我如何得到:
id Name Value
1 A 4
1 B 8
2 C 9
to
id Column
1 A:4, B:8
2 C:9
我如何得到:
id Name Value
1 A 4
1 B 8
2 C 9
to
id Column
1 A:4, B:8
2 C:9
当前回答
如果是SQL Server 2017或SQL Server Vnext, SQL Azure,您可以使用STRING_AGG如下所示:
SELECT id, STRING_AGG(CONCAT(name, ':', [value]), ', ')
FROM #YourTable
GROUP BY id
其他回答
当我尝试将Kevin Fairchild的建议转换为使用包含空格和编码的特殊XML字符(&,<,>)的字符串时,遇到了几个问题。
我的代码的最终版本(它没有回答最初的问题,但可能对某些人有用)看起来像这样:
CREATE TABLE #YourTable ([ID] INT, [Name] VARCHAR(MAX), [Value] INT)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (1,'Oranges & Lemons',4)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (1,'1 < 2',8)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (2,'C',9)
SELECT [ID],
STUFF((
SELECT ', ' + CAST([Name] AS VARCHAR(MAX))
FROM #YourTable WHERE (ID = Results.ID)
FOR XML PATH(''),TYPE
/* Use .value to uncomment XML entities e.g. > < etc*/
).value('.','VARCHAR(MAX)')
,1,2,'') as NameValues
FROM #YourTable Results
GROUP BY ID
DROP TABLE #YourTable
它没有使用空格作为分隔符并将所有空格替换为逗号,而是在每个值前附加一个逗号和空格,然后使用STUFF删除前两个字符。
XML编码由TYPE指令自动处理。
使用Stuff和for xml路径操作符将行连接到字符串:Group By两列——>
CREATE TABLE #YourTable ([ID] INT, [Name] CHAR(1), [Value] INT)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (1,'A',4)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (1,'B',8)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (1,'B',5)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (2,'C',9)
-- retrieve each unique id and name columns and concatonate the values into one column
SELECT
[ID],
STUFF((
SELECT ', ' + [Name] + ':' + CAST([Value] AS VARCHAR(MAX)) -- CONCATONATES EACH APPLICATION : VALUE SET
FROM #YourTable
WHERE (ID = Results.ID and Name = results.[name] )
FOR XML PATH(''),TYPE).value('(./text())[1]','VARCHAR(MAX)')
,1,2,'') AS NameValues
FROM #YourTable Results
GROUP BY ID
SELECT
[ID],[Name] , --these are acting as the group by clause
STUFF((
SELECT ', '+ CAST([Value] AS VARCHAR(MAX)) -- CONCATONATES THE VALUES FOR EACH ID NAME COMBINATION
FROM #YourTable
WHERE (ID = Results.ID and Name = results.[name] )
FOR XML PATH(''),TYPE).value('(./text())[1]','VARCHAR(MAX)')
,1,2,'') AS NameValues
FROM #YourTable Results
GROUP BY ID, name
DROP TABLE #YourTable
我想对所有的医护人员说:
SELECT
s.NOTE_ID
,STUFF ((
SELECT
[note_text] + ' '
FROM
HNO_NOTE_TEXT s1
WHERE
(s1.NOTE_ID = s.NOTE_ID)
ORDER BY [line] ASC
FOR XML PATH(''),TYPE).value('(./text())[1]','VARCHAR(MAX)')
,
1,
2,
'') AS NOTE_TEXT_CONCATINATED
FROM
HNO_NOTE_TEXT s
GROUP BY NOTE_ID
使用Sql Server 2005及以上版本的另一种选择
---- test data
declare @t table (OUTPUTID int, SCHME varchar(10), DESCR varchar(10))
insert @t select 1125439 ,'CKT','Approved'
insert @t select 1125439 ,'RENO','Approved'
insert @t select 1134691 ,'CKT','Approved'
insert @t select 1134691 ,'RENO','Approved'
insert @t select 1134691 ,'pn','Approved'
---- actual query
;with cte(outputid,combined,rn)
as
(
select outputid, SCHME + ' ('+DESCR+')', rn=ROW_NUMBER() over (PARTITION by outputid order by schme, descr)
from @t
)
,cte2(outputid,finalstatus,rn)
as
(
select OUTPUTID, convert(varchar(max),combined), 1 from cte where rn=1
union all
select cte2.outputid, convert(varchar(max),cte2.finalstatus+', '+cte.combined), cte2.rn+1
from cte2
inner join cte on cte.OUTPUTID = cte2.outputid and cte.rn=cte2.rn+1
)
select outputid, MAX(finalstatus) from cte2 group by outputid
没有看到任何交叉应用的答案,也不需要XML提取。这是凯文·费尔柴尔德的一个略有不同的版本。在更复杂的查询中使用它更快更容易:
select T.ID
,MAX(X.cl) NameValues
from #YourTable T
CROSS APPLY
(select STUFF((
SELECT ', ' + [Name] + ':' + CAST([Value] AS VARCHAR(MAX))
FROM #YourTable
WHERE (ID = T.ID)
FOR XML PATH(''))
,1,2,'') [cl]) X
GROUP BY T.ID