我想澄清一下我的理解是否正确:
==是一个引用比较,即两个对象都指向相同的内存位置 .equals()计算为对象中值的比较
我想澄清一下我的理解是否正确:
==是一个引用比较,即两个对象都指向相同的内存位置 .equals()计算为对象中值的比较
当前回答
例1 -
==和.equals方法只用于引用比较。它表示两个对象是否引用同一个对象。
对象类等于方法实现
public class HelloWorld{
public static void main(String []args){
Object ob1 = new Object();
Object ob2 = ob1;
System.out.println(ob1 == ob2); // true
System.out.println(ob1.equals(ob2)); // true
}
}
例2 -
但是如果我们想要使用equals方法比较对象的内容,那么class必须重写对象的类equals()方法并提供内容比较的实现。这里,String类重写了用于内容比较的equals方法。所有包装器类都覆盖了用于内容比较的equals方法。
字符串类等于方法实现
public class HelloWorld{
public static void main(String []args){
String ob1 = new String("Hi");
String ob2 = new String("Hi");
System.out.println(ob1 == ob2); // false (Both references are referring two different objects)
System.out.println(ob1.equals(ob2)); // true
}
}
例3 -
对于String,还有一个用例。在这里,当我们将任何字符串赋值给string引用时,字符串常量就会在string常量池中创建。如果将相同的字符串赋值给新的字符串引用,则不会创建新的字符串常量,而是引用现有的字符串常量。
public class HelloWorld{
public static void main(String []args){
String ob1 = "Hi";
String ob2 = "Hi";
System.out.println(ob1 == ob2); // true
System.out.println(ob1.equals(ob2)); // true
}
}
注意,每当重写hashCode方法时,通常都需要重写该方法,以便维护hashCode方法的一般契约,该契约规定相等的对象必须具有相等的散列码。
Java API equals()方法契约
其他回答
String池(又名实习池)和Integer池进一步模糊了区别,并允许您在某些情况下对对象使用==而不是.equals
这可以为您提供更好的性能(?),但代价是更大的复杂性。
例如:
assert "ab" == "a" + "b";
Integer i = 1;
Integer j = i;
assert i == j;
复杂性权衡:以下内容可能会让你大吃一惊:
assert new String("a") != new String("a");
Integer i = 128;
Integer j = 128;
assert i != j;
我建议你远离这样的微观优化,总是用.equals表示对象,用==表示原语:
assert (new String("a")).equals(new String("a"));
Integer i = 128;
Integer j = 128;
assert i.equals(j);
==运算符测试两个变量是否有相同的引用 (又名指向内存地址的指针)。
String foo = new String("abc");
String bar = new String("abc");
if(foo==bar)
// False (The objects are not the same)
bar = foo;
if(foo==bar)
// True (Now the objects are the same)
而equals()方法测试两个变量是否引用对象 具有相同的状态(值)。
String foo = new String("abc");
String bar = new String("abc");
if(foo.equals(bar))
// True (The objects are identical but not same)
欢呼:-)
对于String类:
equals()方法比较String实例中的“值”(在堆上),而不考虑两个对象引用是否引用同一个String实例。如果任意两个String类型的对象引用引用同一个String实例,那就太好了!如果两个对象引用引用两个不同的String实例..这没什么区别。它是每个被比较的String实例中的“值”(即:字符数组的内容)。
On the other hand, the "==" operator compares the value of two object references to see whether they refer to the same String instance. If the value of both object references "refer to" the same String instance then the result of the boolean expression would be "true"..duh. If, on the other hand, the value of both object references "refer to" different String instances (even though both String instances have identical "values", that is, the contents of the character arrays of each String instance are the same) the result of the boolean expression would be "false".
就像任何解释一样,让它深入人心。
我希望这能让你清楚一点。
一般来说,你问题的答案是“是的”,但是……
.equals(...) will only compare what it is written to compare, no more, no less. If a class does not override the equals method, then it defaults to the equals(Object o) method of the closest parent class that has overridden this method. If no parent classes have provided an override, then it defaults to the method from the ultimate parent class, Object, and so you're left with the Object#equals(Object o) method. Per the Object API this is the same as ==; that is, it returns true if and only if both variables refer to the same object, if their references are one and the same. Thus you will be testing for object equality and not functional equality. Always remember to override hashCode if you override equals so as not to "break the contract". As per the API, the result returned from the hashCode() method for two objects must be the same if their equals methods show that they are equivalent. The converse is not necessarily true.
要在自定义类中使用equals函数,您必须重写equals函数(以及其他函数)。
equals方法比较对象。
==二进制操作符比较内存地址。