在Jest测试中,我一直得到“localStorage is not defined”,这是有意义的,但我的选项是什么?碰壁。


当前回答

如果使用create-react-app,文档中解释了一个更简单和直接的解决方案。

创建src/setupTests.js,并把这个放在里面:

const localStorageMock = {
  getItem: jest.fn(),
  setItem: jest.fn(),
  clear: jest.fn()
};
global.localStorage = localStorageMock;

Tom Mertz的评论如下:

然后,您可以通过执行以下操作来测试localStorageMock的函数是否被使用

expect(localStorage.getItem).toBeCalledWith('token')
// or
expect(localStorage.getItem.mock.calls.length).toBe(1)

在你的测试中,如果你想确保它被调用。查看https://facebook.github.io/jest/docs/en/mock-functions.html

其他回答

一个更好的替代方法,它处理未定义的值(它不需要toString()),如果值不存在则返回null。用react v15、redux和redux-auth-wrapper进行了测试

class LocalStorageMock {
  constructor() {
    this.store = {}
  }

  clear() {
    this.store = {}
  }

  getItem(key) {
    return this.store[key] || null
  }

  setItem(key, value) {
    this.store[key] = value
  }

  removeItem(key) {
    delete this.store[key]
  }
}

global.localStorage = new LocalStorageMock

2021年,打印稿

class LocalStorageMock {
  store: { [k: string]: string };
  length: number;

  constructor() {
    this.store = {};
    this.length = 0;
  }

  /**
   * @see https://developer.mozilla.org/en-US/docs/Web/API/Storage/key
   * @returns
   */
  key = (idx: number): string => {
    const values = Object.values(this.store);
    return values[idx];
  };

  clear() {
    this.store = {};
  }

  getItem(key: string) {
    return this.store[key] || null;
  }

  setItem(key: string, value: string) {
    this.store[key] = String(value);
  }

  removeItem(key: string) {
    delete this.store[key];
  }
}

export default LocalStorageMock;

然后你可以用它

global.localStorage = new LocalStorageMock();

我从github找到了这个解决方案

var localStorageMock = (function() {
  var store = {};

  return {
    getItem: function(key) {
        return store[key] || null;
    },
    setItem: function(key, value) {
        store[key] = value.toString();
    },
    clear: function() {
        store = {};
    }
  }; 
})();

Object.defineProperty(window, 'localStorage', {
 value: localStorageMock
});

您可以在setupTests中插入这段代码,它应该可以正常工作。

我在一个使用typesctipt的项目中测试了它。

如果使用create-react-app,文档中解释了一个更简单和直接的解决方案。

创建src/setupTests.js,并把这个放在里面:

const localStorageMock = {
  getItem: jest.fn(),
  setItem: jest.fn(),
  clear: jest.fn()
};
global.localStorage = localStorageMock;

Tom Mertz的评论如下:

然后,您可以通过执行以下操作来测试localStorageMock的函数是否被使用

expect(localStorage.getItem).toBeCalledWith('token')
// or
expect(localStorage.getItem.mock.calls.length).toBe(1)

在你的测试中,如果你想确保它被调用。查看https://facebook.github.io/jest/docs/en/mock-functions.html

一个使用TypeScript和Jest的更优雅的解决方案。

    interface Spies {
      [key: string]: jest.SpyInstance
    }
    
    describe('→ Local storage', () => {
    
      const spies: Spies = {}
    
      beforeEach(() => {
        ['setItem', 'getItem', 'clear'].forEach((fn: string) => {
          const mock = jest.fn(localStorage[fn])
          spies[fn] = jest.spyOn(Storage.prototype, fn).mockImplementation(mock)
        })
      })
    
      afterEach(() => {
        Object.keys(spies).forEach((key: string) => spies[key].mockRestore())
      })
    
      test('→ setItem ...', async () => {
          localStorage.setItem( 'foo', 'bar' )
          expect(localStorage.getItem('foo')).toEqual('bar')
          expect(spies.setItem).toHaveBeenCalledTimes(1)
      })
    })