我主要是c#开发人员,但我目前正在用Python开发一个项目。
我如何在Python中表示等价的Enum ?
我主要是c#开发人员,但我目前正在用Python开发一个项目。
我如何在Python中表示等价的Enum ?
当前回答
def M_add_class_attribs(attribs):
def foo(name, bases, dict_):
for v, k in attribs:
dict_[k] = v
return type(name, bases, dict_)
return foo
def enum(*names):
class Foo(object):
__metaclass__ = M_add_class_attribs(enumerate(names))
def __setattr__(self, name, value): # this makes it read-only
raise NotImplementedError
return Foo()
像这样使用它:
Animal = enum('DOG', 'CAT')
Animal.DOG # returns 0
Animal.CAT # returns 1
Animal.DOG = 2 # raises NotImplementedError
如果你只想要唯一的符号,不关心值,替换这行:
__metaclass__ = M_add_class_attribs(enumerate(names))
用这个:
__metaclass__ = M_add_class_attribs((object(), name) for name in names)
其他回答
另一个非常简单的Python枚举实现,使用namedtuple:
from collections import namedtuple
def enum(*keys):
return namedtuple('Enum', keys)(*keys)
MyEnum = enum('FOO', 'BAR', 'BAZ')
,或者
# With sequential number values
def enum(*keys):
return namedtuple('Enum', keys)(*range(len(keys)))
# From a dict / keyword args
def enum(**kwargs):
return namedtuple('Enum', kwargs.keys())(*kwargs.values())
# Example for dictionary param:
values = {"Salad": 20, "Carrot": 99, "Tomato": "No i'm not"}
Vegetables= enum(**values)
# >>> print(Vegetables.Tomato) 'No i'm not'
# Example for keyworded params:
Fruits = enum(Apple="Steve Jobs", Peach=1, Banana=2)
# >>> print(Fruits.Apple) 'Steve Jobs'
就像上面子类设置的方法一样,这允许:
'FOO' in MyEnum
other = MyEnum.FOO
assert other == MyEnum.FOO
但是具有更大的灵活性,因为它可以有不同的键和值。这允许
MyEnum.FOO < MyEnum.BAR
如果使用填充连续数字值的版本,则按预期操作。
我喜欢使用列表或集合作为枚举。例如:
>>> packet_types = ['INIT', 'FINI', 'RECV', 'SEND']
>>> packet_types.index('INIT')
0
>>> packet_types.index('FINI')
1
>>>
对于旧的Python 2.x
def enum(*sequential, **named):
enums = dict(zip(sequential, [object() for _ in range(len(sequential))]), **named)
return type('Enum', (), enums)
如果你命名它,是你的问题,但如果不创建对象而不是值允许你这样做:
>>> DOG = enum('BARK', 'WALK', 'SIT')
>>> CAT = enum('MEOW', 'WALK', 'SIT')
>>> DOG.WALK == CAT.WALK
False
当使用这里的其他实现时(在我的例子中使用命名实例时),必须确保永远不要尝试比较来自不同枚举的对象。这里有一个可能的陷阱:
>>> DOG = enum('BARK'=1, 'WALK'=2, 'SIT'=3)
>>> CAT = enum('WALK'=1, 'SIT'=2)
>>> pet1_state = DOG.BARK
>>> pet2_state = CAT.WALK
>>> pet1_state == pet2_state
True
呵!
这是我见过的最好的一个:“Python中的First Class Enums”
http://code.activestate.com/recipes/413486/
It gives you a class, and the class contains all the enums. The enums can be compared to each other, but don't have any particular value; you can't use them as an integer value. (I resisted this at first because I am used to C enums, which are integer values. But if you can't use it as an integer, you can't use it as an integer by mistake so overall I think it is a win.) Each enum is a unique value. You can print enums, you can iterate over them, you can test that an enum value is "in" the enum. It's pretty complete and slick.
