如果您有java.io.InputStream对象,应该如何处理该对象并生成String?
假设我有一个包含文本数据的InputStream,我想将其转换为String,例如,我可以将其写入日志文件。
获取InputStream并将其转换为字符串的最简单方法是什么?
public String convertStreamToString(InputStream is) {
// ???
}
如果您有java.io.InputStream对象,应该如何处理该对象并生成String?
假设我有一个包含文本数据的InputStream,我想将其转换为String,例如,我可以将其写入日志文件。
获取InputStream并将其转换为字符串的最简单方法是什么?
public String convertStreamToString(InputStream is) {
// ???
}
当前回答
就reduce和concat而言,它可以在Java 8中表示为:
String fromFile = new BufferedReader(new
InputStreamReader(inputStream)).lines().reduce(String::concat).get();
其他回答
这是一个改编自org.apache.commons.io.IOUtils源代码的答案,适用于那些想要apache实现但不想要整个库的人。
private static final int BUFFER_SIZE = 4 * 1024;
public static String inputStreamToString(InputStream inputStream, String charsetName)
throws IOException {
StringBuilder builder = new StringBuilder();
InputStreamReader reader = new InputStreamReader(inputStream, charsetName);
char[] buffer = new char[BUFFER_SIZE];
int length;
while ((length = reader.read(buffer)) != -1) {
builder.append(buffer, 0, length);
}
return builder.toString();
}
如果使用流读取器,请确保在结束时关闭流
private String readStream(InputStream iStream) throws IOException {
//build a Stream Reader, it can read char by char
InputStreamReader iStreamReader = new InputStreamReader(iStream);
//build a buffered Reader, so that i can read whole line at once
BufferedReader bReader = new BufferedReader(iStreamReader);
String line = null;
StringBuilder builder = new StringBuilder();
while((line = bReader.readLine()) != null) { //Read till end
builder.append(line);
builder.append("\n"); // append new line to preserve lines
}
bReader.close(); //close all opened stuff
iStreamReader.close();
//iStream.close(); //EDIT: Let the creator of the stream close it!
// some readers may auto close the inner stream
return builder.toString();
}
编辑:在JDK7+上,可以使用trywithresources构造。
/**
* Reads the stream into a string
* @param iStream the input stream
* @return the string read from the stream
* @throws IOException when an IO error occurs
*/
private String readStream(InputStream iStream) throws IOException {
//Buffered reader allows us to read line by line
try (BufferedReader bReader =
new BufferedReader(new InputStreamReader(iStream))){
StringBuilder builder = new StringBuilder();
String line;
while((line = bReader.readLine()) != null) { //Read till end
builder.append(line);
builder.append("\n"); // append new line to preserve lines
}
return builder.toString();
}
}
当输入流来自类路径资源(这似乎是一项流行任务)时,Guava提供了更短的高效自动关闭解决方案:
byte[] bytes = Resources.toByteArray(classLoader.getResource(path));
or
String text = Resources.toString(classLoader.getResource(path), StandardCharsets.UTF_8);
还有ByteSource和CharSource的一般概念,它们温和地负责打开和关闭流。
因此,例如,不要显式打开一个小文件来读取其内容:
String content = Files.asCharSource(new File("robots.txt"), StandardCharsets.UTF_8).read();
byte[] data = Files.asByteSource(new File("favicon.ico")).read();
或者只是
String content = Files.toString(new File("robots.txt"), StandardCharsets.UTF_8);
byte[] data = Files.toByteArray(new File("favicon.ico"));
使用java 9中支持的java.io.InputStream.transferTo(OutputStream)和ByteArrayOutputStream.toString(String),该字符串采用字符集名称:
public static String gobble(InputStream in, String charsetName) throws IOException {
ByteArrayOutputStream bos = new ByteArrayOutputStream();
in.transferTo(bos);
return bos.toString(charsetName);
}
以下是我经过一些实验后提出的最优雅、纯Java(无库)解决方案:
public static String fromStream(InputStream in) throws IOException
{
BufferedReader reader = new BufferedReader(new InputStreamReader(in));
StringBuilder out = new StringBuilder();
String newLine = System.getProperty("line.separator");
String line;
while ((line = reader.readLine()) != null) {
out.append(line);
out.append(newLine);
}
return out.toString();
}