Try-catch是用来帮助异常处理的。这意味着它将在某种程度上帮助我们的系统变得更加健壮:尝试从意外事件中恢复。

我们怀疑在执行和指令(发送消息)时可能会发生一些事情,因此它被包含在try中。如果发生了几乎意想不到的事情,我们可以做些什么:我们编写捕获。我不认为我们调用只是为了记录异常。我认为catch块是为了给我们从错误中恢复的机会。

现在,假设我们从错误中恢复,因为我们可以修复错误。如果能再试一次,那就太好了:

try{ some_instruction(); }
catch (NearlyUnexpectedException e){
   fix_the_problem();
   retry;
}

这将很快陷入永恒循环,但让我们假设fix_the_problem返回true,然后重试。假设在Java中没有这样的东西,你将如何解决这个问题?你认为解决这个问题的最佳设计代码是什么?

这就像一个哲学问题,因为我已经知道Java不直接支持我所要求的内容。


当前回答

如果它是有用的,可以考虑更多的选项,所有放在一起(停止文件而不是重试,睡眠,继续更大的循环)都可能有帮助。

 bigLoop:
 while(!stopFileExists()) {
    try {
      // do work
      break;
    }
    catch (ExpectedExceptionType e) {

       // could sleep in here, too.

       // another option would be to "restart" some bigger loop, like
       continue bigLoop;
    }
    // ... more work
}

其他回答

如果不是所有异常都需要重试,那么只有一些例外。如果至少要尝试一次,这里有一个替代的实用方法:

void runWithRetry(Runnable runnable, Class<Exception> exClass, int maxRetries) {
        Exception err = null;
        do {
            maxRetries--;
            try {
                runnable.run();
                err = null;
            } catch (Exception e) {
                if(exClass.isAssignableFrom(e.getClass())){
                    err = e;
                }else {
                    throw e;
                }
            }
        } while (err != null && maxRetries > 0);

        if (err != null) {
            throw err;
        }
    }

用法:

    runWithRetry(() -> {
       // do something
    }, TimeoutException.class, 5)

如果它是有用的,可以考虑更多的选项,所有放在一起(停止文件而不是重试,睡眠,继续更大的循环)都可能有帮助。

 bigLoop:
 while(!stopFileExists()) {
    try {
      // do work
      break;
    }
    catch (ExpectedExceptionType e) {

       // could sleep in here, too.

       // another option would be to "restart" some bigger loop, like
       continue bigLoop;
    }
    // ... more work
}

你需要像这样在while循环中封装try-catch: -

int count = 0;
int maxTries = 3;
while(true) {
    try {
        // Some Code
        // break out of loop, or return, on success
    } catch (SomeException e) {
        // handle exception
        if (++count == maxTries) throw e;
    }
}

我已经采取了count和maxTries,以避免运行到一个无限循环,以防异常继续发生在你的try块。

这是一个老问题,但解决方案仍然重要。以下是我在Java 8中不使用任何第三方库的通用解决方案:

public interface RetryConsumer<T> {
    T evaluate() throws Throwable;
}
public interface RetryPredicate<T> {
    boolean shouldRetry(T t);
}
public class RetryOperation<T> {
    private RetryConsumer<T> retryConsumer;
    private int noOfRetry;
    private int delayInterval;
    private TimeUnit timeUnit;
    private RetryPredicate<T> retryPredicate;
    private List<Class<? extends Throwable>> exceptionList;

    public static class OperationBuilder<T> {
        private RetryConsumer<T> iRetryConsumer;
        private int iNoOfRetry;
        private int iDelayInterval;
        private TimeUnit iTimeUnit;
        private RetryPredicate<T> iRetryPredicate;
        private Class<? extends Throwable>[] exceptionClasses;

        private OperationBuilder() {
        }

        public OperationBuilder<T> retryConsumer(final RetryConsumer<T> retryConsumer) {
            this.iRetryConsumer = retryConsumer;
            return this;
        }

        public OperationBuilder<T> noOfRetry(final int noOfRetry) {
            this.iNoOfRetry = noOfRetry;
            return this;
        }

        public OperationBuilder<T> delayInterval(final int delayInterval, final TimeUnit timeUnit) {
            this.iDelayInterval = delayInterval;
            this.iTimeUnit = timeUnit;
            return this;
        }

        public OperationBuilder<T> retryPredicate(final RetryPredicate<T> retryPredicate) {
            this.iRetryPredicate = retryPredicate;
            return this;
        }

