我主要是c#开发人员,但我目前正在用Python开发一个项目。
我如何在Python中表示等价的Enum ?
我主要是c#开发人员,但我目前正在用Python开发一个项目。
我如何在Python中表示等价的Enum ?
当前回答
有趣的是,前几天我正好需要这个,但我找不到一个值得使用的实现……所以我自己写了:
import functools
class EnumValue(object):
def __init__(self,name,value,type):
self.__value=value
self.__name=name
self.Type=type
def __str__(self):
return self.__name
def __repr__(self):#2.6 only... so change to what ever you need...
return '{cls}({0!r},{1!r},{2})'.format(self.__name,self.__value,self.Type.__name__,cls=type(self).__name__)
def __hash__(self):
return hash(self.__value)
def __nonzero__(self):
return bool(self.__value)
def __cmp__(self,other):
if isinstance(other,EnumValue):
return cmp(self.__value,other.__value)
else:
return cmp(self.__value,other)#hopefully their the same type... but who cares?
def __or__(self,other):
if other is None:
return self
elif type(self) is not type(other):
raise TypeError()
return EnumValue('{0.Name} | {1.Name}'.format(self,other),self.Value|other.Value,self.Type)
def __and__(self,other):
if other is None:
return self
elif type(self) is not type(other):
raise TypeError()
return EnumValue('{0.Name} & {1.Name}'.format(self,other),self.Value&other.Value,self.Type)
def __contains__(self,other):
if self.Value==other.Value:
return True
return bool(self&other)
def __invert__(self):
enumerables=self.Type.__enumerables__
return functools.reduce(EnumValue.__or__,(enum for enum in enumerables.itervalues() if enum not in self))
@property
def Name(self):
return self.__name
@property
def Value(self):
return self.__value
class EnumMeta(type):
@staticmethod
def __addToReverseLookup(rev,value,newKeys,nextIter,force=True):
if value in rev:
forced,items=rev.get(value,(force,()) )
if forced and force: #value was forced, so just append
rev[value]=(True,items+newKeys)
elif not forced:#move it to a new spot
next=nextIter.next()
EnumMeta.__addToReverseLookup(rev,next,items,nextIter,False)
rev[value]=(force,newKeys)
else: #not forcing this value
next = nextIter.next()
EnumMeta.__addToReverseLookup(rev,next,newKeys,nextIter,False)
rev[value]=(force,newKeys)
else:#set it and forget it
rev[value]=(force,newKeys)
return value
def __init__(cls,name,bases,atts):
classVars=vars(cls)
enums = classVars.get('__enumerables__',None)
nextIter = getattr(cls,'__nextitr__',itertools.count)()
reverseLookup={}
values={}
if enums is not None:
#build reverse lookup
for item in enums:
if isinstance(item,(tuple,list)):
items=list(item)
value=items.pop()
EnumMeta.__addToReverseLookup(reverseLookup,value,tuple(map(str,items)),nextIter)
else:
value=nextIter.next()
value=EnumMeta.__addToReverseLookup(reverseLookup,value,(str(item),),nextIter,False)#add it to the reverse lookup, but don't force it to that value
#build values and clean up reverse lookup
for value,fkeys in reverseLookup.iteritems():
f,keys=fkeys
for key in keys:
enum=EnumValue(key,value,cls)
setattr(cls,key,enum)
values[key]=enum
reverseLookup[value]=tuple(val for val in values.itervalues() if val.Value == value)
setattr(cls,'__reverseLookup__',reverseLookup)
setattr(cls,'__enumerables__',values)
setattr(cls,'_Max',max([key for key in reverseLookup] or [0]))
return super(EnumMeta,cls).__init__(name,bases,atts)
def __iter__(cls):
for enum in cls.__enumerables__.itervalues():
yield enum
def GetEnumByName(cls,name):
return cls.__enumerables__.get(name,None)
def GetEnumByValue(cls,value):
return cls.__reverseLookup__.get(value,(None,))[0]
