因为还没有人提供这个代码:

SELECT TOP @limit f1, f2, f3...
FROM t1
WHERE c1 = v1, c2 > v2...
AND
    t1.id NOT IN
        (SELECT TOP @offset id
         FROM t1
         WHERE c1 = v1, c2 > v2...
         ORDER BY o1, o2...)
ORDER BY o1, o2...

重要的几点:

ORDER BY必须相同 @limit可以替换为检索结果的数量， @offset是要跳过的结果数 请将性能与以前的解决方案进行比较，因为它们可能更有效 这个解决方案重复了where和order by子句，如果它们不同步，将提供不正确的结果 另一方面，如果需要的话，order by是明确存在的

在SQL server中，你可以使用TOP和ROW_NUMBER()

另一个例子:

declare @limit int 
declare @offset int 
set @offset = 2;
set @limit = 20;
declare @count int
declare @idxini int 
declare @idxfim int 
select @idxfim = @offset * @limit
select @idxini = @idxfim - (@limit-1);
WITH paging AS
    (
        SELECT 
             ROW_NUMBER() OVER (order by object_id) AS rowid, *
        FROM 
            sys.objects 
    )
select *
    from 
        (select COUNT(1) as rowqtd from paging) qtd, 
            paging 
    where 
        rowid between @idxini and @idxfim
    order by 
        rowid;

我能做到的最接近

select * FROM( SELECT *, ROW_NUMBER() over (ORDER BY ID ) as ct from [db].[dbo].[table] ) sub where ct > fromNumber  and ct <= toNumber

我猜类似于select * from [db].[dbo]。[table] LIMIT 0,10

select top (@TakeCount) * --FETCH NEXT
from(
    Select  ROW_NUMBER() OVER (order by StartDate) AS rowid,*
    From YourTable
)A
where Rowid>@SkipCount --OFFSET

对我来说，一起使用OFFSET和FETCH很慢，所以我使用了TOP和OFFSET的组合，就像这样(这更快):

SELECT TOP 20 * FROM (SELECT columname1, columname2 FROM tablename
    WHERE <conditions...> ORDER BY columname1 OFFSET 100 ROWS) aliasname

注意:如果在同一个查询中同时使用TOP和OFFSET:

SELECT TOP 20 columname1, columname2 FROM tablename
    WHERE <conditions...> ORDER BY columname1 OFFSET 100 ROWS

然后你会得到一个错误，所以为了同时使用TOP和OFFSET，你需要用子查询来分离它。

如果你需要使用SELECT DISTINCT，那么查询如下:

SELECT TOP 20 FROM (SELECT DISTINCT columname1, columname2
    WHERE <conditions...> ORDER BY columname1 OFFSET 100 ROWS) aliasname

注意:使用SELECT ROW_NUMBER和DISTINCT不适合我。