如果你需要数值，这是最快的方法:

dog, cat, rabbit = range(3)

在Python 3中。X你也可以在最后添加一个星号占位符，它将吸收范围内所有剩余的值，以防你不介意浪费内存和无法计数:

dog, cat, rabbit, horse, *_ = range(100)

我喜欢Java枚举，这就是我在Python中的做法:

def enum(clsdef):
    class Enum(object):
        __slots__=tuple([var for var in clsdef.__dict__ if isinstance((getattr(clsdef, var)), tuple) and not var.startswith('__')])

        def __new__(cls, *args, **kwargs):
            if not '_the_instance' in cls.__dict__:
                cls._the_instance = object.__new__(cls, *args, **kwargs)
            return cls._the_instance

        def __init__(self):
            clsdef.values=lambda cls, e=Enum: e.values()
            clsdef.valueOf=lambda cls, n, e=self: e.valueOf(n)
            for ordinal, key in enumerate(self.__class__.__slots__):
                args=getattr(clsdef, key)
                instance=clsdef(*args)
                instance._name=key
                instance._ordinal=ordinal
                setattr(self, key, instance)

        @classmethod
        def values(cls):
            if not hasattr(cls, '_values'):
                cls._values=[getattr(cls, name) for name in cls.__slots__]
            return cls._values

        def valueOf(self, name):
            return getattr(self, name)

        def __repr__(self):
            return ''.join(['<class Enum (', clsdef.__name__, ') at ', str(hex(id(self))), '>'])

    return Enum()

示例使用:

i=2
@enum
class Test(object):
    A=("a",1)
    B=("b",)
    C=("c",2)
    D=tuple()
    E=("e",3)

    while True:
        try:
            F, G, H, I, J, K, L, M, N, O=[tuple() for _ in range(i)]
            break;
        except ValueError:
            i+=1

    def __init__(self, name="default", aparam=0):
        self.name=name
        self.avalue=aparam

所有类变量都定义为元组，就像构造函数一样。到目前为止，还不能使用命名参数。

为什么枚举必须是整数?不幸的是，在不改变Python语言的情况下，我想不出任何好看的构造来生成它，所以我将使用字符串:

class Enumerator(object):
    def __init__(self, name):
        self.name = name

    def __eq__(self, other):
        if self.name == other:
            return True
        return self is other

    def __ne__(self, other):
        if self.name != other:
            return False
        return self is other

    def __repr__(self):
        return 'Enumerator({0})'.format(self.name)

    def __str__(self):
        return self.name

class Enum(object):
    def __init__(self, *enumerators):
        for e in enumerators:
            setattr(self, e, Enumerator(e))
    def __getitem__(self, key):
        return getattr(self, key)

也许现在更好的是，为了配置文件或其他远程输入，我们可以自然地对字符串进行测试。

例子:

class Cow(object):
    State = Enum(
        'standing',
        'walking',
        'eating',
        'mooing',
        'sleeping',
        'dead',
        'dying'
    )
    state = State.standing

In [1]: from enum import Enum

In [2]: c = Cow()

In [3]: c2 = Cow()

In [4]: c.state, c2.state
Out[4]: (Enumerator(standing), Enumerator(standing))

In [5]: c.state == c2.state
Out[5]: True

In [6]: c.State.mooing
Out[6]: Enumerator(mooing)

In [7]: c.State['mooing']
Out[7]: Enumerator(mooing)

In [8]: c.state = Cow.State.dead

In [9]: c.state == c2.state
Out[9]: False

In [10]: c.state == Cow.State.dead
Out[10]: True

In [11]: c.state == 'dead'
Out[11]: True

In [12]: c.state == Cow.State['dead']
Out[11]: True

Davidg建议使用词典。我想更进一步，使用集合:

months = set('January', 'February', ..., 'December')

现在你可以测试一个值是否与集合中的一个值匹配，如下所示:

if m in months:

但是，像dF，我通常只使用字符串常量来代替枚举。

在答案列表中没有看到这个，这是我想出的一个。它允许使用'in'关键字和len()方法:

class EnumTypeError(TypeError):
    pass

class Enum(object):
    """
    Minics enum type from different languages
    Usage:
    Letters = Enum(list('abc'))
    a = Letters.a
    print(a in Letters) # True
    print(54 in Letters) # False
    """
    def __init__(self, enums):
        if isinstance(enums, dict):
            self.__dict__.update(enums)
        elif isinstance(enums, list) or isinstance(enums, tuple):
            self.__dict__.update(**dict((v,k) for k,v in enumerate(enums)))
        else:
            raise EnumTypeError

    def __contains__(self, key):
        return key in self.__dict__.values()

    def __len__(self):
        return len(self.__dict__.values())


if __name__ == '__main__':
    print('Using a dictionary to create Enum:')
    Letters = Enum(dict((v,k) for k,v in enumerate(list('abcde'))))
    a = Letters.a
    print('\tIs a in e?', a in Letters)
    print('\tIs 54 in e?', 54 in Letters)
    print('\tLength of Letters enum:', len(Letters))

    print('\nUsing a list to create Enum:')
    Letters = Enum(list('abcde'))
    a = Letters.a
    print('\tIs a in e?', a in Letters)
    print('\tIs 54 in e?', 54 in Letters)
    print('\tLength of Letters enum:', len(Letters))

    try:
        # make sure we raise an exception if we pass an invalid arg
        Failure = Enum('This is a Failure')
        print('Failure')
    except EnumTypeError:
        print('Success!')

输出:

Using a dictionary to create Enum:
        Is a in e? True
        Is 54 in e? False
        Length of Letters enum: 5

Using a list to create Enum:
        Is a in e? True
        Is 54 in e? False
        Length of Letters enum: 5
Success!

def M_add_class_attribs(attribs):
    def foo(name, bases, dict_):
        for v, k in attribs:
            dict_[k] = v
        return type(name, bases, dict_)
    return foo

def enum(*names):
    class Foo(object):
        __metaclass__ = M_add_class_attribs(enumerate(names))
        def __setattr__(self, name, value):  # this makes it read-only
            raise NotImplementedError
    return Foo()

像这样使用它:

Animal = enum('DOG', 'CAT')
Animal.DOG # returns 0
Animal.CAT # returns 1
Animal.DOG = 2 # raises NotImplementedError

如果你只想要唯一的符号，不关心值，替换这行:

__metaclass__ = M_add_class_attribs(enumerate(names))

用这个:

__metaclass__ = M_add_class_attribs((object(), name) for name in names)