class Enum(object):
__metaclass__=EnumMeta
__enumerables__=None
class FlagEnum(Enum):
@staticmethod
def __nextitr__():
yield 0
for val in itertools.count():
yield 2**val
def enum(name,*args):
return EnumMeta(name,(Enum,),dict(__enumerables__=args))
接受或离开它,它做了我需要它做的:)
像这样使用它:
class Air(FlagEnum):
__enumerables__=('None','Oxygen','Nitrogen','Hydrogen')
class Mammals(Enum):
__enumerables__=('Bat','Whale',('Dog','Puppy',1),'Cat')
Bool = enum('Bool','Yes',('No',0))
其他回答
对于旧的Python 2.x
def enum(*sequential, **named):
enums = dict(zip(sequential, [object() for _ in range(len(sequential))]), **named)
return type('Enum', (), enums)
如果你命名它,是你的问题,但如果不创建对象而不是值允许你这样做:
>>> DOG = enum('BARK', 'WALK', 'SIT')
>>> CAT = enum('MEOW', 'WALK', 'SIT')
>>> DOG.WALK == CAT.WALK
False
当使用这里的其他实现时(在我的例子中使用命名实例时),必须确保永远不要尝试比较来自不同枚举的对象。这里有一个可能的陷阱:
>>> DOG = enum('BARK'=1, 'WALK'=2, 'SIT'=3)
>>> CAT = enum('WALK'=1, 'SIT'=2)
>>> pet1_state = DOG.BARK
>>> pet2_state = CAT.WALK
>>> pet1_state == pet2_state
True
呵!
我使用元类来实现枚举(在我的想法中,它是一个const)。代码如下:
class ConstMeta(type):
'''
Metaclass for some class that store constants
'''
def __init__(cls, name, bases, dct):
'''
init class instance
'''
def static_attrs():
'''
@rtype: (static_attrs, static_val_set)
@return: Static attributes in dict format and static value set
'''
import types
attrs = {}
val_set = set()
#Maybe more
filter_names = set(['__doc__', '__init__', '__metaclass__', '__module__', '__main__'])
for key, value in dct.iteritems():
if type(value) != types.FunctionType and key not in filter_names:
if len(value) != 2:
raise NotImplementedError('not support for values that is not 2 elements!')
#Check value[0] duplication.
if value[0] not in val_set:
val_set.add(value[0])
else:
raise KeyError("%s 's key: %s is duplicated!" % (dict([(key, value)]), value[0]))
attrs[key] = value
return attrs, val_set
attrs, val_set = static_attrs()
#Set STATIC_ATTRS to class instance so that can reuse
setattr(cls, 'STATIC_ATTRS', attrs)
setattr(cls, 'static_val_set', val_set)
super(ConstMeta, cls).__init__(name, bases, dct)
def __getattribute__(cls, name):
'''
Rewrite the special function so as to get correct attribute value
'''
static_attrs = object.__getattribute__(cls, 'STATIC_ATTRS')
if name in static_attrs:
return static_attrs[name][0]
return object.__getattribute__(cls, name)
def static_values(cls):
'''
Put values in static attribute into a list, use the function to validate value.
@return: Set of values
'''
return cls.static_val_set
def __getitem__(cls, key):
'''
Rewrite to make syntax SomeConstClass[key] works, and return desc string of related static value.
@return: Desc string of related static value
'''
for k, v in cls.STATIC_ATTRS.iteritems():
if v[0] == key:
return v[1]
raise KeyError('Key: %s does not exists in %s !' % (str(key), repr(cls)))
class Const(object):
'''
Base class for constant class.
@usage:
Definition: (must inherit from Const class!
>>> class SomeConst(Const):
>>> STATUS_NAME_1 = (1, 'desc for the status1')
>>> STATUS_NAME_2 = (2, 'desc for the status2')
Invoke(base upper SomeConst class):
1) SomeConst.STATUS_NAME_1 returns 1
2) SomeConst[1] returns 'desc for the status1'
3) SomeConst.STATIC_ATTRS returns {'STATUS_NAME_1': (1, 'desc for the status1'), 'STATUS_NAME_2': (2, 'desc for the status2')}
4) SomeConst.static_values() returns set([1, 2])
Attention:
SomeCosnt's value 1, 2 can not be duplicated!
