如果您有java.io.InputStream对象,应该如何处理该对象并生成String?


假设我有一个包含文本数据的InputStream,我想将其转换为String,例如,我可以将其写入日志文件。

获取InputStream并将其转换为字符串的最简单方法是什么?

public String convertStreamToString(InputStream is) {
// ???
}

当前回答

你可以使用仙人掌:

String text = new TextOf(inputStream).asString();

UTF-8编码是默认编码。如果您需要另一个:

String text = new TextOf(inputStream, "UTF-16").asString();

其他回答

我已经创建了这段代码,并且它有效。没有所需的外部插件。

有一个字符串到流和流到字符串的转换器:

import java.io.ByteArrayInputStream;
import java.io.InputStream;

public class STRINGTOSTREAM {

    public static void main(String[] args)
    {
        String text = "Hello Bhola..!\nMy Name Is Kishan ";

        InputStream strm = new ByteArrayInputStream(text.getBytes());    // Convert String to Stream

        String data = streamTostring(strm);

        System.out.println(data);
    }

    static String streamTostring(InputStream stream)
    {
        String data = "";

        try
        {
            StringBuilder stringbuld = new StringBuilder();
            int i;
            while ((i=stream.read())!=-1)
            {
                stringbuld.append((char)i);
            }
            data = stringbuld.toString();
        }
        catch(Exception e)
        {
            data = "No data Streamed.";
        }
        return data;
    }

与Okio一起:

String result = Okio.buffer(Okio.source(inputStream)).readUtf8();

此外,您还可以从指定的资源路径获取InputStream:

public static InputStream getResourceAsStream(String path)
{
    InputStream myiInputStream = ClassName.class.getResourceAsStream(path);
    if (null == myiInputStream)
    {
        mylogger.info("Can't find path = ", path);
    }

    return myiInputStream;
}

要从特定路径获取InputStream,请执行以下操作:

public static URL getResource(String path)
{
    URL myURL = ClassName.class.getResource(path);
    if (null == myURL)
    {
        mylogger.info("Can't find resource path = ", path);
    }
    return myURL;
}

如果使用流读取器,请确保在结束时关闭流

private String readStream(InputStream iStream) throws IOException {
    //build a Stream Reader, it can read char by char
    InputStreamReader iStreamReader = new InputStreamReader(iStream);
    //build a buffered Reader, so that i can read whole line at once
    BufferedReader bReader = new BufferedReader(iStreamReader);
    String line = null;
    StringBuilder builder = new StringBuilder();
    while((line = bReader.readLine()) != null) {  //Read till end
        builder.append(line);
        builder.append("\n"); // append new line to preserve lines
    }
    bReader.close();         //close all opened stuff
    iStreamReader.close();
    //iStream.close(); //EDIT: Let the creator of the stream close it!
                       // some readers may auto close the inner stream
    return builder.toString();
}

编辑:在JDK7+上,可以使用trywithresources构造。

/**
 * Reads the stream into a string
 * @param iStream the input stream
 * @return the string read from the stream
 * @throws IOException when an IO error occurs
 */
private String readStream(InputStream iStream) throws IOException {

    //Buffered reader allows us to read line by line
    try (BufferedReader bReader =
                 new BufferedReader(new InputStreamReader(iStream))){
        StringBuilder builder = new StringBuilder();
        String line;
        while((line = bReader.readLine()) != null) {  //Read till end
            builder.append(line);
            builder.append("\n"); // append new line to preserve lines
        }
        return builder.toString();
    }
}

我有log4j可用,所以我可以使用org.apache.log4j.lf5.util.StreamUtils.getBytes来获取字节,我可以使用Stringctor将其转换为字符串

String result = new String(StreamUtils.getBytes(inputStream));