你可以按照这个步骤来做， 通过重新播种表，可以删除表中的数据。

delete from table_name
dbcc checkident('table_name',reseed,0)

如果出现错误，则必须重新播种主表。

这是我对这个问题的解决方案。我用它来改变PK，但想法是一样的。希望这将是有用的)

PRINT 'Script starts'

DECLARE @foreign_key_name varchar(255)
DECLARE @keycnt int
DECLARE @foreign_table varchar(255)
DECLARE @foreign_column_1 varchar(255)
DECLARE @foreign_column_2 varchar(255)
DECLARE @primary_table varchar(255)
DECLARE @primary_column_1 varchar(255)
DECLARE @primary_column_2 varchar(255)
DECLARE @TablN varchar(255)

-->> Type the primary table name
SET @TablN = ''
---------------------------------------------------------------------------------------    ------------------------------
--Here will be created the temporary table with all reference FKs
---------------------------------------------------------------------------------------------------------------------
PRINT 'Creating the temporary table'
select cast(f.name  as varchar(255)) as foreign_key_name
    , r.keycnt
    , cast(c.name as  varchar(255)) as foreign_table
    , cast(fc.name as varchar(255)) as  foreign_column_1
    , cast(fc2.name as varchar(255)) as foreign_column_2
    , cast(p.name as varchar(255)) as primary_table
    , cast(rc.name as varchar(255))  as primary_column_1
    , cast(rc2.name as varchar(255)) as  primary_column_2
    into #ConTab
    from sysobjects f
    inner join sysobjects c on  f.parent_obj = c.id 
    inner join sysreferences r on f.id =  r.constid
    inner join sysobjects p on r.rkeyid = p.id
    inner  join syscolumns rc on r.rkeyid = rc.id and r.rkey1 = rc.colid
    inner  join syscolumns fc on r.fkeyid = fc.id and r.fkey1 = fc.colid
    left join  syscolumns rc2 on r.rkeyid = rc2.id and r.rkey2 = rc.colid
    left join  syscolumns fc2 on r.fkeyid = fc2.id and r.fkey2 = fc.colid
    where f.type =  'F' and p.name = @TablN
 ORDER BY cast(p.name as varchar(255))
---------------------------------------------------------------------------------------------------------------------
--Cursor, below, will drop all reference FKs
---------------------------------------------------------------------------------------------------------------------
DECLARE @CURSOR CURSOR
/*Fill in cursor*/

PRINT 'Cursor 1 starting. All refernce FK will be droped'

SET @CURSOR  = CURSOR SCROLL
FOR
select foreign_key_name
    , keycnt
    , foreign_table
    , foreign_column_1
    , foreign_column_2
    , primary_table
    , primary_column_1
    , primary_column_2
    from #ConTab

OPEN @CURSOR

FETCH NEXT FROM @CURSOR INTO @foreign_key_name, @keycnt, @foreign_table,         @foreign_column_1, @foreign_column_2, 
                        @primary_table, @primary_column_1, @primary_column_2

WHILE @@FETCH_STATUS = 0
BEGIN

    EXEC ('ALTER TABLE ['+@foreign_table+'] DROP CONSTRAINT ['+@foreign_key_name+']')

FETCH NEXT FROM @CURSOR INTO @foreign_key_name, @keycnt, @foreign_table, @foreign_column_1, @foreign_column_2, 
                         @primary_table, @primary_column_1, @primary_column_2
END
CLOSE @CURSOR
PRINT 'Cursor 1 finished work'
---------------------------------------------------------------------------------------------------------------------
--Here you should provide the chainging script for the primary table
---------------------------------------------------------------------------------------------------------------------

PRINT 'Altering primary table begin'

TRUNCATE TABLE table_name

PRINT 'Altering finished'

---------------------------------------------------------------------------------------------------------------------
--Cursor, below, will add again all reference FKs
--------------------------------------------------------------------------------------------------------------------

PRINT 'Cursor 2 starting. All refernce FK will added'
SET @CURSOR  = CURSOR SCROLL
FOR
select foreign_key_name
    , keycnt
    , foreign_table
    , foreign_column_1
    , foreign_column_2
    , primary_table
    , primary_column_1
    , primary_column_2
    from #ConTab

OPEN @CURSOR

FETCH NEXT FROM @CURSOR INTO @foreign_key_name, @keycnt, @foreign_table, @foreign_column_1, @foreign_column_2, 
                         @primary_table, @primary_column_1, @primary_column_2

WHILE @@FETCH_STATUS = 0
BEGIN

    EXEC ('ALTER TABLE [' +@foreign_table+ '] WITH NOCHECK ADD  CONSTRAINT [' +@foreign_key_name+ '] FOREIGN KEY(['+@foreign_column_1+'])
        REFERENCES [' +@primary_table+'] (['+@primary_column_1+'])')

    EXEC ('ALTER TABLE [' +@foreign_table+ '] CHECK CONSTRAINT [' +@foreign_key_name+']')

