如何使用JUnit来测试某些代码是否抛出异常?

我当然可以这样做:

@Test
public void testFooThrowsIndexOutOfBoundsException() {
  boolean thrown = false;

  try {
    foo.doStuff();
  } catch (IndexOutOfBoundsException e) {
    thrown = true;
  }

  assertTrue(thrown);
}

我记得,对于这类情况,有一个注释或Assert.xyz之类的东西远没有JUnit那么笨拙,更符合JUnit的精神。


当前回答

使用可以与JUnit一起使用的AssertJ断言:

import static org.assertj.core.api.Assertions.*;

@Test
public void testFooThrowsIndexOutOfBoundsException() {
  Foo foo = new Foo();

  assertThatThrownBy(() -> foo.doStuff())
        .isInstanceOf(IndexOutOfBoundsException.class);
}

它比@Test(expected=IndexOutOfBoundsException.class)更好,因为它保证了测试中的预期行抛出了异常,并允许您更容易地检查有关异常的详细信息,例如消息:

assertThatThrownBy(() ->
       {
         throw new Exception("boom!");
       })
    .isInstanceOf(Exception.class)
    .hasMessageContaining("boom");

Maven/Gradle说明。

其他回答

这取决于JUnit版本和使用的断言库。

JUnit5和4.13见答案如果您使用AssertJ或google truth,请参阅答案

JUnit<=4.12的原始答案是:

    @Test(expected = IndexOutOfBoundsException.class)
    public void testIndexOutOfBoundsException() {

        ArrayList emptyList = new ArrayList();
        Object o = emptyList.get(0);

    }

尽管答案对于JUnit<=4.12有更多选项。

参考:

JUnit测试常见问题解答

我们可以在必须返回异常的方法之后使用断言失败:

try{
   methodThatThrowMyException();
   Assert.fail("MyException is not thrown !");
} catch (final Exception exception) {
   // Verify if the thrown exception is instance of MyException, otherwise throws an assert failure
   assertTrue(exception instanceof MyException, "An exception other than MyException is thrown !");
   // In case of verifying the error message
   MyException myException = (MyException) exception;
   assertEquals("EXPECTED ERROR MESSAGE", myException.getMessage());
}

在JUnit 4或更高版本中,您可以如下测试异常

@Rule
public ExpectedException exceptions = ExpectedException.none();

这提供了许多可以用来改进JUnit测试的特性。如果您看到下面的示例,我将测试异常的3个方面。

引发的异常类型异常消息异常的原因

public class MyTest {

    @Rule
    public ExpectedException exceptions = ExpectedException.none();

    ClassUnderTest classUnderTest;

    @Before
    public void setUp() throws Exception {
        classUnderTest = new ClassUnderTest();
    }

    @Test
    public void testAppleisSweetAndRed() throws Exception {

        exceptions.expect(Exception.class);
        exceptions.expectMessage("this is the exception message");
        exceptions.expectCause(Matchers.<Throwable>equalTo(exceptionCause));

        classUnderTest.methodUnderTest("param1", "param2");
    }

}

这样如何:捕获一个非常普通的异常,确保它从catch块中取出,然后断言该异常的类是您期望的。如果a)异常类型错误(例如,如果您使用了空指针),并且b)该异常从未被抛出,则该断言将失败。

public void testFooThrowsIndexOutOfBoundsException() {
  Throwable e = null;

  try {
    foo.doStuff();
  } catch (Throwable ex) {
    e = ex;
  }

  assertTrue(e instanceof IndexOutOfBoundsException);
}

只需制作一个可以关闭和打开的Matcher,如下所示:

public class ExceptionMatcher extends BaseMatcher<Throwable> {
    private boolean active = true;
    private Class<? extends Throwable> throwable;

    public ExceptionMatcher(Class<? extends Throwable> throwable) {
        this.throwable = throwable;
    }

    public void on() {
        this.active = true;
    }

    public void off() {
        this.active = false;
    }

    @Override
    public boolean matches(Object object) {
        return active && throwable.isAssignableFrom(object.getClass());
    }

    @Override
    public void describeTo(Description description) {
        description.appendText("not the covered exception type");
    }
}

要使用它:

add public ExpectedException exception=ExpectedException.none();,那么:

ExceptionMatcher exMatch = new ExceptionMatcher(MyException.class);
exception.expect(exMatch);
someObject.somethingThatThrowsMyException();
exMatch.off();