它可能会在你的信息中添加标签。在你把它传递给sendMail之前打印出消息。

只是为了补充答案，以便您的邮件传递系统可以扩展。

我建议有一个配置文件(可以是.json， .yml， .ini等)，包含发件人的电子邮件配置，密码和收件人。

通过这种方式，您可以根据需要创建不同的可定制项目。

下面是一个包含3个文件，config, functions和main的小示例。纯文本邮件。

config_email.ini

[email_1]
sender = test@test.com
password = XXXXXXXXXXX
recipients= ["email_2@test.com", "email_2@test.com"]

[email_2]
sender = test_2@test.com
password = XXXXXXXXXXX
recipients= ["email_2@test.com", "email_2@test.com", "email_3@test.com"]

这些项将从main.py调用，它将返回它们各自的值。

函数functions_email.py文件:

import smtplib,configparser,json
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText

def get_credentials(item):
    parse = configparser.ConfigParser()
    parse.read('config_email.ini')
    sender = parse[item]['sender ']
    password = parse[item]['password']
    recipients= json.loads(parse[item]['recipients'])
    return sender,password,recipients

def get_msg(sender,recipients,subject,mail_body):
    msg = MIMEMultipart()
    msg['Subject'] = subject
    msg['From'] = sender 
    msg['To'] = ', '.join(recipients)       
    text = """\
    """+mail_body+""" """
    part1 = MIMEText(text, "plain")
    msg.attach(part1)
    return msg

def send_email(msg,sender,password,recipients):
    s = smtplib.SMTP('smtp.test.com')
    s.login(sender,password)
    s.sendmail(sender, recipients, msg.as_string())
    s.quit()    

文件main.py:

from functions_email import *

sender,password,recipients = get_credenciales('email_2')
subject= 'text to subject'
mail_body = 'body....................'
msg = get_msg(sender,recipients ,subject,mail_body)    
send_email(msg,sender,password,recipients)

最好的问候!

我编写了一个简单的函数send_email()，用于使用smtplib和电子邮件包发送电子邮件(链接到我的文章)。它还使用dotenv包来加载发件人的电子邮件和密码(请不要在代码中保密!)我正在使用Gmail电子邮件服务。密码是应用程序密码(这里是谷歌文档如何生成应用程序密码)。

import os
import smtplib
from email.message import EmailMessage
from dotenv import load_dotenv
_ = load_dotenv()


def send_email(to, subject, message):
    try:
        email_address = os.environ.get("EMAIL_ADDRESS")
        email_password = os.environ.get("EMAIL_PASSWORD")

        if email_address is None or email_password is None:
            # no email address or password
            # something is not configured properly
            print("Did you set email address and password correctly?")
            return False

        # create email
        msg = EmailMessage()
        msg['Subject'] = subject
        msg['From'] = email_address
        msg['To'] = to
        msg.set_content(message)

        # send email
        with smtplib.SMTP_SSL('smtp.gmail.com', 465) as smtp:
            smtp.login(email_address, email_password)
            smtp.send_message(msg)
        return True
    except Exception as e:
        print("Problem during send email")
        print(str(e))
    return False

以上方法对于简单的电子邮件发送是可行的。如果您正在寻找更高级的功能，例如HTML内容或附件，当然可以手工编码，但我建议使用现有的包，例如yagmail。

Gmail每天限制500封邮件。对于每天发送许多电子邮件，请考虑事务性电子邮件服务提供商，如Amazon SES, MailGun, MailJet或SendGrid。

import smtplib

s = smtplib.SMTP(your smtp server, smtp port) #SMTP session

message = "Hii!!!"

s.sendmail("sender", "Receiver", message) # sending the mail

s.quit() # terminating the session

我对发送电子邮件的包选项不满意，我决定制作并开源我自己的电子邮件发送器。它易于使用，并支持高级用例。

如何安装:

pip install redmail

用法:

from redmail import EmailSender
email = EmailSender(
    host="<SMTP HOST ADDRESS>",
    port=<PORT NUMBER>,
)

email.send(
    sender="me@example.com",
    receivers=["you@example.com"],
    subject="An example email",
    text="Hi, this is text body.",
    html="<h1>Hi,</h1><p>this is HTML body</p>"
)

如果您的服务器需要用户和密码，只需将user_name和密码传递给EmailSender。

我在send方法中包含了很多特性:

包含附件 将图像直接包含到HTML主体中 金贾的模板 漂亮的HTML表格开箱即用

文档: https://red-mail.readthedocs.io/en/latest/

源代码:https://github.com/Miksus/red-mail

我建议您使用标准包email和smtplib一起发送电子邮件。请看下面的例子(摘自Python文档)。注意，如果遵循这种方法，“简单”任务确实很简单，而更复杂的任务(如附加二进制对象或发送纯/HTML多部分消息)将很快完成。

# Import smtplib for the actual sending function
import smtplib

# Import the email modules we'll need
from email.mime.text import MIMEText

# Open a plain text file for reading.  For this example, assume that
# the text file contains only ASCII characters.
with open(textfile, 'rb') as fp:
    # Create a text/plain message
    msg = MIMEText(fp.read())

# me == the sender's email address
# you == the recipient's email address
msg['Subject'] = 'The contents of %s' % textfile
msg['From'] = me
msg['To'] = you

# Send the message via our own SMTP server, but don't include the
# envelope header.
s = smtplib.SMTP('localhost')
s.sendmail(me, [you], msg.as_string())
s.quit()

要将电子邮件发送到多个目的地，您还可以遵循Python文档中的示例:

# Import smtplib for the actual sending function
import smtplib

# Here are the email package modules we'll need
from email.mime.image import MIMEImage
from email.mime.multipart import MIMEMultipart

# Create the container (outer) email message.
msg = MIMEMultipart()
msg['Subject'] = 'Our family reunion'
# me == the sender's email address
# family = the list of all recipients' email addresses
msg['From'] = me
msg['To'] = ', '.join(family)
msg.preamble = 'Our family reunion'

# Assume we know that the image files are all in PNG format
for file in pngfiles:
    # Open the files in binary mode.  Let the MIMEImage class automatically
    # guess the specific image type.
    with open(file, 'rb') as fp:
        img = MIMEImage(fp.read())
    msg.attach(img)

# Send the email via our own SMTP server.
s = smtplib.SMTP('localhost')
s.sendmail(me, family, msg.as_string())
s.quit()

如您所见，MIMEText对象中的报头To必须是由逗号分隔的电子邮件地址组成的字符串。另一方面，sendmail函数的第二个参数必须是一个字符串列表(每个字符串都是一个电子邮件地址)。

所以，如果你有三个电子邮件地址:person1@example.com, person2@example.com和person3@example.com，你可以这样做(明显的部分省略了):

to = ["person1@example.com", "person2@example.com", "person3@example.com"]
msg['To'] = ",".join(to)
s.sendmail(me, to, msg.as_string())

"，".join(to)部分从列表中生成一个单独的字符串，用逗号分隔。

从你的问题中，我猜你还没有读过Python教程——如果你想在Python中有所了解，这是必须的——标准库的文档大部分都很出色。