Collections类有一个有效的洗牌方法，可以复制，这样就不依赖于它:

/**
 * Usage:
 *    int[] array = {1, 2, 3};
 *    Util.shuffle(array);
 */
public class Util {

    private static Random random;

    /**
     * Code from method java.util.Collections.shuffle();
     */
    public static void shuffle(int[] array) {
        if (random == null) random = new Random();
        int count = array.length;
        for (int i = count; i > 1; i--) {
            swap(array, i - 1, random.nextInt(i));
        }
    }

    private static void swap(int[] array, int i, int j) {
        int temp = array[i];
        array[i] = array[j];
        array[j] = temp;
    }
}

Collections类有一个有效的洗牌方法，可以复制，这样就不依赖于它:

/**
 * Usage:
 *    int[] array = {1, 2, 3};
 *    Util.shuffle(array);
 */
public class Util {

    private static Random random;

    /**
     * Code from method java.util.Collections.shuffle();
     */
    public static void shuffle(int[] array) {
        if (random == null) random = new Random();
        int count = array.length;
        for (int i = count; i > 1; i--) {
            swap(array, i - 1, random.nextInt(i));
        }
    }

    private static void swap(int[] array, int i, int j) {
        int temp = array[i];
        array[i] = array[j];
        array[j] = temp;
    }
}

使用ArrayList<Integer>可以帮助您解决洗牌问题，而无需应用大量逻辑和消耗更少的时间。以下是我的建议:

ArrayList<Integer> x = new ArrayList<Integer>();
for(int i=1; i<=add.length(); i++)
{
    x.add(i);
}
Collections.shuffle(x);

最简单的洗牌代码:

import java.util.*;
public class ch {
    public static void main(String args[])
    {
        Scanner sc=new Scanner(System.in);
        ArrayList<Integer> l=new ArrayList<Integer>(10);
        for(int i=0;i<10;i++)
            l.add(sc.nextInt());
        Collections.shuffle(l);
        for(int j=0;j<10;j++)
            System.out.println(l.get(j));       
    }
}

Box from int[] to List<Integer> 用集合洗牌。洗牌法

int[] solutionArray = { 1, 2, 3, 4, 5, 6, 6, 5, 4, 3, 2, 1 };

List<Integer> list = Arrays.stream(solutionArray).boxed().collect(Collectors.toList());
Collections.shuffle(list);

System.out.println(list.toString());
// [1, 5, 5, 4, 2, 6, 1, 3, 3, 4, 2, 6]

最简单的解决方案，这种随机洗牌数组。

String location[] = {"delhi","banglore","mathura","lucknow","chandigarh","mumbai"};
int index;
String temp;
Random random = new Random();
for(int i=1;i<location.length;i++)
{
    index = random.nextInt(i+1);
    temp = location[index];
    location[index] = location[i];
    location[i] = temp;
    System.out.println("Location Based On Random Values :"+location[i]);
}