stringToArrayBuffer(byteString) {
    var byteArray = new Uint8Array(byteString.length);
    for (var i = 0; i < byteString.length; i++) {
      byteArray[i] = byteString.codePointAt(i);
    }
    return byteArray;
  }
  arrayBufferToString(buffer) {
    var byteArray = new Uint8Array(buffer);
    var byteString = '';
    for (var i = 0; i < byteArray.byteLength; i++) {
      byteString += String.fromCodePoint(byteArray[i]);
    }
    return byteString;
  }

我用了这个，对我很有用。

function arrayBufferToBase64( buffer ) {
    var binary = '';
    var bytes = new Uint8Array( buffer );
    var len = bytes.byteLength;
    for (var i = 0; i < len; i++) {
        binary += String.fromCharCode( bytes[ i ] );
    }
    return window.btoa( binary );
}



function base64ToArrayBuffer(base64) {
    var binary_string =  window.atob(base64);
    var len = binary_string.length;
    var bytes = new Uint8Array( len );
    for (var i = 0; i < len; i++)        {
        bytes[i] = binary_string.charCodeAt(i);
    }
    return bytes.buffer;
}

下面是一个Typescript的工作实现:

bufferToString(buffer: ArrayBuffer): string {
    return String.fromCharCode.apply(null, Array.from(new Uint16Array(buffer)));
}

stringToBuffer(value: string): ArrayBuffer {
    let buffer = new ArrayBuffer(value.length * 2); // 2 bytes per char
    let view = new Uint16Array(buffer);
    for (let i = 0, length = value.length; i < length; i++) {
        view[i] = value.charCodeAt(i);
    }
    return buffer;
}

在使用crypt .subtle时，我已经使用它进行了许多操作。

Blob比String.fromCharCode(null,array)慢得多;

但如果数组缓冲区太大，就会失败。我发现的最佳解决方案是使用String.fromCharCode(null，数组);并将其拆分为不会破坏堆栈的操作，但每次比单个char更快。

大数组缓冲区的最佳解决方案是:

function arrayBufferToString(buffer){

    var bufView = new Uint16Array(buffer);
    var length = bufView.length;
    var result = '';
    var addition = Math.pow(2,16)-1;

    for(var i = 0;i<length;i+=addition){

        if(i + addition > length){
            addition = length - i;
        }
        result += String.fromCharCode.apply(null, bufView.subarray(i,i+addition));
    }

    return result;

}

我发现这比使用blob快20倍。它也适用于超过100mb的大字符串。

atob()返回的“本机”二进制字符串是一个每个字符1字节的数组。

所以我们不应该在一个字符中存储2个字节。

var arrayBufferToString = function(buffer) {
  return String.fromCharCode.apply(null, new Uint8Array(buffer));
}

var stringToArrayBuffer = function(str) {
  return (new Uint8Array([].map.call(str,function(x){return x.charCodeAt(0)}))).buffer;
}

Just

const buffer = thisReturnsBuffers();

const blob = new Blob([buffer], {type: 'text/plain; charset=utf-8'});

blob.text().then(text => console.log(text));

Or

const stringVal = "string here";

const blob = new Blob([stringVal], {type: 'text/plain; charset=utf-8'});

blob.arrayBuffer().then(buffer => console.log(buffer));

你们为什么要把事情搞得这么复杂?