我主要是c#开发人员,但我目前正在用Python开发一个项目。

我如何在Python中表示等价的Enum ?


当前回答

def M_add_class_attribs(attribs):
    def foo(name, bases, dict_):
        for v, k in attribs:
            dict_[k] = v
        return type(name, bases, dict_)
    return foo

def enum(*names):
    class Foo(object):
        __metaclass__ = M_add_class_attribs(enumerate(names))
        def __setattr__(self, name, value):  # this makes it read-only
            raise NotImplementedError
    return Foo()

像这样使用它:

Animal = enum('DOG', 'CAT')
Animal.DOG # returns 0
Animal.CAT # returns 1
Animal.DOG = 2 # raises NotImplementedError

如果你只想要唯一的符号,不关心值,替换这行:

__metaclass__ = M_add_class_attribs(enumerate(names))

用这个:

__metaclass__ = M_add_class_attribs((object(), name) for name in names)

其他回答

def M_add_class_attribs(attribs):
    def foo(name, bases, dict_):
        for v, k in attribs:
            dict_[k] = v
        return type(name, bases, dict_)
    return foo

def enum(*names):
    class Foo(object):
        __metaclass__ = M_add_class_attribs(enumerate(names))
        def __setattr__(self, name, value):  # this makes it read-only
            raise NotImplementedError
    return Foo()

像这样使用它:

Animal = enum('DOG', 'CAT')
Animal.DOG # returns 0
Animal.CAT # returns 1
Animal.DOG = 2 # raises NotImplementedError

如果你只想要唯一的符号,不关心值,替换这行:

__metaclass__ = M_add_class_attribs(enumerate(names))

用这个:

__metaclass__ = M_add_class_attribs((object(), name) for name in names)

这是我在这里找到的一个很好的Python食谱:http://code.activestate.com/recipes/577024-yet-another-enum-for-python/

def enum(typename, field_names):
    "Create a new enumeration type"

    if isinstance(field_names, str):
        field_names = field_names.replace(',', ' ').split()
    d = dict((reversed(nv) for nv in enumerate(field_names)), __slots__ = ())
    return type(typename, (object,), d)()

使用示例:

STATE = enum('STATE', 'GET_QUIZ, GET_VERSE, TEACH')

更多细节可以在食谱页面上找到。

在Java pre-JDK 5中使用的类型安全枚举模式有一个 优势的数量。就像Alexandru的回答一样,你创建了一个 类和类级别字段是枚举值;然而,枚举 值是类的实例,而不是小整数。这已经 优点是枚举值不会在不经意间比较相等 对于小整数,你可以控制它们的打印方式,任意添加 方法(如果有用的话),并使用isinstance进行断言:

class Animal:
   def __init__(self, name):
       self.name = name

   def __str__(self):
       return self.name

   def __repr__(self):
       return "<Animal: %s>" % self

Animal.DOG = Animal("dog")
Animal.CAT = Animal("cat")

>>> x = Animal.DOG
>>> x
<Animal: dog>
>>> x == 1
False

python-dev上最近的一个线程指出,在野外有几个枚举库,包括:

flufl.enum lazr.enum ... 和富有想象力的enum

Python 2.7和find_name()

下面是所选思想的一个易于阅读的实现,其中包含一些辅助方法,这些方法可能比“reverse_mapping”更python化,使用起来更简洁。要求Python >= 2.7。

为了解决下面的一些注释,枚举对于防止代码中的拼写错误非常有用,例如对于状态机,错误分类器等。

def Enum(*sequential, **named):
  """Generate a new enum type. Usage example:

  ErrorClass = Enum('STOP','GO')
  print ErrorClass.find_name(ErrorClass.STOP)
    = "STOP"
  print ErrorClass.find_val("STOP")
    = 0
  ErrorClass.FOO     # Raises AttributeError
  """
  enums = { v:k for k,v in enumerate(sequential) } if not named else named

  @classmethod
  def find_name(cls, val):
    result = [ k for k,v in cls.__dict__.iteritems() if v == val ]
    if not len(result):
        raise ValueError("Value %s not found in Enum" % val)
    return result[0]

  @classmethod
  def find_val(cls, n):
    return getattr(cls, n)

  enums['find_val'] = find_val
  enums['find_name'] = find_name
  return type('Enum', (), enums)

我用什么:

class Enum(object):
    def __init__(self, names, separator=None):
        self.names = names.split(separator)
        for value, name in enumerate(self.names):
            setattr(self, name.upper(), value)
    def tuples(self):
        return tuple(enumerate(self.names))

使用方法:

>>> state = Enum('draft published retracted')
>>> state.DRAFT
0
>>> state.RETRACTED
2
>>> state.FOO
Traceback (most recent call last):
   File "<stdin>", line 1, in <module>
AttributeError: 'Enum' object has no attribute 'FOO'
>>> state.tuples()
((0, 'draft'), (1, 'published'), (2, 'retracted'))

这就给出了整数常数,比如状态。PUBLISHED和在Django模型中用作选项的二元组。