我如何得到:

id       Name       Value
1          A          4
1          B          8
2          C          9

to

id          Column
1          A:4, B:8
2          C:9

当前回答

另一个不带垃圾的例子:",TYPE).value('(./text())[1]','VARCHAR(MAX)')"

WITH t AS (
    SELECT 1 n, 1 g, 1 v
    UNION ALL 
    SELECT 2 n, 1 g, 2 v
    UNION ALL 
    SELECT 3 n, 2 g, 3 v
)
SELECT g
        , STUFF (
                (
                    SELECT ', ' + CAST(v AS VARCHAR(MAX))
                    FROM t sub_t
                    WHERE sub_t.g = main_t.g
                    FOR XML PATH('')
                )
                , 1, 2, ''
        ) cg
FROM t main_t
GROUP BY g

输入-输出是

*************************   ->  *********************
*   n   *   g   *   v   *       *   g   *   cg      *
*   -   *   -   *   -   *       *   -   *   -       *
*   1   *   1   *   1   *       *   1   *   1, 2    *
*   2   *   1   *   2   *       *   2   *   3       *
*   3   *   2   *   3   *       *********************
*************************   

其他回答

当我尝试将Kevin Fairchild的建议转换为使用包含空格和编码的特殊XML字符(&,<,>)的字符串时,遇到了几个问题。

我的代码的最终版本(它没有回答最初的问题,但可能对某些人有用)看起来像这样:

CREATE TABLE #YourTable ([ID] INT, [Name] VARCHAR(MAX), [Value] INT)

INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (1,'Oranges & Lemons',4)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (1,'1 < 2',8)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (2,'C',9)

SELECT  [ID],
  STUFF((
    SELECT ', ' + CAST([Name] AS VARCHAR(MAX))
    FROM #YourTable WHERE (ID = Results.ID) 
    FOR XML PATH(''),TYPE 
     /* Use .value to uncomment XML entities e.g. &gt; &lt; etc*/
    ).value('.','VARCHAR(MAX)') 
  ,1,2,'') as NameValues
FROM    #YourTable Results
GROUP BY ID

DROP TABLE #YourTable

它没有使用空格作为分隔符并将所有空格替换为逗号,而是在每个值前附加一个逗号和空格,然后使用STUFF删除前两个字符。

XML编码由TYPE指令自动处理。

另一个不带垃圾的例子:",TYPE).value('(./text())[1]','VARCHAR(MAX)')"

WITH t AS (
    SELECT 1 n, 1 g, 1 v
    UNION ALL 
    SELECT 2 n, 1 g, 2 v
    UNION ALL 
    SELECT 3 n, 2 g, 3 v
)
SELECT g
        , STUFF (
                (
                    SELECT ', ' + CAST(v AS VARCHAR(MAX))
                    FROM t sub_t
                    WHERE sub_t.g = main_t.g
                    FOR XML PATH('')
                )
                , 1, 2, ''
        ) cg
FROM t main_t
GROUP BY g

输入-输出是

*************************   ->  *********************
*   n   *   g   *   v   *       *   g   *   cg      *
*   -   *   -   *   -   *       *   -   *   -       *
*   1   *   1   *   1   *       *   1   *   1, 2    *
*   2   *   1   *   2   *       *   2   *   3       *
*   3   *   2   *   3   *       *********************
*************************   

使用Stuff和for xml路径操作符将行连接到字符串:Group By两列——>

CREATE TABLE #YourTable ([ID] INT, [Name] CHAR(1), [Value] INT)

INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (1,'A',4)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (1,'B',8)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (1,'B',5)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (2,'C',9)

-- retrieve each unique id and name columns and concatonate the values into one column
SELECT 
  [ID], 
  STUFF((
    SELECT ', ' + [Name] + ':' + CAST([Value] AS VARCHAR(MAX)) -- CONCATONATES EACH APPLICATION : VALUE SET      
    FROM #YourTable 
    WHERE (ID = Results.ID and Name = results.[name] ) 
    FOR XML PATH(''),TYPE).value('(./text())[1]','VARCHAR(MAX)')
  ,1,2,'') AS NameValues
FROM #YourTable Results
GROUP BY ID


SELECT 
  [ID],[Name] , --these are acting as the group by clause
  STUFF((
    SELECT ', '+  CAST([Value] AS VARCHAR(MAX)) -- CONCATONATES THE VALUES FOR EACH ID NAME COMBINATION 
    FROM #YourTable 
    WHERE (ID = Results.ID and Name = results.[name] ) 
    FOR XML PATH(''),TYPE).value('(./text())[1]','VARCHAR(MAX)')
  ,1,2,'') AS  NameValues
FROM #YourTable Results
GROUP BY ID, name

DROP TABLE #YourTable

这类问题在这里经常被问到,解决方案将在很大程度上取决于潜在的需求:

https://stackoverflow.com/search?q=sql+pivot

and

https://stackoverflow.com/search?q=sql+concatenate

通常,如果没有动态sql、用户定义函数或游标,就没有仅使用sql的方法来完成此任务。

如果你启用了clr,你可以使用GitHub中的Group_Concat库