下面的代码将实现数组的随机排序。

// Shuffle the elements in the array
Collections.shuffle(Arrays.asList(array));

来自:http://www.programcreek.com/2012/02/java-method-to-shuffle-an-int-array-with-random-order/

还有另一种方法，还没有发布

//that way, send many object types diferentes
public anotherWayToReciveParameter(Object... objects)
{
    //ready with array
    final int length =objects.length;
    System.out.println(length);
    //for ready same list
    Arrays.asList(objects);
}

这种方法更简单，取决于上下文

下面是一个使用Apache Commons Math 3的解决方案。X(仅适用于int[]数组):

MathArrays.shuffle(array);

http://commons.apache.org/proper/commons-math/javadocs/api-3.6.1/org/apache/commons/math3/util/MathArrays.html shuffle (int [])

另外，Apache Commons Lang 3.6为ArrayUtils类引入了新的shuffle方法(用于对象和任何基本类型)。

ArrayUtils.shuffle(array);

http://commons.apache.org/proper/commons-lang/javadocs/api-release/org/apache/commons/lang3/ArrayUtils.html#shuffle-int:A-

使用Guava的int . aslist()就像这样简单:

Collections.shuffle(Ints.asList(array));

下面是一个有效的Fisher-Yates shuffle数组函数:

private static void shuffleArray(int[] array)
{
    int index;
    Random random = new Random();
    for (int i = array.length - 1; i > 0; i--)
    {
        index = random.nextInt(i + 1);
        if (index != i)
        {
            array[index] ^= array[i];
            array[i] ^= array[index];
            array[index] ^= array[i];
        }
    }
}

or

private static void shuffleArray(int[] array)
{
    int index, temp;
    Random random = new Random();
    for (int i = array.length - 1; i > 0; i--)
    {
        index = random.nextInt(i + 1);
        temp = array[index];
        array[index] = array[i];
        array[i] = temp;
    }
}

下面是一个使用数组列表的简单方法:

List<Integer> solution = new ArrayList<>();
for (int i = 1; i <= 6; i++) {
    solution.add(i);
}
Collections.shuffle(solution);