如果您有java.io.InputStream对象,应该如何处理该对象并生成String?
假设我有一个包含文本数据的InputStream,我想将其转换为String,例如,我可以将其写入日志文件。
获取InputStream并将其转换为字符串的最简单方法是什么?
public String convertStreamToString(InputStream is) {
// ???
}
如果您有java.io.InputStream对象,应该如何处理该对象并生成String?
假设我有一个包含文本数据的InputStream,我想将其转换为String,例如,我可以将其写入日志文件。
获取InputStream并将其转换为字符串的最简单方法是什么?
public String convertStreamToString(InputStream is) {
// ???
}
当前回答
这个问题的解决方案不是最简单的,但由于没有提到NIO流和通道,这里有一个使用NIO通道和ByteBuffer将流转换为字符串的版本。
public static String streamToStringChannel(InputStream in, String encoding, int bufSize) throws IOException {
ReadableByteChannel channel = Channels.newChannel(in);
ByteBuffer byteBuffer = ByteBuffer.allocate(bufSize);
ByteArrayOutputStream bout = new ByteArrayOutputStream();
WritableByteChannel outChannel = Channels.newChannel(bout);
while (channel.read(byteBuffer) > 0 || byteBuffer.position() > 0) {
byteBuffer.flip(); //make buffer ready for write
outChannel.write(byteBuffer);
byteBuffer.compact(); //make buffer ready for reading
}
channel.close();
outChannel.close();
return bout.toString(encoding);
}
下面是如何使用它的示例:
try (InputStream in = new FileInputStream("/tmp/large_file.xml")) {
String x = streamToStringChannel(in, "UTF-8", 1);
System.out.println(x);
}
对于大型文件,此方法的性能应该很好。
其他回答
此代码适用于新的Java学习者:
private String textDataFromFile;
public String getFromFile(InputStream myInputStream) throws FileNotFoundException, IOException {
BufferedReader bufferReader = new BufferedReader(new InputStreamReader(myInputStream));
StringBuilder stringBuilder = new StringBuilder();
String eachStringLine;
while ((eachStringLine = bufferReader.readLine()) != null) {
stringBuilder.append(eachStringLine).append("\n");
}
textDataFromFile = stringBuilder.toString();
return textDataFromFile;
}
嗯,你可以自己编程。。。这并不复杂。。。
String Inputstream2String (InputStream is) throws IOException
{
final int PKG_SIZE = 1024;
byte[] data = new byte [PKG_SIZE];
StringBuilder buffer = new StringBuilder(PKG_SIZE * 10);
int size;
size = is.read(data, 0, data.length);
while (size > 0)
{
String str = new String(data, 0, size);
buffer.append(str);
size = is.read(data, 0, data.length);
}
return buffer.toString();
}
使用java 9中支持的java.io.InputStream.transferTo(OutputStream)和ByteArrayOutputStream.toString(String),该字符串采用字符集名称:
public static String gobble(InputStream in, String charsetName) throws IOException {
ByteArrayOutputStream bos = new ByteArrayOutputStream();
in.transferTo(bos);
return bos.toString(charsetName);
}
考虑到文件,首先应该获得java.io.Reader实例。然后可以将其读取并添加到StringBuilder中(如果我们不在多个线程中访问StringBuffer,我们就不需要StringBuffer了,StringBuilder速度更快)。这里的技巧是我们在块中工作,因此不需要其他缓冲流。块大小被参数化以用于运行时性能优化。
public static String slurp(final InputStream is, final int bufferSize) {
final char[] buffer = new char[bufferSize];
final StringBuilder out = new StringBuilder();
try (Reader in = new InputStreamReader(is, "UTF-8")) {
for (;;) {
int rsz = in.read(buffer, 0, buffer.length);
if (rsz < 0)
break;
out.append(buffer, 0, rsz);
}
}
catch (UnsupportedEncodingException ex) {
/* ... */
}
catch (IOException ex) {
/* ... */
}
return out.toString();
}
注意:这可能不是个好主意。此方法使用递归,因此将非常快地命中StackOverflowError:
public String read (InputStream is) {
byte next = is.read();
return next == -1 ? "" : next + read(is); // Recursive part: reads next byte recursively
}