使用MSSQL2005，如果我首先截断子表(具有FK关系的主键的表)，我可以截断带有外键约束的表吗?
我知道我也可以
使用不带where子句的DELETE，然后RESEED标识(或) 删除FK，截断表，并重新创建FK。
我认为只要我在父表之前截断子表，我就可以不做上面的任何一个选项，但我得到了这个错误:
不能截断表'TableName'，因为它被一个FOREIGN KEY约束引用。
当前回答
好吧，因为我没有找到我使用的非常简单的解决方案的例子，这是:
删除外键; 截断表 重新创建外键
是这样的:
1)查找导致失败的外键名称(例如:FK_PROBLEM_REASON，带字段ID，来自表TABLE_OWNING_CONSTRAINT) 2)从表中删除该键:
ALTER TABLE TABLE_OWNING_CONSTRAINT DROP CONSTRAINT FK_PROBLEM_REASON
3)截断招聘表
TRUNCATE TABLE TABLE_TO_TRUNCATE
4)重新添加第一个表的键:
ALTER TABLE TABLE_OWNING_CONSTRAINT ADD CONSTRAINT FK_PROBLEM_REASON FOREIGN KEY(ID) REFERENCES TABLE_TO_TRUNCATE (ID)
就是这样。
其他回答
这是我对这个问题的解决方案。我用它来改变PK，但想法是一样的。希望这将是有用的)
PRINT 'Script starts'
DECLARE @foreign_key_name varchar(255)
DECLARE @keycnt int
DECLARE @foreign_table varchar(255)
DECLARE @foreign_column_1 varchar(255)
DECLARE @foreign_column_2 varchar(255)
DECLARE @primary_table varchar(255)
DECLARE @primary_column_1 varchar(255)
DECLARE @primary_column_2 varchar(255)
DECLARE @TablN varchar(255)
-->> Type the primary table name
SET @TablN = ''
--------------------------------------------------------------------------------------- ------------------------------
--Here will be created the temporary table with all reference FKs
---------------------------------------------------------------------------------------------------------------------
PRINT 'Creating the temporary table'
select cast(f.name as varchar(255)) as foreign_key_name
, r.keycnt
, cast(c.name as varchar(255)) as foreign_table
, cast(fc.name as varchar(255)) as foreign_column_1
, cast(fc2.name as varchar(255)) as foreign_column_2
, cast(p.name as varchar(255)) as primary_table
, cast(rc.name as varchar(255)) as primary_column_1
, cast(rc2.name as varchar(255)) as primary_column_2
into #ConTab
from sysobjects f
inner join sysobjects c on f.parent_obj = c.id
inner join sysreferences r on f.id = r.constid
inner join sysobjects p on r.rkeyid = p.id
inner join syscolumns rc on r.rkeyid = rc.id and r.rkey1 = rc.colid
inner join syscolumns fc on r.fkeyid = fc.id and r.fkey1 = fc.colid
left join syscolumns rc2 on r.rkeyid = rc2.id and r.rkey2 = rc.colid
left join syscolumns fc2 on r.fkeyid = fc2.id and r.fkey2 = fc.colid
where f.type = 'F' and p.name = @TablN
ORDER BY cast(p.name as varchar(255))
---------------------------------------------------------------------------------------------------------------------
--Cursor, below, will drop all reference FKs
---------------------------------------------------------------------------------------------------------------------
DECLARE @CURSOR CURSOR
/*Fill in cursor*/
PRINT 'Cursor 1 starting. All refernce FK will be droped'
SET @CURSOR = CURSOR SCROLL
FOR
select foreign_key_name
, keycnt
, foreign_table
, foreign_column_1
, foreign_column_2
, primary_table
, primary_column_1
, primary_column_2
from #ConTab
OPEN @CURSOR
FETCH NEXT FROM @CURSOR INTO @foreign_key_name, @keycnt, @foreign_table, @foreign_column_1, @foreign_column_2,
@primary_table, @primary_column_1, @primary_column_2
WHILE @@FETCH_STATUS = 0
BEGIN
EXEC ('ALTER TABLE ['+@foreign_table+'] DROP CONSTRAINT ['+@foreign_key_name+']')
FETCH NEXT FROM @CURSOR INTO @foreign_key_name, @keycnt, @foreign_table, @foreign_column_1, @foreign_column_2,
@primary_table, @primary_column_1, @primary_column_2
END
CLOSE @CURSOR
PRINT 'Cursor 1 finished work'
---------------------------------------------------------------------------------------------------------------------
--Here you should provide the chainging script for the primary table
---------------------------------------------------------------------------------------------------------------------
PRINT 'Altering primary table begin'
TRUNCATE TABLE table_name
PRINT 'Altering finished'
---------------------------------------------------------------------------------------------------------------------
--Cursor, below, will add again all reference FKs
