这是我的基于Java 8的解决方案，它使用新的流API来收集InputStream中的所有行：

public static String toString(InputStream inputStream) {
    BufferedReader reader = new BufferedReader(
        new InputStreamReader(inputStream));
    return reader.lines().collect(Collectors.joining(
        System.getProperty("line.separator")));
}

Kotlin用户只需：

println(InputStreamReader(is).readText())

鉴于

readText()

是Kotlin标准库的内置扩展方法。

此代码适用于新的Java学习者：

private String textDataFromFile;

public String getFromFile(InputStream myInputStream) throws FileNotFoundException, IOException {

    BufferedReader bufferReader = new BufferedReader(new InputStreamReader(myInputStream));

    StringBuilder stringBuilder = new StringBuilder();

    String eachStringLine;

    while ((eachStringLine = bufferReader.readLine()) != null) {
        stringBuilder.append(eachStringLine).append("\n");
    }
    textDataFromFile = stringBuilder.toString();

    return textDataFromFile;
}

JDK中最简单的方法是使用以下代码片段。

String convertToString(InputStream in){
    String resource = new Scanner(in).useDelimiter("\\Z").next();
    return resource;
}

public String read(InputStream in) throws IOException {
    try (BufferedReader buffer = new BufferedReader(new InputStreamReader(in))) {
        return buffer.lines().collect(Collectors.joining("\n"));
    }
}

此外，您还可以从指定的资源路径获取InputStream：

public static InputStream getResourceAsStream(String path)
{
    InputStream myiInputStream = ClassName.class.getResourceAsStream(path);
    if (null == myiInputStream)
    {
        mylogger.info("Can't find path = ", path);
    }

    return myiInputStream;
}

要从特定路径获取InputStream，请执行以下操作：

public static URL getResource(String path)
{
    URL myURL = ClassName.class.getResource(path);
    if (null == myURL)
    {
        mylogger.info("Can't find resource path = ", path);
    }
    return myURL;
}