If WrongConst is like this, it will raise KeyError:
class WrongConst(Const):
STATUS_NAME_1 = (1, 'desc for the status1')
STATUS_NAME_2 = (1, 'desc for the status2')
'''
__metaclass__ = ConstMeta
##################################################################
#Const Base Class ends
##################################################################
def main():
class STATUS(Const):
ERROR = (-3, '??')
OK = (0, '??')
print STATUS.ERROR
print STATUS.static_values()
print STATUS.STATIC_ATTRS
#Usage sample:
user_input = 1
#Validate input:
print user_input in STATUS.static_values()
#Template render like:
print '<select>'
for key, value in STATUS.STATIC_ATTRS.items():
print '<option value="%s">%s</option>' % (value[0], value[1])
print '</select>'
if __name__ == '__main__':
main()
使用下面的方法。
TYPE = {'EAN13': u'EAN-13',
'CODE39': u'Code 39',
'CODE128': u'Code 128',
'i25': u'Interleaved 2 of 5',}
>>> TYPE.items()
[('EAN13', u'EAN-13'), ('i25', u'Interleaved 2 of 5'), ('CODE39', u'Code 39'), ('CODE128', u'Code 128')]
>>> TYPE.keys()
['EAN13', 'i25', 'CODE39', 'CODE128']
>>> TYPE.values()
[u'EAN-13', u'Interleaved 2 of 5', u'Code 39', u'Code 128']
我用它来选择Django模型,它看起来非常python化。它不是一个真正的Enum,但它完成了这项工作。
def M_add_class_attribs(attribs):
def foo(name, bases, dict_):
for v, k in attribs:
dict_[k] = v
return type(name, bases, dict_)
return foo
def enum(*names):
class Foo(object):
__metaclass__ = M_add_class_attribs(enumerate(names))
def __setattr__(self, name, value): # this makes it read-only
raise NotImplementedError
return Foo()
像这样使用它:
Animal = enum('DOG', 'CAT')
Animal.DOG # returns 0
Animal.CAT # returns 1
Animal.DOG = 2 # raises NotImplementedError
如果你只想要唯一的符号,不关心值,替换这行:
__metaclass__ = M_add_class_attribs(enumerate(names))
用这个:
__metaclass__ = M_add_class_attribs((object(), name) for name in names)
为什么枚举必须是整数?不幸的是,在不改变Python语言的情况下,我想不出任何好看的构造来生成它,所以我将使用字符串:
class Enumerator(object):
def __init__(self, name):
self.name = name
def __eq__(self, other):
if self.name == other:
return True
return self is other
def __ne__(self, other):
if self.name != other:
return False
return self is other
def __repr__(self):
return 'Enumerator({0})'.format(self.name)
def __str__(self):
return self.name
class Enum(object):
def __init__(self, *enumerators):
for e in enumerators:
setattr(self, e, Enumerator(e))
def __getitem__(self, key):
return getattr(self, key)
也许现在更好的是,为了配置文件或其他远程输入,我们可以自然地对字符串进行测试。
例子:
class Cow(object):
State = Enum(
'standing',
'walking',
'eating',
'mooing',
'sleeping',
'dead',
'dying'
)
state = State.standing
In [1]: from enum import Enum
In [2]: c = Cow()
In [3]: c2 = Cow()
In [4]: c.state, c2.state
Out[4]: (Enumerator(standing), Enumerator(standing))
In [5]: c.state == c2.state
Out[5]: True
In [6]: c.State.mooing
Out[6]: Enumerator(mooing)
In [7]: c.State['mooing']
Out[7]: Enumerator(mooing)
In [8]: c.state = Cow.State.dead
In [9]: c.state == c2.state
Out[9]: False
In [10]: c.state == Cow.State.dead
Out[10]: True
In [11]: c.state == 'dead'
Out[11]: True
In [12]: c.state == Cow.State['dead']
Out[11]: True