我是一个老派的MySQL用户,总是更喜欢JOIN而不是子查询。但是现在每个人都用子查询,我讨厌它;我不知道为什么。
我缺乏理论知识来判断是否有任何不同。子查询是否与JOIN一样好,因此没有什么可担心的?
我是一个老派的MySQL用户,总是更喜欢JOIN而不是子查询。但是现在每个人都用子查询,我讨厌它;我不知道为什么。
我缺乏理论知识来判断是否有任何不同。子查询是否与JOIN一样好,因此没有什么可担心的?
当前回答
如果你想用join加速你的查询:
对于“inner join/join”, 不要使用where条件,而是使用“ON”条件。 例如:
select id,name from table1 a
join table2 b on a.name=b.name
where id='123'
Try,
select id,name from table1 a
join table2 b on a.name=b.name and a.id='123'
对于“左/右连接”, 不要在“ON”条件下使用,因为如果你使用左/右连接,它将获得任何一个表的所有行。所以,在"开"里也没用。所以,尝试使用“Where”条件
其他回答
子查询能够动态地计算聚合函数。 例如,找到这本书的最低价格,并得到所有以这个价格出售的书。 1)使用子查询:
SELECT titles, price
FROM Books, Orders
WHERE price =
(SELECT MIN(price)
FROM Orders) AND (Books.ID=Orders.ID);
2)使用join
SELECT MIN(price)
FROM Orders;
-----------------
2.99
SELECT titles, price
FROM Books b
INNER JOIN Orders o
ON b.ID = o.ID
WHERE o.price = 2.99;
MSDN文档SQL Server说
Many Transact-SQL statements that include subqueries can be alternatively formulated as joins. Other questions can be posed only with subqueries. In Transact-SQL, there is usually no performance difference between a statement that includes a subquery and a semantically equivalent version that does not. However, in some cases where existence must be checked, a join yields better performance. Otherwise, the nested query must be processed for each result of the outer query to ensure elimination of duplicates. In such cases, a join approach would yield better results.
所以如果你需要
select * from t1 where exists select * from t2 where t2.parent=t1.id
尝试使用join代替。在其他情况下,这没有什么区别。
我说:为子查询创建函数可以消除混乱的问题,并允许您为子查询实现额外的逻辑。因此,我建议尽可能为子查询创建函数。
代码中的混乱是一个大问题,几十年来业界一直在努力避免它。
MySQL版本:5.5.28-0ubuntu0.12.04.2-log
在我的印象中,JOIN总是比MySQL中的子查询更好,但EXPLAIN是更好的判断方式。下面是一个子查询比join更好的例子。
这是我的查询与3个子查询:
EXPLAIN SELECT vrl.list_id,vrl.ontology_id,vrl.position,l.name AS list_name, vrlih.position AS previous_position, vrl.moved_date
FROM `vote-ranked-listory` vrl
INNER JOIN lists l ON l.list_id = vrl.list_id
INNER JOIN `vote-ranked-list-item-history` vrlih ON vrl.list_id = vrlih.list_id AND vrl.ontology_id=vrlih.ontology_id AND vrlih.type='PREVIOUS_POSITION'
INNER JOIN list_burial_state lbs ON lbs.list_id = vrl.list_id AND lbs.burial_score < 0.5
WHERE vrl.position <= 15 AND l.status='ACTIVE' AND l.is_public=1 AND vrl.ontology_id < 1000000000
AND (SELECT list_id FROM list_tag WHERE list_id=l.list_id AND tag_id=43) IS NULL
AND (SELECT list_id FROM list_tag WHERE list_id=l.list_id AND tag_id=55) IS NULL
AND (SELECT list_id FROM list_tag WHERE list_id=l.list_id AND tag_id=246403) IS NOT NULL
ORDER BY vrl.moved_date DESC LIMIT 200;
解释说明:
+----+--------------------+----------+--------+-----------------------------------------------------+--------------+---------+-------------------------------------------------+------+--------------------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+--------------------+----------+--------+-----------------------------------------------------+--------------+---------+-------------------------------------------------+------+--------------------------+
| 1 | PRIMARY | vrl | index | PRIMARY | moved_date | 8 | NULL | 200 | Using where |
| 1 | PRIMARY | l | eq_ref | PRIMARY,status,ispublic,idx_lookup,is_public_status | PRIMARY | 4 | ranker.vrl.list_id | 1 | Using where |
