您可以在公共表表达式中使用ROW_NUMBER来实现这一点。

;WITH My_CTE AS
(
     SELECT
          col1,
          col2,
          ROW_NUMBER() OVER(ORDER BY col1) AS row_number
     FROM
          My_Table
     WHERE
          <<<whatever>>>
)
SELECT
     col1,
     col2
FROM
     My_CTE
WHERE
     row_number BETWEEN @start_row AND @end_row

@nombre_row :nombre ligne par page  
@page:numero de la page

//--------------code sql---------------

declare  @page int,@nombre_row int;
    set @page='2';
    set @nombre_row=5;
    SELECT  *
FROM    ( SELECT    ROW_NUMBER() OVER ( ORDER BY etudiant_ID ) AS RowNum, *
      FROM      etudiant

    ) AS RowConstrainedResult
WHERE   RowNum >= ((@page-1)*@nombre_row)+1
    AND RowNum < ((@page)*@nombre_row)+1
ORDER BY RowNum

因为还没有人提供这个代码:

SELECT TOP @limit f1, f2, f3...
FROM t1
WHERE c1 = v1, c2 > v2...
AND
    t1.id NOT IN
        (SELECT TOP @offset id
         FROM t1
         WHERE c1 = v1, c2 > v2...
         ORDER BY o1, o2...)
ORDER BY o1, o2...

重要的几点:

ORDER BY必须相同 @limit可以替换为检索结果的数量， @offset是要跳过的结果数 请将性能与以前的解决方案进行比较，因为它们可能更有效 这个解决方案重复了where和order by子句，如果它们不同步，将提供不正确的结果 另一方面，如果需要的话，order by是明确存在的

特别是对于SQL-SERVER，您可以通过许多不同的方式实现这一点。对于给定的真实例子，我们取Customer表。

例1:使用"SET ROWCOUNT"

SET ROWCOUNT 10
SELECT CustomerID, CompanyName from Customers
ORDER BY CompanyName

若要返回所有行，请将ROWCOUNT设置为0

SET ROWCOUNT 0  
SELECT CustomerID, CompanyName from Customers
    ORDER BY CompanyName

例2:使用"ROW_NUMBER and OVER"

With Cust AS
( SELECT CustomerID, CompanyName,
ROW_NUMBER() OVER (order by CompanyName) as RowNumber 
FROM Customers )
select *
from Cust
Where RowNumber Between 0 and 10

例3:使用“OFFSET and FETCH”，但是使用这个“ORDER BY”是强制的

SELECT CustomerID, CompanyName FROM Customers
ORDER BY CompanyName
OFFSET 0 ROWS
FETCH NEXT 10 ROWS ONLY

希望这对你有所帮助。

另一个例子:

declare @limit int 
declare @offset int 
set @offset = 2;
set @limit = 20;
declare @count int
declare @idxini int 
declare @idxfim int 
select @idxfim = @offset * @limit
select @idxini = @idxfim - (@limit-1);
WITH paging AS
    (
        SELECT 
             ROW_NUMBER() OVER (order by object_id) AS rowid, *
        FROM 
            sys.objects 
    )
select *
    from 
        (select COUNT(1) as rowqtd from paging) qtd, 
            paging 
    where 
        rowid between @idxini and @idxfim
    order by 
        rowid;

详细阐述Somnath-Muluk的回答:

SELECT *
FROM table_name_here
ORDER BY (SELECT NULL AS NOORDER)
OFFSET 9 ROWS 
FETCH NEXT 25 ROWS ONLY 

W /o添加任何额外的列。 在SQL Server 2019中测试，但我猜也可以在旧的版本中工作。