--------------------------------------------------------------------------------------------------------------------
PRINT 'Cursor 2 starting. All refernce FK will added'
SET @CURSOR = CURSOR SCROLL
FOR
select foreign_key_name
, keycnt
, foreign_table
, foreign_column_1
, foreign_column_2
, primary_table
, primary_column_1
, primary_column_2
from #ConTab
OPEN @CURSOR
FETCH NEXT FROM @CURSOR INTO @foreign_key_name, @keycnt, @foreign_table, @foreign_column_1, @foreign_column_2,
@primary_table, @primary_column_1, @primary_column_2
WHILE @@FETCH_STATUS = 0
BEGIN
EXEC ('ALTER TABLE [' +@foreign_table+ '] WITH NOCHECK ADD CONSTRAINT [' +@foreign_key_name+ '] FOREIGN KEY(['+@foreign_column_1+'])
REFERENCES [' +@primary_table+'] (['+@primary_column_1+'])')
EXEC ('ALTER TABLE [' +@foreign_table+ '] CHECK CONSTRAINT [' +@foreign_key_name+']')
FETCH NEXT FROM @CURSOR INTO @foreign_key_name, @keycnt, @foreign_table, @foreign_column_1, @foreign_column_2,
@primary_table, @primary_column_1, @primary_column_2
END
CLOSE @CURSOR
PRINT 'Cursor 2 finished work'
---------------------------------------------------------------------------------------------------------------------
PRINT 'Temporary table droping'
drop table #ConTab
PRINT 'Finish'
没有ALTER TABLE
-- Delete all records
DELETE FROM [TableName]
-- Set current ID to "1"
-- If table already contains data, use "0"
-- If table is empty and never insert data, use "1"
-- Use SP https://github.com/reduardo7/TableTruncate
DBCC CHECKIDENT ([TableName], RESEED, 0)
作为存储过程
https://github.com/reduardo7/TableTruncate
注意，如果您有数百万条以上的记录，这可能不是您想要的，因为它非常慢。
如果您以任何频率执行此操作，甚至在时间表上，我绝对不会明确地使用DML语句。写入事务日志的成本非常高，将整个数据库设置为SIMPLE恢复模式以截断一个表是荒谬的。
最好的办法，不幸是艰苦或费力的办法。这是:
减少约束 截断表 重新创建约束
我这样做的过程包括以下步骤:
在SSMS中，右键单击有问题的表，并选择查看依赖项 记下引用的表格(如果有的话) 回到对象资源管理器，展开Keys节点并记下外键(如果有的话) 开始编写脚本(删除/截断/重新创建)
这种性质的脚本应该在begin tran和commit tran块中完成。
唯一的方法是在截断之前删除外键。截断数据之后，必须重新创建索引。
下面的脚本生成删除所有外键约束所需的SQL。
DECLARE @drop NVARCHAR(MAX) = N'';
SELECT @drop += N'
ALTER TABLE ' + QUOTENAME(cs.name) + '.' + QUOTENAME(ct.name)
+ ' DROP CONSTRAINT ' + QUOTENAME(fk.name) + ';'
FROM sys.foreign_keys AS fk
INNER JOIN sys.tables AS ct
ON fk.parent_object_id = ct.[object_id]
INNER JOIN sys.schemas AS cs
ON ct.[schema_id] = cs.[schema_id];
SELECT @drop
接下来，下面的脚本生成重新创建外键所需的SQL。
DECLARE @create NVARCHAR(MAX) = N'';
SELECT @create += N'
ALTER TABLE '
+ QUOTENAME(cs.name) + '.' + QUOTENAME(ct.name)
+ ' ADD CONSTRAINT ' + QUOTENAME(fk.name)
+ ' FOREIGN KEY (' + STUFF((SELECT ',' + QUOTENAME(c.name)
-- get all the columns in the constraint table
FROM sys.columns AS c
INNER JOIN sys.foreign_key_columns AS fkc
ON fkc.parent_column_id = c.column_id
AND fkc.parent_object_id = c.[object_id]
WHERE fkc.constraint_object_id = fk.[object_id]
ORDER BY fkc.constraint_column_id
FOR XML PATH(N''), TYPE).value(N'.[1]', N'nvarchar(max)'), 1, 1, N'')
+ ') REFERENCES ' + QUOTENAME(rs.name) + '.' + QUOTENAME(rt.name)
+ '(' + STUFF((SELECT ',' + QUOTENAME(c.name)
-- get all the referenced columns
FROM sys.columns AS c
INNER JOIN sys.foreign_key_columns AS fkc
ON fkc.referenced_column_id = c.column_id
AND fkc.referenced_object_id = c.[object_id]
WHERE fkc.constraint_object_id = fk.[object_id]
ORDER BY fkc.constraint_column_id
FOR XML PATH(N''), TYPE).value(N'.[1]', N'nvarchar(max)'), 1, 1, N'') + ');'
FROM sys.foreign_keys AS fk
INNER JOIN sys.tables AS rt -- referenced table
ON fk.referenced_object_id = rt.[object_id]
INNER JOIN sys.schemas AS rs
ON rt.[schema_id] = rs.[schema_id]
INNER JOIN sys.tables AS ct -- constraint table
ON fk.parent_object_id = ct.[object_id]
INNER JOIN sys.schemas AS cs
ON ct.[schema_id] = cs.[schema_id]
WHERE rt.is_ms_shipped = 0 AND ct.is_ms_shipped = 0;
SELECT @create
运行生成的脚本删除所有外键，截断表，然后运行生成的脚本重新创建所有外键。
查询从这里开始。
最简单的方法: 1 -在phpmyadmin中输入 2 -点击左列的表名 3 -点击操作(顶部菜单) 4 -点击“清空表格(TRUNCATE)” 5 -禁用框“启用外键检查” 6 -完成!
图片教程链接 教程:http://www.imageno.com/wz6gv1wuqajrpic.html (对不起，我没有足够的声誉上传图片:P)
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