| 1 | PRIMARY | vrlih | eq_ref | PRIMARY | PRIMARY | 9 | ranker.vrl.list_id,ranker.vrl.ontology_id,const | 1 | Using where |
| 1 | PRIMARY | lbs | eq_ref | PRIMARY,idx_list_burial_state,burial_score | PRIMARY | 4 | ranker.vrl.list_id | 1 | Using where |
| 4 | DEPENDENT SUBQUERY | list_tag | ref | list_tag_key,list_id,tag_id | list_tag_key | 9 | ranker.l.list_id,const | 1 | Using where; Using index |
| 3 | DEPENDENT SUBQUERY | list_tag | ref | list_tag_key,list_id,tag_id | list_tag_key | 9 | ranker.l.list_id,const | 1 | Using where; Using index |
| 2 | DEPENDENT SUBQUERY | list_tag | ref | list_tag_key,list_id,tag_id | list_tag_key | 9 | ranker.l.list_id,const | 1 | Using where; Using index |
+----+--------------------+----------+--------+-----------------------------------------------------+--------------+---------+-------------------------------------------------+------+--------------------------+
使用join的相同查询是:
EXPLAIN SELECT vrl.list_id,vrl.ontology_id,vrl.position,l.name AS list_name, vrlih.position AS previous_position, vrl.moved_date
FROM `vote-ranked-listory` vrl
INNER JOIN lists l ON l.list_id = vrl.list_id
INNER JOIN `vote-ranked-list-item-history` vrlih ON vrl.list_id = vrlih.list_id AND vrl.ontology_id=vrlih.ontology_id AND vrlih.type='PREVIOUS_POSITION'
INNER JOIN list_burial_state lbs ON lbs.list_id = vrl.list_id AND lbs.burial_score < 0.5
LEFT JOIN list_tag lt1 ON lt1.list_id = vrl.list_id AND lt1.tag_id = 43
LEFT JOIN list_tag lt2 ON lt2.list_id = vrl.list_id AND lt2.tag_id = 55
INNER JOIN list_tag lt3 ON lt3.list_id = vrl.list_id AND lt3.tag_id = 246403
WHERE vrl.position <= 15 AND l.status='ACTIVE' AND l.is_public=1 AND vrl.ontology_id < 1000000000
AND lt1.list_id IS NULL AND lt2.tag_id IS NULL
ORDER BY vrl.moved_date DESC LIMIT 200;
输出为:
+----+-------------+-------+--------+-----------------------------------------------------+--------------+---------+---------------------------------------------+------+----------------------------------------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+-------------+-------+--------+-----------------------------------------------------+--------------+---------+---------------------------------------------+------+----------------------------------------------+
| 1 | SIMPLE | lt3 | ref | list_tag_key,list_id,tag_id | tag_id | 5 | const | 2386 | Using where; Using temporary; Using filesort |
| 1 | SIMPLE | l | eq_ref | PRIMARY,status,ispublic,idx_lookup,is_public_status | PRIMARY | 4 | ranker.lt3.list_id | 1 | Using where |
| 1 | SIMPLE | vrlih | ref | PRIMARY | PRIMARY | 4 | ranker.lt3.list_id | 103 | Using where |
| 1 | SIMPLE | vrl | ref | PRIMARY | PRIMARY | 8 | ranker.lt3.list_id,ranker.vrlih.ontology_id | 65 | Using where |
| 1 | SIMPLE | lt1 | ref | list_tag_key,list_id,tag_id | list_tag_key | 9 | ranker.lt3.list_id,const | 1 | Using where; Using index; Not exists |
| 1 | SIMPLE | lbs | eq_ref | PRIMARY,idx_list_burial_state,burial_score | PRIMARY | 4 | ranker.vrl.list_id | 1 | Using where |
| 1 | SIMPLE | lt2 | ref | list_tag_key,list_id,tag_id | list_tag_key | 9 | ranker.lt3.list_id,const | 1 | Using where; Using index |
+----+-------------+-------+--------+-----------------------------------------------------+--------------+---------+---------------------------------------------+------+----------------------------------------------+
