我如何得到:

id       Name       Value
1          A          4
1          B          8
2          C          9

to

id          Column
1          A:4, B:8
2          C:9

当前回答

如果group by只包含一个项目,您可以通过以下方式显著提高性能:

SELECT 
  [ID],

CASE WHEN MAX( [Name]) = MIN( [Name]) THEN 
MAX( [Name]) NameValues
ELSE

  STUFF((
    SELECT ', ' + [Name] + ':' + CAST([Value] AS VARCHAR(MAX)) 
    FROM #YourTable 
    WHERE (ID = Results.ID) 
    FOR XML PATH(''),TYPE).value('(./text())[1]','VARCHAR(MAX)')
  ,1,2,'') AS NameValues

END

FROM #YourTable Results
GROUP BY ID

其他回答

只是补充一下Cade所说的,这通常是一个前端显示的事情,因此应该在那里处理。我知道有时候100%用SQL编写文件导出或其他“仅SQL”解决方案更容易,但大多数时候这种连接应该在显示层中处理。

不需要光标…while循环就足够了。

------------------------------
-- Setup
------------------------------

DECLARE @Source TABLE
(
  id int,
  Name varchar(30),
  Value int
)

DECLARE @Target TABLE
(
  id int,
  Result varchar(max) 
)


INSERT INTO @Source(id, Name, Value) SELECT 1, 'A', 4
INSERT INTO @Source(id, Name, Value) SELECT 1, 'B', 8
INSERT INTO @Source(id, Name, Value) SELECT 2, 'C', 9


------------------------------
-- Technique
------------------------------

INSERT INTO @Target (id)
SELECT id
FROM @Source
GROUP BY id

DECLARE @id int, @Result varchar(max)
SET @id = (SELECT MIN(id) FROM @Target)

WHILE @id is not null
BEGIN
  SET @Result = null

  SELECT @Result =
    CASE
      WHEN @Result is null
      THEN ''
      ELSE @Result + ', '
    END + s.Name + ':' + convert(varchar(30),s.Value)
  FROM @Source s
  WHERE id = @id

  UPDATE @Target
  SET Result = @Result
  WHERE id = @id

  SET @id = (SELECT MIN(id) FROM @Target WHERE @id < id)
END

SELECT *
FROM @Target

让我们变得非常简单:

SELECT stuff(
    (
    select ', ' + x from (SELECT 'xxx' x union select 'yyyy') tb 
    FOR XML PATH('')
    )
, 1, 2, '')

替换这一行:

select ', ' + x from (SELECT 'xxx' x union select 'yyyy') tb

你的疑问。

如果是SQL Server 2017或SQL Server Vnext, SQL Azure,您可以使用STRING_AGG如下所示:

SELECT id, STRING_AGG(CONCAT(name, ':', [value]), ', ')
FROM #YourTable 
GROUP BY id

我想对所有的医护人员说:

 
SELECT
s.NOTE_ID
,STUFF ((
        SELECT
           [note_text] + ' ' 
        FROM
            HNO_NOTE_TEXT s1
        WHERE
            (s1.NOTE_ID = s.NOTE_ID)
        ORDER BY [line] ASC
         FOR XML PATH(''),TYPE).value('(./text())[1]','VARCHAR(MAX)')
         ,
        1,
        2,
        '') AS NOTE_TEXT_CONCATINATED
FROM
    HNO_NOTE_TEXT s
    GROUP BY NOTE_ID