在Jest测试中,我一直得到“localStorage is not defined”,这是有意义的,但我的选项是什么?碰壁。


当前回答

或者你只是像这样使用一个模拟包:

https://www.npmjs.com/package/jest-localstorage-mock

它不仅处理存储功能,还允许您测试是否实际调用了存储。

其他回答

在这里引用了一些其他的答案来解决一个用Typescript的项目。我像这样创建了一个LocalStorageMock:

export class LocalStorageMock {

    private store = {}

    clear() {
        this.store = {}
    }

    getItem(key: string) {
        return this.store[key] || null
    }

    setItem(key: string, value: string) {
        this.store[key] = value
    }

    removeItem(key: string) {
        delete this.store[key]
    }
}

然后我创建了一个LocalStorageWrapper类,我使用它来访问应用程序中的所有本地存储,而不是直接访问全局本地存储变量。便于在包装器中为测试设置模拟。

首先,我创建了一个名为localStorage.ts(localStorage.js)的文件

class LocalStorageMock {
  store: Store;
  length: number;

  constructor() {
    this.store = {};
    this.length = 0;
  }

  key(n: number): any {
    if (typeof n === 'undefined') {
      throw new Error(
        "Uncaught TypeError: Failed to execute 'key' on 'Storage': 1 argument required, but only 0 present."
      );
    }

    if (n >= Object.keys(this.store).length) {
      return null;
    }

    return Object.keys(this.store)[n];
  }

  getItem(key: string): Store | null {
    if (!Object.keys(this.store).includes(key)) {
      return null;
    }

    return this.store[key];
  }

  setItem(key: string, value: any): undefined {
    if (typeof key === 'undefined' && typeof value === 'undefined') {
      throw new Error(
        "Uncaught TypeError: Failed to execute 'setItem' on 'Storage': 2 arguments required, but only 0 present."
      );
    }

    if (typeof value === 'undefined') {
      throw new Error(
        "Uncaught TypeError: Failed to execute 'setItem' on 'Storage': 2 arguments required, but only 1 present."
      );
    }

    if (!key) return undefined;

    this.store[key] = value.toString() || '';
    this.length = Object.keys(this.store).length;

    return undefined;
  }

  removeItem(key: string): undefined {
    if (typeof key === 'undefined') {
      throw new Error(
        "Uncaught TypeError: Failed to execute 'removeItem' on 'Storage': 1 argument required, but only 0 present."
      );
    }

    delete this.store[key];
    this.length = Object.keys(this.store).length;
    return undefined;
  }

  clear(): undefined {
    this.store = {};
    this.length = 0;

    return undefined;
  }
}

export const getLocalStorageMock = (): any => {
  return new LocalStorageMock();
};

global.localStorage = new LocalStorageMock();

然后创建名为session.test.ts的测试文件(session.test.js)

import { getLocalStorageMock } from '../localstorage';
describe('session storage', () => {
  let localStorage;
  beforeEach(() => {
    localStorage = getLocalStorageMock();
  });

  describe('getItem', () => {
    it('should return null if the item is undefined', () => {
      expect(localStorage.getItem('item')).toBeNull();
    });
    it("should return '' instead of null", () => {
      localStorage.setItem('item', '');
      expect(localStorage.getItem('item')).toBe('');
    });
    it('should return navid', () => {
      localStorage.setItem('item', 'navid');
      expect(localStorage.getItem('item')).toBe('navid');
    });

  });
});

如果你正在寻找一个mock而不是存根,这是我使用的解决方案:

export const localStorageMock = {
   getItem: jest.fn().mockImplementation(key => localStorageItems[key]),
   setItem: jest.fn().mockImplementation((key, value) => {
       localStorageItems[key] = value;
   }),
   clear: jest.fn().mockImplementation(() => {
       localStorageItems = {};
   }),
   removeItem: jest.fn().mockImplementation((key) => {
       localStorageItems[key] = undefined;
   }),
};

export let localStorageItems = {}; // eslint-disable-line import/no-mutable-exports

为了便于初始化,我导出了存储项。例如,我可以很容易地将它设置为一个对象

在Jest + JSDom的新版本中,不可能设置这个,但是本地存储已经可用,你可以像这样监视它:

const setItemSpy = jest.spyOn(Object.getPrototypeOf(window.localStorage), 'setItem');

答:

目前(7月22日)localStorage不能像你通常会被嘲笑或监视,并在创建-反应-应用程序文档中概述。这是由于jsdom中所做的更改。你可以在jest和jsdom问题跟踪器中读到它。

作为一种变通方法,你可以监视原型:

// does not work:
jest.spyOn(localStorage, "setItem");
localStorage.setItem = jest.fn();

// either of these lines will work, different syntax that does the same thing:
jest.spyOn(Storage.prototype, 'setItem');
Storage.prototype.setItem = jest.fn();

// assertions as usual:
expect(localStorage.setItem).toHaveBeenCalled();

关于监视原型机的注意事项:

监视实例使您能够观察和模拟特定对象的行为。

另一方面,监视原型,将同时观察/操作该类的每个实例。除非您有一个特殊的用例,否则这可能不是您想要的。

但是,在本例中没有区别,因为localStorage只存在一个实例。

我从github找到了这个解决方案

var localStorageMock = (function() {
  var store = {};

  return {
    getItem: function(key) {
        return store[key] || null;
    },
    setItem: function(key, value) {
        store[key] = value.toString();
    },
    clear: function() {
        store = {};
    }
  }; 
})();

Object.defineProperty(window, 'localStorage', {
 value: localStorageMock
});

您可以在setupTests中插入这段代码,它应该可以正常工作。

我在一个使用typesctipt的项目中测试了它。