r = (bigint >> 16) & 255;
g = (bigint >> 8) & 255;
b = bigint & 255;
var rgb = r + "," + g + "," + b;
//If in #AARRBBGG format
if (aRgb.length == 8) {
a = ((bigint >> 24) & 255) / 255;
return "rgba(" + rgb + "," + a.toFixed(1) + ")";
}
}
return "rgba(" + rgb + ",1)";
}
http://jsfiddle.net/kvLyscs3/
My example =) color: { toHex: function(num){ var str = num.toString(16); return (str.length<6?'#00'+str:'#'+str); }, toNum: function(hex){ return parseInt(hex.replace('#',''), 16); }, rgbToHex: function(color) { color = color.replace(/\s/g,""); var aRGB = color.match(/^rgb\((\d{1,3}[%]?),(\d{1,3}[%]?),(\d{1,3}[%]?)\)$/i); if(aRGB) { color = ''; for (var i=1; i<=3; i++) color += Math.round((aRGB[i][aRGB[i].length-1]=="%"?2.55:1)*parseInt(aRGB[i])).toString(16).replace(/^(.)$/,'0$1'); } else color = color.replace(/^#?([\da-f])([\da-f])([\da-f])$/i, '$1$1$2$2$3$3'); return '#'+color; }
您可以尝试下面这段简单的代码。
用于十六进制到RGB
list($r, $g, $b) = sscanf(#7bde84, "#%02x%02x%02x");
echo $r . "," . $g . "," . $b;
这将返回123,222,132
用于RGB到HEX
$rgb = (123,222,132),
$rgbarr = explode(",",$rgb,3);
echo sprintf("#%02x%02x%02x", $rgbarr[0], $rgbarr[1], $rgbarr[2]);
这将返回#7bde84
上面的一个干净的咖啡脚本版本(谢谢@TimDown):
rgbToHex = (rgb) ->
a = rgb.match /\d+/g
rgb unless a.length is 3
"##{ ((1 << 24) + (parseInt(a[0]) << 16) + (parseInt(a[1]) << 8) + parseInt(a[2])).toString(16).slice(1) }"