FETCH NEXT FROM @CURSOR INTO @foreign_key_name, @keycnt, @foreign_table, @foreign_column_1, @foreign_column_2, 
                         @primary_table, @primary_column_1, @primary_column_2
END
CLOSE @CURSOR
PRINT 'Cursor 2 finished work'
---------------------------------------------------------------------------------------------------------------------
PRINT 'Temporary table droping'
drop table #ConTab
PRINT 'Finish'

正确的;你不能截断一个有FK约束的表。

通常我的处理方法是:

去掉约束 截断表格 重新创建约束。

(当然，这一切都在一笔交易中。)

当然，这只适用于子节点已经被截断的情况。否则，我会走不同的路线，完全取决于我的数据是什么样子的。(变量太多，不便在此赘述。)

最初的海报决定了为什么会这样;更多细节请看这个答案。

我写了以下方法，并尝试将它们参数化，这样你就可以在查询文档中运行它们，或者轻松地使用它们制作一个有用的SP。

一)删除

如果你的表没有数百万条记录，这工作得很好，没有任何Alter命令:

---------------------------------------------------------------
------------------- Just Fill Parameters Value ----------------
---------------------------------------------------------------
DECLARE @DbName AS NVARCHAR(30) = 'MyDb'         --< Db Name
DECLARE @Schema AS NVARCHAR(30) = 'dbo'          --< Schema
DECLARE @TableName AS NVARCHAR(30) = 'Book'      --< Table Name
------------------ /Just Fill Parameters Value ----------------

DECLARE @Query AS NVARCHAR(500) = 'Delete FROM ' + @TableName

EXECUTE sp_executesql @Query
SET @Query=@DbName+'.'+@Schema+'.'+@TableName
DBCC CHECKIDENT (@Query,RESEED, 0)

在我上面的回答中，解决问题中提到的问题的方法是基于@s15199d的回答。

B)截断

如果你的表有数百万条记录，或者你在你的代码中没有任何Alter命令的问题，那么使用这个:

--   Book                               Student
--
--   |  BookId  | Field1 |              | StudentId |  BookId  |
--   ---------------------              ------------------------ 
--   |    1     |    A   |              |     2     |    1     |  
--   |    2     |    B   |              |     1     |    1     |
--   |    3     |    C   |              |     2     |    3     |  

---------------------------------------------------------------
------------------- Just Fill Parameters Value ----------------
---------------------------------------------------------------
DECLARE @DbName AS NVARCHAR(30) = 'MyDb'
DECLARE @Schema AS NVARCHAR(30) = 'dbo'
DECLARE @TableName_ToTruncate AS NVARCHAR(30) = 'Book'

DECLARE @TableName_OfOwnerOfConstraint AS NVARCHAR(30) = 'Student' --< Decelations About FK_Book_Constraint
DECLARE @Ref_ColumnName_In_TableName_ToTruncate AS NVARCHAR(30) = 'BookId' --< Decelations About FK_Book_Constraint
DECLARE @FK_ColumnName_In_TableOfOwnerOfConstraint AS NVARCHAR(30) = 'Fk_BookId' --< Decelations About FK_Book_Constraint
DECLARE @FK_ConstraintName AS NVARCHAR(30) = 'FK_Book_Constraint'                --< Decelations About FK_Book_Constraint
------------------ /Just Fill Parameters Value ----------------

DECLARE @Query AS NVARCHAR(2000)

SET @Query= 'ALTER TABLE '+@TableName_OfOwnerOfConstraint+' DROP CONSTRAINT '+@FK_ConstraintName
EXECUTE sp_executesql @Query

SET @Query= 'Truncate Table '+ @TableName_ToTruncate
EXECUTE sp_executesql @Query

SET @Query= 'ALTER TABLE '+@TableName_OfOwnerOfConstraint+' ADD CONSTRAINT '+@FK_ConstraintName+' FOREIGN KEY('+@FK_ColumnName_In_TableOfOwnerOfConstraint+') REFERENCES '+@TableName_ToTruncate+'('+@Ref_ColumnName_In_TableName_ToTruncate+')'
EXECUTE sp_executesql @Query

在上面的回答中，我解决问题中提到的问题的方法是基于@LauroWolffValenteSobrinho的回答。 如果你有不止一个约束，那么你应该把它的代码像我一样附加到上面的查询 此外，您还可以更改上面的代码基@SerjSagan answer来禁用或启用约束

因为TRUNCATE TABLE是一个DDL命令，所以它不能检查表中的记录是否被子表中的记录引用。

这就是为什么DELETE有效而TRUNCATE TABLE无效的原因:因为数据库能够确保它没有被另一条记录引用。

SET FOREIGN_KEY_CHECKS=0;
TRUNCATE table1;
TRUNCATE table2;
SET FOREIGN_KEY_CHECKS=1;

引用-截断外键约束表

在MYSQL为我工作