我如何得到:
id Name Value
1 A 4
1 B 8
2 C 9
to
id Column
1 A:4, B:8
2 C:9
我如何得到:
id Name Value
1 A 4
1 B 8
2 C 9
to
id Column
1 A:4, B:8
2 C:9
当前回答
这类问题在这里经常被问到,解决方案将在很大程度上取决于潜在的需求:
https://stackoverflow.com/search?q=sql+pivot
and
https://stackoverflow.com/search?q=sql+concatenate
通常,如果没有动态sql、用户定义函数或游标,就没有仅使用sql的方法来完成此任务。
其他回答
不需要光标…while循环就足够了。
------------------------------
-- Setup
------------------------------
DECLARE @Source TABLE
(
id int,
Name varchar(30),
Value int
)
DECLARE @Target TABLE
(
id int,
Result varchar(max)
)
INSERT INTO @Source(id, Name, Value) SELECT 1, 'A', 4
INSERT INTO @Source(id, Name, Value) SELECT 1, 'B', 8
INSERT INTO @Source(id, Name, Value) SELECT 2, 'C', 9
------------------------------
-- Technique
------------------------------
INSERT INTO @Target (id)
SELECT id
FROM @Source
GROUP BY id
DECLARE @id int, @Result varchar(max)
SET @id = (SELECT MIN(id) FROM @Target)
WHILE @id is not null
BEGIN
SET @Result = null
SELECT @Result =
CASE
WHEN @Result is null
THEN ''
ELSE @Result + ', '
END + s.Name + ':' + convert(varchar(30),s.Value)
FROM @Source s
WHERE id = @id
UPDATE @Target
SET Result = @Result
WHERE id = @id
SET @id = (SELECT MIN(id) FROM @Target WHERE @id < id)
END
SELECT *
FROM @Target
我使用了这种方法,可能更容易掌握。获取一个根元素,然后连接到具有相同ID但不是“正式”名称的选项
Declare @IdxList as Table(id int, choices varchar(max),AisName varchar(255))
Insert into @IdxLIst(id,choices,AisName)
Select IdxId,''''+Max(Title)+'''',Max(Title) From [dbo].[dta_Alias]
where IdxId is not null group by IdxId
Update @IdxLIst
set choices=choices +','''+Title+''''
From @IdxLIst JOIN [dta_Alias] ON id=IdxId And Title <> AisName
where IdxId is not null
Select * from @IdxList where choices like '%,%'
我想对所有的医护人员说:
SELECT
s.NOTE_ID
,STUFF ((
SELECT
[note_text] + ' '
FROM
HNO_NOTE_TEXT s1
WHERE
(s1.NOTE_ID = s.NOTE_ID)
ORDER BY [line] ASC
FOR XML PATH(''),TYPE).value('(./text())[1]','VARCHAR(MAX)')
,
1,
2,
'') AS NOTE_TEXT_CONCATINATED
FROM
HNO_NOTE_TEXT s
GROUP BY NOTE_ID
不需要游标,WHILE循环或用户定义函数。
只需要创造性地使用FOR XML和PATH。
[注意:此解决方案仅适用于SQL 2005及更高版本。原来的问题没有指定使用的版本。
CREATE TABLE #YourTable ([ID] INT, [Name] CHAR(1), [Value] INT)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (1,'A',4)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (1,'B',8)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (2,'C',9)
SELECT
[ID],
STUFF((
SELECT ', ' + [Name] + ':' + CAST([Value] AS VARCHAR(MAX))
FROM #YourTable
WHERE (ID = Results.ID)
FOR XML PATH(''),TYPE).value('(./text())[1]','VARCHAR(MAX)')
,1,2,'') AS NameValues
FROM #YourTable Results
GROUP BY ID
DROP TABLE #YourTable
一个例子是
在Oracle中可以使用LISTAGG聚合函数。
原始记录
name type
------------
name1 type1
name2 type2
name2 type3
Sql
SELECT name, LISTAGG(type, '; ') WITHIN GROUP(ORDER BY name)
FROM table
GROUP BY name
导致
name type
------------
name1 type1
name2 type2; type3