接受的答案返回发现的元素或多或少是无序的，方法是尽可能深入地跟随第一个子分支，同时在返回和重复尚未解析的树枝的步骤之前，沿途生成发现的元素。

如果你需要按降序排列的后代元素，其中直接的子元素将首先产生，然后是它们的子元素，依此类推，下面的算法将工作:

public static IEnumerable<T> GetVisualDescendants<T>(DependencyObject parent, bool applyTemplates = false)
    where T : DependencyObject
{
    if (parent == null || !(child is Visual || child is Visual3D))
        yield break;

    var descendants = new Queue<DependencyObject>();
    descendants.Enqueue(parent);

    while (descendants.Count > 0)
    {
        var currentDescendant = descendants.Dequeue();

        if (applyTemplates)
            (currentDescendant as FrameworkElement)?.ApplyTemplate();

        for (var i = 0; i < VisualTreeHelper.GetChildrenCount(currentDescendant); i++)
        {
            var child = VisualTreeHelper.GetChild(currentDescendant, i);

            if (child is Visual || child is Visual3D)
                descendants.Enqueue(child);

            if (child is T foundObject)
                yield return foundObject;
        }
    }
}

生成的元素将从最近到最远进行排序。 这将是有用的，例如，如果你正在寻找某种类型和条件的最近的子元素:

var foundElement = GetDescendants<StackPanel>(someElement)
                       .FirstOrDefault(o => o.SomeProperty == SomeState);

我的c++ /CLI版本

template < class T, class U >
bool Isinst(U u) 
{
    return dynamic_cast< T >(u) != nullptr;
}

template <typename T>
    T FindVisualChildByType(Windows::UI::Xaml::DependencyObject^ element, Platform::String^ name)
    {
        if (Isinst<T>(element) && dynamic_cast<Windows::UI::Xaml::FrameworkElement^>(element)->Name == name)
        {
            return dynamic_cast<T>(element);
        }
        int childcount = Windows::UI::Xaml::Media::VisualTreeHelper::GetChildrenCount(element);
        for (int i = 0; i < childcount; ++i)
        {
            auto childElement = FindVisualChildByType<T>(Windows::UI::Xaml::Media::VisualTreeHelper::GetChild(element, i), name);
            if (childElement != nullptr)
            {
                return childElement;
            }
        }
        return nullptr;
    };

我发现没有Visual Tree Helpers更容易:

foreach (UIElement element in MainWindow.Children) {
    if (element is TextBox) { 
        if ((element as TextBox).Text != "")
        {
            //Do something
        }
    }
};

I wanted to add a comment but I have less than 50 pts so I can only "Answer". Be aware that if you use the "VisualTreeHelper" method to retrieve XAML "TextBlock" objects then it will also grab XAML "Button" objects. If you re-initialize the "TextBlock" object by writing to the Textblock.Text parameter then you will no longer be able to change the Button text using the Button.Content parameter. The Button will permanently show the text written to it from the Textblock.Text write action (from when it was retrieved --

foreach (TextBlock tb in FindVisualChildren<TextBlock>(window))
{
// do something with tb here
   tb.Text = ""; //this will overwrite Button.Content and render the 
                 //Button.Content{set} permanently disabled.
}

要解决这个问题，您可以尝试使用XAML“文本框”并添加方法(或事件)来模拟XAMAL按钮。XAML“TextBox”不是通过搜索“TextBlock”收集的。

请注意，使用VisualTreeHelper仅适用于派生自Visual或Visual3D的控件。如果你还需要检查其他元素(例如TextBlock, FlowDocument等)，使用VisualTreeHelper将抛出一个异常。

如果有必要，这里有一个回到逻辑树的替代方案:

http://www.hardcodet.net/2009/06/finding-elements-in-wpf-tree-both-ways

下面是另一个紧凑的版本，使用泛型语法:

    public static IEnumerable<T> FindLogicalChildren<T>(DependencyObject obj) where T : DependencyObject
    {
        if (obj != null) {
            if (obj is T)
                yield return obj as T;

            foreach (DependencyObject child in LogicalTreeHelper.GetChildren(obj).OfType<DependencyObject>()) 
                foreach (T c in FindLogicalChildren<T>(child)) 
                    yield return c;
        }
    }