DELETE FROM TABLENAME
DBCC CHECKIDENT ('DATABASENAME.dbo.TABLENAME', RESEED, 0)

注意，如果您有数百万条以上的记录，这可能不是您想要的，因为它非常慢。

这是一个使用实体框架的人的例子

要重置的表:Foo 另一个表取决于:酒吧 约束表Foo上的列:FooColumn 表Bar上的约束列:BarColumn 公共覆盖无效Down() ｛ DropForeignKey(“dbo。Bar"， "BarColumn"， "dbo.Foo"); Sql("TRUNCATE TABLE Foo"); AddForeignKey(“dbo。Bar"， "BarColumn"， "dbo "。Foo"， "FooColumn"， cascadeDelete: true); ｝

@denver_citizen和@Peter Szanto的回答对我不太适用，但我修改了它们，以解释:

组合键 “删除”和“更新”动作 重新添加时检查索引 dbo以外的模式 同时处理多个表

DECLARE @Debug bit = 0;

-- List of tables to truncate
select
    SchemaName, Name
into #tables
from (values 
    ('schema', 'table')
    ,('schema2', 'table2')
) as X(SchemaName, Name)


BEGIN TRANSACTION TruncateTrans;

with foreignKeys AS (
     SELECT 
        SCHEMA_NAME(fk.schema_id) as SchemaName
        ,fk.Name as ConstraintName
        ,OBJECT_NAME(fk.parent_object_id) as TableName
        ,SCHEMA_NAME(t.SCHEMA_ID) as ReferencedSchemaName
        ,OBJECT_NAME(fk.referenced_object_id) as ReferencedTableName
        ,fc.constraint_column_id
        ,COL_NAME(fk.parent_object_id, fc.parent_column_id) AS ColumnName
        ,COL_NAME(fk.referenced_object_id, fc.referenced_column_id) as ReferencedColumnName
        ,fk.delete_referential_action_desc
        ,fk.update_referential_action_desc
    FROM sys.foreign_keys AS fk
        JOIN sys.foreign_key_columns AS fc
            ON fk.object_id = fc.constraint_object_id
        JOIN #tables tbl 
            ON OBJECT_NAME(fc.referenced_object_id) = tbl.Name
        JOIN sys.tables t on OBJECT_NAME(t.object_id) = tbl.Name 
            and SCHEMA_NAME(t.schema_id) = tbl.SchemaName
            and t.OBJECT_ID = fc.referenced_object_id
)



select
    quotename(fk.ConstraintName) AS ConstraintName
    ,quotename(fk.SchemaName) + '.' + quotename(fk.TableName) AS TableName
    ,quotename(fk.ReferencedSchemaName) + '.' + quotename(fk.ReferencedTableName) AS ReferencedTableName
    ,replace(fk.delete_referential_action_desc, '_', ' ') AS DeleteAction
    ,replace(fk.update_referential_action_desc, '_', ' ') AS UpdateAction
    ,STUFF((
        SELECT ',' + quotename(fk2.ColumnName)
        FROM foreignKeys fk2 
        WHERE fk2.ConstraintName = fk.ConstraintName and fk2.SchemaName = fk.SchemaName
        ORDER BY fk2.constraint_column_id
        FOR XML PATH('')
    ),1,1,'') AS ColumnNames
    ,STUFF((
        SELECT ',' + quotename(fk2.ReferencedColumnName)
        FROM foreignKeys fk2 
        WHERE fk2.ConstraintName = fk.ConstraintName and fk2.SchemaName = fk.SchemaName
        ORDER BY fk2.constraint_column_id
        FOR XML PATH('')
    ),1,1,'') AS ReferencedColumnNames
into #FKs
from foreignKeys fk
GROUP BY fk.SchemaName, fk.ConstraintName, fk.TableName, fk.ReferencedSchemaName, fk.ReferencedTableName, fk.delete_referential_action_desc, fk.update_referential_action_desc



-- Drop FKs
select 
    identity(int,1,1) as ID,
    'ALTER TABLE ' + fk.TableName + ' DROP CONSTRAINT ' + fk.ConstraintName AS script
into #scripts
from #FKs fk

-- Truncate 
insert into #scripts
select distinct 
    'TRUNCATE TABLE ' + quotename(tbl.SchemaName) + '.' + quotename(tbl.Name) AS script
from #tables tbl

-- Recreate
insert into #scripts
select 
    'ALTER TABLE ' + fk.TableName + 
    ' WITH CHECK ADD CONSTRAINT ' + fk.ConstraintName + 
    ' FOREIGN KEY ('+ fk.ColumnNames +')' + 
    ' REFERENCES ' + fk.ReferencedTableName +' ('+ fk.ReferencedColumnNames +')' +
    ' ON DELETE ' + fk.DeleteAction COLLATE Latin1_General_CI_AS_KS_WS + ' ON UPDATE ' + fk.UpdateAction COLLATE Latin1_General_CI_AS_KS_WS AS script
from #FKs fk


DECLARE @script nvarchar(MAX);

DECLARE curScripts CURSOR FOR 
    select script
    from #scripts
    order by ID

OPEN curScripts

WHILE 1=1 BEGIN
    FETCH NEXT FROM curScripts INTO @script
    IF @@FETCH_STATUS != 0 BREAK;

    print @script;
    IF @Debug = 0
        EXEC (@script);
END
CLOSE curScripts
DEALLOCATE curScripts


drop table #scripts
drop table #FKs
drop table #tables


COMMIT TRANSACTION TruncateTrans;

因为TRUNCATE TABLE是一个DDL命令，所以它不能检查表中的记录是否被子表中的记录引用。

这就是为什么DELETE有效而TRUNCATE TABLE无效的原因:因为数据库能够确保它没有被另一条记录引用。

SET FOREIGN_KEY_CHECKS=0;
TRUNCATE table1;
TRUNCATE table2;
SET FOREIGN_KEY_CHECKS=1;

引用-截断外键约束表

在MYSQL为我工作

在使用delete语句删除表中的所有行之后，使用以下命令

delete from tablename

DBCC CHECKIDENT ('tablename', RESEED, 0)

编辑:修正的SQL Server语法