rows列的比较表明了差异,使用join的查询使用的是using temporary;使用filesort。
当然,当我运行这两个查询时,第一个查询在0.02秒内完成,第二个查询甚至在1分钟后都没有完成,所以EXPLAIN正确地解释了这些查询。
如果我在list_tag表上没有INNER JOIN,即如果我删除
AND (SELECT list_id FROM list_tag WHERE list_id=l.list_id AND tag_id=246403) IS NOT NULL
从第一个查询和相应的:
INNER JOIN list_tag lt3 ON lt3.list_id = vrl.list_id AND lt3.tag_id = 246403
从第二个查询开始,那么EXPLAIN为两个查询返回相同的行数,并且这两个查询的运行速度相同。
我认为在引用的答案中没有强调的是重复的问题和可能由特定(使用)案例引起的有问题的结果。
(尽管马塞洛·坎托斯提到过)
我将引用斯坦福大学Lagunita SQL课程的例子。
学生表
+------+--------+------+--------+
| sID | sName | GPA | sizeHS |
+------+--------+------+--------+
| 123 | Amy | 3.9 | 1000 |
| 234 | Bob | 3.6 | 1500 |
| 345 | Craig | 3.5 | 500 |
| 456 | Doris | 3.9 | 1000 |
| 567 | Edward | 2.9 | 2000 |
| 678 | Fay | 3.8 | 200 |
| 789 | Gary | 3.4 | 800 |
| 987 | Helen | 3.7 | 800 |
| 876 | Irene | 3.9 | 400 |
| 765 | Jay | 2.9 | 1500 |
| 654 | Amy | 3.9 | 1000 |
| 543 | Craig | 3.4 | 2000 |
+------+--------+------+--------+
应用表
(向特定大学及专业申请)
+------+----------+----------------+----------+
| sID | cName | major | decision |
+------+----------+----------------+----------+
| 123 | Stanford | CS | Y |
| 123 | Stanford | EE | N |
| 123 | Berkeley | CS | Y |
| 123 | Cornell | EE | Y |
| 234 | Berkeley | biology | N |
| 345 | MIT | bioengineering | Y |
| 345 | Cornell | bioengineering | N |
| 345 | Cornell | CS | Y |
| 345 | Cornell | EE | N |
| 678 | Stanford | history | Y |
| 987 | Stanford | CS | Y |
| 987 | Berkeley | CS | Y |
| 876 | Stanford | CS | N |
| 876 | MIT | biology | Y |
| 876 | MIT | marine biology | N |
| 765 | Stanford | history | Y |
| 765 | Cornell | history | N |
| 765 | Cornell | psychology | Y |
| 543 | MIT | CS | N |
+------+----------+----------------+----------+
让我们试着找出申请计算机科学专业的学生的平均绩点(不论大学)
使用子查询:
select GPA from Student where sID in (select sID from Apply where major = 'CS');
+------+
| GPA |
+------+
| 3.9 |
| 3.5 |
| 3.7 |
| 3.9 |
| 3.4 |
+------+
这个结果集的平均值是:
select avg(GPA) from Student where sID in (select sID from Apply where major = 'CS');
+--------------------+
| avg(GPA) |
+--------------------+
| 3.6800000000000006 |
+--------------------+
使用连接:
select GPA from Student, Apply where Student.sID = Apply.sID and Apply.major = 'CS';
+------+
| GPA |
+------+
| 3.9 |
| 3.9 |
| 3.5 |
| 3.7 |
| 3.7 |
| 3.9 |
| 3.4 |
+------+
该结果集的平均值:
select avg(GPA) from Student, Apply where Student.sID = Apply.sID and Apply.major = 'CS';
+-------------------+
| avg(GPA) |
+-------------------+
| 3.714285714285714 |
+-------------------+
It is obvious that the second attempt yields misleading results in our use case, given that it counts duplicates for the computation of the average value. It is also evident that usage of distinct with the join - based statement will not eliminate the problem, given that it will erroneously keep one out of three occurrences of the 3.9 score. The correct case is to account for TWO (2) occurrences of the 3.9 score given that we actually have TWO (2) students with that score that comply with our query criteria.
在某些情况下,除了性能问题,子查询似乎是最安全的方法。
只有当第二个连接表的数据明显多于主表时,才会出现这种差异。我有过这样的经历……
我们有一个用户表,有10万个条目,他们的会员数据(友谊)大约有30万个条目。这是一个join语句,目的是获取好友及其数据,但有很大的延迟。但是当成员表中只有少量数据时,它工作得很好。一旦我们将其更改为使用子查询,它就可以正常工作。
但与此同时,连接查询正在处理比主表拥有更少条目的其他表。
所以我认为连接和子查询语句工作得很好,这取决于数据和情况。