我有一组数字,我需要确保它们是唯一的。我在互联网上找到了下面的代码片段,它工作得很好,直到数组中有一个零。我在Stack Overflow上找到了另一个脚本,看起来几乎与它完全一样,但它不会失败。

所以为了帮助我学习,有人能帮我确定原型脚本哪里出错吗?

Array.prototype.getUnique = function() {
 var o = {}, a = [], i, e;
 for (i = 0; e = this[i]; i++) {o[e] = 1};
 for (e in o) {a.push (e)};
 return a;
}

重复问题的更多答案:

从JS数组中删除重复值

类似的问题:

获取数组中的所有非唯一值(即:重复/多次出现)


当前回答

此脚本修改数组,过滤出重复的值。它适用于数字和字符串。

https://jsfiddle.net/qsdL6y5j/1/

    Array.prototype.getUnique = function () {
        var unique = this.filter(function (elem, pos) {
            return this.indexOf(elem) == pos;
        }.bind(this));
        this.length = 0;
        this.splice(0, 0, unique);
    }

    var duplicates = [0, 0, 1, 1, 2, 3, 1, 1, 0, 4, 4];
    duplicates.getUnique();
    alert(duplicates);

相反,此版本允许您返回具有唯一值的新数组,该值保持原始值(仅传递true)。

https://jsfiddle.net/dj7qxyL7/

    Array.prototype.getUnique = function (createArray) {
        createArray = createArray === true ? true : false;
        var temp = JSON.stringify(this);
        temp = JSON.parse(temp);
        if (createArray) {
            var unique = temp.filter(function (elem, pos) {
                return temp.indexOf(elem) == pos;
            }.bind(this));
            return unique;
        }
        else {
            var unique = this.filter(function (elem, pos) {
                return this.indexOf(elem) == pos;
            }.bind(this));
            this.length = 0;
            this.splice(0, 0, unique);
        }
    }

    var duplicates = [0, 0, 1, 1, 2, 3, 1, 1, 0, 4, 4];
    console.log('++++ ovveride')
    duplicates.getUnique();
    console.log(duplicates);
    console.log('++++ new array')
    var duplicates2 = [0, 0, 1, 1, 2, 3, 1, 1, 0, 4, 4];
    var unique = duplicates2.getUnique(true);
    console.log(unique);
    console.log('++++ original')
    console.log(duplicates2);

Browser support:

Feature Chrome  Firefox (Gecko)     Internet Explorer   Opera   Safari
Basic support   (Yes)   1.5 (1.8)   9                   (Yes)   (Yes)

其他回答

也可以使用jQuery

var a = [1,5,1,6,4,5,2,5,4,3,1,2,6,6,3,3,2,4];

// note: jQuery's filter params are opposite of javascript's native implementation :(
var unique = $.makeArray($(a).filter(function(i,itm){ 
    // note: 'index', not 'indexOf'
    return i == $(a).index(itm);
}));

// unique: [1, 5, 6, 4, 2, 3]

最初的答案是:jQuery函数从数组中获取所有唯一元素?

在ES6/以后

仅获取唯一值

  let a = [
           { id: 1, name: "usman" },
           { id: 2, name: "zia" },
           { id: 3, name: "usman" },
          ];
const unique = [...new Set(a.map((item) => item.name))];
console.log(unique); // ["usman", "zia"]

获取唯一对象

const myObjArray = [
                       { id: 1, name: "usman" },
                       { id: 2, name: "zia" },
                       { id: 3, name: "usman" },
                   ];
// Creates an array of objects with unique "name" property values.
let uniqueObjArray = [
  ...new Map(myObjArray.map((item) => [item["name"], item])).values(),
];

console.log("uniqueObjArray", uniqueObjArray);

如果顺序不重要,那么我们可以创建一个哈希,并获取密钥以创建唯一的数组。

var ar = [1,3,4,5,5,6,5,6,2,1];
var uarEle = {};
links.forEach(function(a){ uarEle[a] = 1; });
var uar = keys(uarEle)

uar将具有唯一的数组元素。

变量数=[1,1,2,3,4,4];函数唯一(dupArray){return dupArray.reduce(函数(上一个,num){if(previous.find(函数(项){返回项==num;})) {返回上一个;}其他{先前推送(num);返回上一个;}}, [])}var check=唯一(数字);console.log(检查);

这个不是纯的,它会修改数组,但这是最快的。如果你的速度更快,请写下评论;)

http://jsperf.com/unique-array-webdeb

Array.prototype.uniq = function(){
    for(var i = 0, l = this.length; i < l; ++i){
        var item = this[i];
        var duplicateIdx = this.indexOf(item, i + 1);
        while(duplicateIdx != -1) {
            this.splice(duplicateIdx, 1);
            duplicateIdx = this.indexOf(item, duplicateIdx);
            l--;
        }
    }

    return this;
}

[
 "",2,4,"A","abc",
 "",2,4,"A","abc",
 "",2,4,"A","abc",
 "",2,4,"A","abc",
 "",2,4,"A","abc",
 "",2,4,"A","abc",
 "",2,4,"A","abc",
 "",2,4,"A","abc"
].uniq() //  ["",2,4,"A","abc"]