编辑(cfi):上面的链接不兼容Python 3。下面是我将枚举.py移植到Python 3的端口:
def cmp(a,b):
if a < b: return -1
if b < a: return 1
return 0
def Enum(*names):
##assert names, "Empty enums are not supported" # <- Don't like empty enums? Uncomment!
class EnumClass(object):
__slots__ = names
def __iter__(self): return iter(constants)
def __len__(self): return len(constants)
def __getitem__(self, i): return constants[i]
def __repr__(self): return 'Enum' + str(names)
def __str__(self): return 'enum ' + str(constants)
class EnumValue(object):
__slots__ = ('__value')
def __init__(self, value): self.__value = value
Value = property(lambda self: self.__value)
EnumType = property(lambda self: EnumType)
def __hash__(self): return hash(self.__value)
def __cmp__(self, other):
# C fans might want to remove the following assertion
# to make all enums comparable by ordinal value {;))
assert self.EnumType is other.EnumType, "Only values from the same enum are comparable"
return cmp(self.__value, other.__value)
def __lt__(self, other): return self.__cmp__(other) < 0
def __eq__(self, other): return self.__cmp__(other) == 0
def __invert__(self): return constants[maximum - self.__value]
def __nonzero__(self): return bool(self.__value)
def __repr__(self): return str(names[self.__value])
maximum = len(names) - 1
constants = [None] * len(names)
for i, each in enumerate(names):
val = EnumValue(i)
setattr(EnumClass, each, val)
constants[i] = val
constants = tuple(constants)
EnumType = EnumClass()
return EnumType
if __name__ == '__main__':
print( '\n*** Enum Demo ***')
print( '--- Days of week ---')
Days = Enum('Mo', 'Tu', 'We', 'Th', 'Fr', 'Sa', 'Su')
print( Days)
print( Days.Mo)
print( Days.Fr)
print( Days.Mo < Days.Fr)
print( list(Days))
for each in Days:
print( 'Day:', each)
print( '--- Yes/No ---')
Confirmation = Enum('No', 'Yes')
answer = Confirmation.No
print( 'Your answer is not', ~answer)
我非常喜欢Alec Thomas的解决方案(http://stackoverflow.com/a/1695250):
def enum(**enums):
'''simple constant "enums"'''
return type('Enum', (object,), enums)
它看起来优雅而简洁,但它只是一个创建具有指定属性的类的函数。
通过对函数进行一些修改,我们可以让它表现得更像“枚举”:
注意:我通过尝试重现 pygtk的新样式'enums'的行为(如gtk . messagtype . warning)
def enum_base(t, **enums):
'''enums with a base class'''
T = type('Enum', (t,), {})
for key,val in enums.items():
setattr(T, key, T(val))
return T
这将基于指定类型创建枚举。除了像前面的函数那样提供属性访问外,它的行为与您期望Enum对类型的行为一样。它还继承了基类。
例如,整数enum:
>>> Numbers = enum_base(int, ONE=1, TWO=2, THREE=3)
>>> Numbers.ONE
1
>>> x = Numbers.TWO
>>> 10 + x
12
>>> type(Numbers)
<type 'type'>
>>> type(Numbers.ONE)
<class 'Enum'>
>>> isinstance(x, Numbers)
True
用这个方法还可以做一件有趣的事情,那就是通过覆盖内置方法来定制特定的行为:
def enum_repr(t, **enums):
'''enums with a base class and repr() output'''
class Enum(t):
def __repr__(self):
return '<enum {0} of type Enum({1})>'.format(self._name, t.__name__)
for key,val in enums.items():
i = Enum(val)
i._name = key
setattr(Enum, key, i)
return Enum
>>> Numbers = enum_repr(int, ONE=1, TWO=2, THREE=3)
>>> repr(Numbers.ONE)
'<enum ONE of type Enum(int)>'
>>> str(Numbers.ONE)
'1'