@denver_citizen和@Peter Szanto的回答对我不太适用，但我修改了它们，以解释:

组合键 “删除”和“更新”动作 重新添加时检查索引 dbo以外的模式 同时处理多个表

DECLARE @Debug bit = 0;

-- List of tables to truncate
select
    SchemaName, Name
into #tables
from (values 
    ('schema', 'table')
    ,('schema2', 'table2')
) as X(SchemaName, Name)


BEGIN TRANSACTION TruncateTrans;

with foreignKeys AS (
     SELECT 
        SCHEMA_NAME(fk.schema_id) as SchemaName
        ,fk.Name as ConstraintName
        ,OBJECT_NAME(fk.parent_object_id) as TableName
        ,SCHEMA_NAME(t.SCHEMA_ID) as ReferencedSchemaName
        ,OBJECT_NAME(fk.referenced_object_id) as ReferencedTableName
        ,fc.constraint_column_id
        ,COL_NAME(fk.parent_object_id, fc.parent_column_id) AS ColumnName
        ,COL_NAME(fk.referenced_object_id, fc.referenced_column_id) as ReferencedColumnName
        ,fk.delete_referential_action_desc
        ,fk.update_referential_action_desc
    FROM sys.foreign_keys AS fk
        JOIN sys.foreign_key_columns AS fc
            ON fk.object_id = fc.constraint_object_id
        JOIN #tables tbl 
            ON OBJECT_NAME(fc.referenced_object_id) = tbl.Name
        JOIN sys.tables t on OBJECT_NAME(t.object_id) = tbl.Name 
            and SCHEMA_NAME(t.schema_id) = tbl.SchemaName
            and t.OBJECT_ID = fc.referenced_object_id
)



select
    quotename(fk.ConstraintName) AS ConstraintName
    ,quotename(fk.SchemaName) + '.' + quotename(fk.TableName) AS TableName
    ,quotename(fk.ReferencedSchemaName) + '.' + quotename(fk.ReferencedTableName) AS ReferencedTableName
    ,replace(fk.delete_referential_action_desc, '_', ' ') AS DeleteAction
    ,replace(fk.update_referential_action_desc, '_', ' ') AS UpdateAction
    ,STUFF((
        SELECT ',' + quotename(fk2.ColumnName)
        FROM foreignKeys fk2 
        WHERE fk2.ConstraintName = fk.ConstraintName and fk2.SchemaName = fk.SchemaName
        ORDER BY fk2.constraint_column_id
        FOR XML PATH('')
    ),1,1,'') AS ColumnNames
    ,STUFF((
        SELECT ',' + quotename(fk2.ReferencedColumnName)
        FROM foreignKeys fk2 
        WHERE fk2.ConstraintName = fk.ConstraintName and fk2.SchemaName = fk.SchemaName
        ORDER BY fk2.constraint_column_id
        FOR XML PATH('')
    ),1,1,'') AS ReferencedColumnNames
into #FKs
from foreignKeys fk
GROUP BY fk.SchemaName, fk.ConstraintName, fk.TableName, fk.ReferencedSchemaName, fk.ReferencedTableName, fk.delete_referential_action_desc, fk.update_referential_action_desc



-- Drop FKs
select 
    identity(int,1,1) as ID,
    'ALTER TABLE ' + fk.TableName + ' DROP CONSTRAINT ' + fk.ConstraintName AS script
into #scripts
from #FKs fk

-- Truncate 
insert into #scripts
select distinct 
    'TRUNCATE TABLE ' + quotename(tbl.SchemaName) + '.' + quotename(tbl.Name) AS script
from #tables tbl

-- Recreate
insert into #scripts
select 
    'ALTER TABLE ' + fk.TableName + 
    ' WITH CHECK ADD CONSTRAINT ' + fk.ConstraintName + 
    ' FOREIGN KEY ('+ fk.ColumnNames +')' + 
    ' REFERENCES ' + fk.ReferencedTableName +' ('+ fk.ReferencedColumnNames +')' +
    ' ON DELETE ' + fk.DeleteAction COLLATE Latin1_General_CI_AS_KS_WS + ' ON UPDATE ' + fk.UpdateAction COLLATE Latin1_General_CI_AS_KS_WS AS script
from #FKs fk


DECLARE @script nvarchar(MAX);

DECLARE curScripts CURSOR FOR 
    select script
    from #scripts
    order by ID

OPEN curScripts

WHILE 1=1 BEGIN
    FETCH NEXT FROM curScripts INTO @script
    IF @@FETCH_STATUS != 0 BREAK;

    print @script;
    IF @Debug = 0
        EXEC (@script);
END
CLOSE curScripts
DEALLOCATE curScripts


drop table #scripts
drop table #FKs
drop table #tables


COMMIT TRANSACTION TruncateTrans;

SET FOREIGN_KEY_CHECKS=0;
TRUNCATE table1;
TRUNCATE table2;
SET FOREIGN_KEY_CHECKS=1;

引用-截断外键约束表

在MYSQL为我工作

正确的;你不能截断一个有FK约束的表。

通常我的处理方法是:

去掉约束 截断表格 重新创建约束。

(当然，这一切都在一笔交易中。)

当然，这只适用于子节点已经被截断的情况。否则，我会走不同的路线，完全取决于我的数据是什么样子的。(变量太多，不便在此赘述。)

最初的海报决定了为什么会这样;更多细节请看这个答案。

如果您以任何频率执行此操作，甚至在时间表上，我绝对不会明确地使用DML语句。写入事务日志的成本非常高，将整个数据库设置为SIMPLE恢复模式以截断一个表是荒谬的。

最好的办法，不幸是艰苦或费力的办法。这是:

减少约束 截断表 重新创建约束

我这样做的过程包括以下步骤:

在SSMS中，右键单击有问题的表，并选择查看依赖项 记下引用的表格(如果有的话) 回到对象资源管理器，展开Keys节点并记下外键(如果有的话) 开始编写脚本(删除/截断/重新创建)

这种性质的脚本应该在begin tran和commit tran块中完成。

你可以按照这个步骤来做， 通过重新播种表，可以删除表中的数据。

delete from table_name
dbcc checkident('table_name',reseed,0)

如果出现错误，则必须重新播种主表。

可以在网上其他地方找到

EXEC sp_MSForEachTable 'ALTER TABLE ? NOCHECK CONSTRAINT ALL'
EXEC sp_MSForEachTable 'ALTER TABLE ? DISABLE TRIGGER ALL'
-- EXEC sp_MSForEachTable 'DELETE FROM ?' -- Uncomment to execute
EXEC sp_MSForEachTable 'ALTER TABLE ? CHECK CONSTRAINT ALL'
EXEC sp_MSForEachTable 'ALTER TABLE ? ENABLE TRIGGER ALL'