如何修复此代码中的弃用警告?或者,还有其他的选择吗?
Handler().postDelayed({
context?.let {
//code
}
}, 3000)
如何修复此代码中的弃用警告?或者,还有其他的选择吗?
Handler().postDelayed({
context?.let {
//code
}
}, 3000)
当前回答
使用Executor而不是handler获取更多信息。 使用ScheduledExecutorService实现post delay:
ScheduledExecutorService worker = Executors.newSingleThreadScheduledExecutor();
Runnable runnable = () -> {
public void run() {
// Do something
}
};
worker.schedule(runnable, 2000, TimeUnit.MILLISECONDS);
其他回答
考虑使用协程
scope.launch {
delay(3000L)
// do stuff
}
根据文档(https://developer.android.com/reference/android/os/Handler#Handler()):
Implicitly choosing a Looper during Handler construction can lead to bugs where operations are silently lost (if the Handler is not expecting new tasks and quits), crashes (if a handler is sometimes created on a thread without a Looper active), or race conditions, where the thread a handler is associated with is not what the author anticipated. Instead, use an Executor or specify the Looper explicitly, using Looper#getMainLooper, {link android.view.View#getHandler}, or similar. If the implicit thread local behavior is required for compatibility, use new Handler(Looper.myLooper()) to make it clear to readers.
我们应该停止使用没有Looper的构造函数,而是指定一个Looper。
对于Xamarin Android,而不是
Handler handler;
handler = new Handler();
只写
Handler handler;
handler = new Handler(Looper.MyLooper());
其余的代码都很好。
如果你使用变量作为处理程序和可运行的,然后像这样使用它。
private Handler handler;
private Runnable runnable;
handler = new Handler(Looper.getMainLooper());
handler.postDelayed(runnable = () -> {
// Do delayed stuff here
handler.postDelayed(runnable, 1000);
}, delay);
你还需要删除onDestroy()中的回调
@Override
public void onDestroy() {
super.onDestroy();
if (handler != null) {
handler.removeCallbacks(runnable);
}
}
在Handler构造函数中提供一个循环器
Handler(Looper.getMainLooper())