如何在Python中声明常量?
在Java中,我们做:
public static final String CONST_NAME = "Name";
如何在Python中声明常量?
在Java中,我们做:
public static final String CONST_NAME = "Name";
当前回答
在我的例子中,我需要不可变字节数组来实现包含许多文字数字的加密库,我想确保这些数字是常量。
这个答案是有效的,但是尝试重赋bytearray元素不会引发错误。
def const(func):
'''implement const decorator'''
def fset(self, val):
'''attempting to set a const raises `ConstError`'''
class ConstError(TypeError):
'''special exception for const reassignment'''
pass
raise ConstError
def fget(self):
'''get a const'''
return func()
return property(fget, fset)
class Consts(object):
'''contain all constants'''
@const
def C1():
'''reassignment to C1 fails silently'''
return bytearray.fromhex('deadbeef')
@const
def pi():
'''is immutable'''
return 3.141592653589793
常量是不可变的,但是常量bytearray赋值默默失败:
>>> c = Consts()
>>> c.pi = 6.283185307179586 # (https://en.wikipedia.org/wiki/Tau_(2%CF%80))
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "consts.py", line 9, in fset
raise ConstError
__main__.ConstError
>>> c.C1[0] = 0
>>> c.C1[0]
222
>>> c.C1
bytearray(b'\xde\xad\xbe\xef')
一种更强大、更简单,甚至可能更“python化”的方法涉及使用memoryview对象(<= python-2.6中的缓冲区对象)。
import sys
PY_VER = sys.version.split()[0].split('.')
if int(PY_VER[0]) == 2:
if int(PY_VER[1]) < 6:
raise NotImplementedError
elif int(PY_VER[1]) == 6:
memoryview = buffer
class ConstArray(object):
'''represent a constant bytearray'''
def __init__(self, init):
'''
create a hidden bytearray and expose a memoryview of that bytearray for
read-only use
'''
if int(PY_VER[1]) == 6:
self.__array = bytearray(init.decode('hex'))
else:
self.__array = bytearray.fromhex(init)
self.array = memoryview(self.__array)
def __str__(self):
return str(self.__array)
def __getitem__(self, *args, **kwargs):
return self.array.__getitem__(*args, **kwargs)
ConstArray项赋值是一个TypeError:
>>> C1 = ConstArray('deadbeef')
>>> C1[0] = 0
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'ConstArray' object does not support item assignment
>>> C1[0]
222
其他回答
扩展Raufio的答案,添加__repr__来返回值。
class const(object):
def __init__(self, val):
super(const, self).__setattr__("value", val)
def __setattr__(self, name, val):
raise ValueError("Trying to change a constant value", self)
def __repr__(self):
return ('{0}'.format(self.value))
dt = const(float(0.01))
print dt
那么对象的行为就更像你所期望的那样,你可以直接访问它而不是使用"。value "
python声明“常量”的方式基本上是一个模块级别的变量:
RED = 1
GREEN = 2
BLUE = 3
然后编写类或函数。因为常量几乎都是整数,而且它们在Python中也是不可变的,所以你几乎没有机会改变它。
当然,除非显式地设置RED = 2。
我们可以创建一个描述符对象。
class Constant:
def __init__(self,value=None):
self.value = value
def __get__(self,instance,owner):
return self.value
def __set__(self,instance,value):
raise ValueError("You can't change a constant")
1)如果我们想在实例级使用常量,那么:
class A:
NULL = Constant()
NUM = Constant(0xFF)
class B:
NAME = Constant('bar')
LISTA = Constant([0,1,'INFINITY'])
>>> obj=A()
>>> print(obj.NUM) #=> 255
>>> obj.NUM =100
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: You can't change a constant
2)如果我们只想在类级别上创建常量,我们可以使用元类作为常量(描述符对象)的容器;所有下降的类将继承我们的常量(我们的描述符对象),没有任何可以修改的风险。
# metaclass of my class Foo
class FooMeta(type): pass
# class Foo
class Foo(metaclass=FooMeta): pass
# I create constants in my metaclass
FooMeta.NUM = Constant(0xff)
FooMeta.NAME = Constant('FOO')
>>> Foo.NUM #=> 255
>>> Foo.NAME #=> 'FOO'
>>> Foo.NUM = 0 #=> ValueError: You can't change a constant
如果我创建一个Foo的子类,这个类将继承常量,而不可能修改它们
class Bar(Foo): pass
>>> Bar.NUM #=> 255
>>> Bar.NUM = 0 #=> ValueError: You can't change a constant
我忍不住要提供我自己的极简元类实现(这可能是前面元类答案的变体)。
常量存储在容器类中(不需要实例化)。值只能设置一次,但设置后不能更改(或删除)。
就我个人而言,我目前还没有这个用例,但这是一个有趣的练习。
class MetaConstant(type):
''' Metaclass that allows underlying class to store constants at class-level (subclass instance not needed).
Non-existent attributes of underlying class (constants) can be set initially, but cannot be changed or deleted.
'''
def __setattr__(klass, attr, value):
'If attribute (constant) doesn\'t exist, set value. If attribute exists, raise AttributeError.'
if hasattr(klass, attr):
raise AttributeError(f'Can\'t change the value of the constant {klass.__name__}.{attr} to {value}'
f' (the value of {klass.__name__}.{attr} is already set to'
f' {getattr(klass, attr)}).')
super().__setattr__(attr, value)
def __delattr__(klass, attr):
if hasattr(klass, attr):
raise AttributeError(f'Can\'t delete constant {klass.__name__}.{attr}'
f' (set to {getattr(klass, attr)}).')
class Constants(metaclass=MetaConstant):
'Container class for constants. No instantiation required.'
#pass # uncomment if no constants set upon class creation
B = 'Six' # sets Constants.B to 'Six'
Constants.B = 6 # AttributeError
del Constants.B # AttributeError
Constants.A = 'Five' # sets Constants.A to 'Five'
Constants.A = 5 # AttributeError
del Constants.A # AttributeError
请随意提出改进建议。
你可以使用Tuple常量变量:
tuple是一个有序且不可更改的集合
my_tuple = (1, "Hello", 3.4)
print(my_tuple[0])