这段代码工作，并向我发送电子邮件就好:
import smtplib
#SERVER = "localhost"
FROM = 'monty@python.com'
TO = ["jon@mycompany.com"] # must be a list
SUBJECT = "Hello!"
TEXT = "This message was sent with Python's smtplib."
# Prepare actual message
message = """\
From: %s
To: %s
Subject: %s
%s
""" % (FROM, ", ".join(TO), SUBJECT, TEXT)
# Send the mail
server = smtplib.SMTP('myserver')
server.sendmail(FROM, TO, message)
server.quit()
然而，如果我试图将它包装在这样一个函数中:
def sendMail(FROM,TO,SUBJECT,TEXT,SERVER):
import smtplib
"""this is some test documentation in the function"""
message = """\
From: %s
To: %s
Subject: %s
%s
""" % (FROM, ", ".join(TO), SUBJECT, TEXT)
# Send the mail
server = smtplib.SMTP(SERVER)
server.sendmail(FROM, TO, message)
server.quit()
我得到以下错误:
Traceback (most recent call last):
File "C:/Python31/mailtest1.py", line 8, in <module>
sendmail.sendMail(sender,recipients,subject,body,server)
File "C:/Python31\sendmail.py", line 13, in sendMail
server.sendmail(FROM, TO, message)
File "C:\Python31\lib\smtplib.py", line 720, in sendmail
self.rset()
File "C:\Python31\lib\smtplib.py", line 444, in rset
return self.docmd("rset")
File "C:\Python31\lib\smtplib.py", line 368, in docmd
return self.getreply()
File "C:\Python31\lib\smtplib.py", line 345, in getreply
raise SMTPServerDisconnected("Connection unexpectedly closed")
smtplib.SMTPServerDisconnected: Connection unexpectedly closed
有人能告诉我为什么吗?
只是为了补充答案，以便您的邮件传递系统可以扩展。
我建议有一个配置文件(可以是.json， .yml， .ini等)，包含发件人的电子邮件配置，密码和收件人。
通过这种方式，您可以根据需要创建不同的可定制项目。
下面是一个包含3个文件，config, functions和main的小示例。纯文本邮件。
config_email.ini
[email_1]
sender = test@test.com
password = XXXXXXXXXXX
recipients= ["email_2@test.com", "email_2@test.com"]
[email_2]
sender = test_2@test.com
password = XXXXXXXXXXX
recipients= ["email_2@test.com", "email_2@test.com", "email_3@test.com"]
这些项将从main.py调用，它将返回它们各自的值。
函数functions_email.py文件:
import smtplib,configparser,json
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
def get_credentials(item):
parse = configparser.ConfigParser()
parse.read('config_email.ini')
sender = parse[item]['sender ']
password = parse[item]['password']
recipients= json.loads(parse[item]['recipients'])
return sender,password,recipients
def get_msg(sender,recipients,subject,mail_body):
msg = MIMEMultipart()
msg['Subject'] = subject
msg['From'] = sender
msg['To'] = ', '.join(recipients)
text = """\
"""+mail_body+""" """
part1 = MIMEText(text, "plain")
msg.attach(part1)
return msg
def send_email(msg,sender,password,recipients):
s = smtplib.SMTP('smtp.test.com')
s.login(sender,password)
s.sendmail(sender, recipients, msg.as_string())
s.quit()
文件main.py:
from functions_email import *
sender,password,recipients = get_credenciales('email_2')
subject= 'text to subject'
mail_body = 'body....................'
msg = get_msg(sender,recipients ,subject,mail_body)
send_email(msg,sender,password,recipients)
最好的问候!
我想通过建议yagmail包来帮助你发送电子邮件(我是维护者，抱歉广告，但我觉得它真的能帮助!)
你的整个代码将是:
import yagmail
yag = yagmail.SMTP(FROM, 'pass')
yag.send(TO, SUBJECT, TEXT)
注意，我为所有参数提供了默认值，例如，如果你想发送给自己，你可以省略to，如果你不想要一个主题，你也可以省略它。
此外，我们的目标还在于使附加html代码或图像(以及其他文件)变得非常容易。
在你放置内容的地方，你可以这样做:
contents = ['Body text, and here is an embedded image:', 'http://somedomain/image.png',
'You can also find an audio file attached.', '/local/path/song.mp3']
哇，发送附件是多么简单啊!如果没有yagmail，这大概需要20行;)
此外，如果你设置了一次，你就永远不必再输入密码(并安全地保存密码)。在你的情况下，你可以这样做:
import yagmail
yagmail.SMTP().send(contents = contents)
这样更简洁!
我建议你看看github，或者直接用pip install yagmail安装它。