        @SafeVarargs
        public final OperationBuilder<T> retryOn(final Class<? extends Throwable>... exceptionClasses) {
            this.exceptionClasses = exceptionClasses;
            return this;
        }

        public RetryOperation<T> build() {
            if (Objects.isNull(iRetryConsumer)) {
                throw new RuntimeException("'#retryConsumer:RetryConsumer<T>' not set");
            }

            List<Class<? extends Throwable>> exceptionList = new ArrayList<>();
            if (Objects.nonNull(exceptionClasses) && exceptionClasses.length > 0) {
                exceptionList = Arrays.asList(exceptionClasses);
            }
            iNoOfRetry = iNoOfRetry == 0 ? 1 : 0;
            iTimeUnit = Objects.isNull(iTimeUnit) ? TimeUnit.MILLISECONDS : iTimeUnit;
            return new RetryOperation<>(iRetryConsumer, iNoOfRetry, iDelayInterval, iTimeUnit, iRetryPredicate, exceptionList);
        }
    }

    public static <T> OperationBuilder<T> newBuilder() {
        return new OperationBuilder<>();
    }

    private RetryOperation(RetryConsumer<T> retryConsumer, int noOfRetry, int delayInterval, TimeUnit timeUnit,
                           RetryPredicate<T> retryPredicate, List<Class<? extends Throwable>> exceptionList) {
        this.retryConsumer = retryConsumer;
        this.noOfRetry = noOfRetry;
        this.delayInterval = delayInterval;
        this.timeUnit = timeUnit;
        this.retryPredicate = retryPredicate;
        this.exceptionList = exceptionList;
    }

    public T retry() throws Throwable {
        T result = null;
        int retries = 0;
        while (retries < noOfRetry) {
            try {
                result = retryConsumer.evaluate();
                if (Objects.nonNull(retryPredicate)) {
                    boolean shouldItRetry = retryPredicate.shouldRetry(result);
                    if (shouldItRetry) {
                        retries = increaseRetryCountAndSleep(retries);
                    } else {
                        return result;
                    }
                } else {
                    // no retry condition defined, no exception thrown. This is the desired result.
                    return result;
                }
            } catch (Throwable e) {
                retries = handleException(retries, e);
            }
        }
        return result;
    }

    private int handleException(int retries, Throwable e) throws Throwable {
        if (exceptionList.contains(e.getClass()) || (exceptionList.isEmpty())) {
            // exception is excepted, continue retry.
            retries = increaseRetryCountAndSleep(retries);
            if (retries == noOfRetry) {
                // evaluation is throwing exception, no more retry left. Throw it.
                throw e;
            }
        } else {
            // unexpected exception, no retry required. Throw it.
            throw e;
        }
        return retries;
    }

    private int increaseRetryCountAndSleep(int retries) {
        retries++;
        if (retries < noOfRetry && delayInterval > 0) {
            try {
                timeUnit.sleep(delayInterval);
            } catch (InterruptedException ignore) {
                Thread.currentThread().interrupt();
            }
        }
        return retries;
    }
}

让我们有一个这样的测试用例:

@Test
public void withPredicateAndException() {
    AtomicInteger integer = new AtomicInteger();
    try {
        Integer result = RetryOperation.<Integer>newBuilder()
                .retryConsumer(() -> {
                    int i = integer.incrementAndGet();
                    if (i % 2 == 1) {
                        throw new NumberFormatException("Very odd exception");
                    } else {
                        return i;
                    }
                })
                .noOfRetry(10)
                .delayInterval(10, TimeUnit.MILLISECONDS)
                .retryPredicate(value -> value <= 6)
                .retryOn(NumberFormatException.class, EOFException.class)
                .build()
                .retry();
        Assert.assertEquals(8, result.intValue());
    } catch (Throwable throwable) {
        Assert.fail();
    }
}

你可以从jcabi-aspect(我是一名开发人员)使用AOP和Java注释:

@RetryOnFailure(attempts = 3, delay = 5)
public String load(URL url) {
  return url.openConnection().getContent();
}

您还可以使用@Loggable和@LogException注释。