这应该是有效的：

const getRandomNum = (min, max) => Math.floor(Math.random() * (max - min + 1)) + min

其他解决方案：

（数学随机（）*6|0）+1~~（数学随机（）*6）+1

联机尝试

如果您想覆盖负数和正数，并确保其安全，请使用以下方法：

JS解决方案：

function generateRangom(low, up) {
  const u = Math.max(low, up);
  const l = Math.min(low, up);
  const diff = u - l;
  const r = Math.floor(Math.random() * (diff + 1)); //'+1' because Math.random() returns 0..0.99, it does not include 'diff' value, so we do +1, so 'diff + 1' won't be included, but just 'diff' value will be.
  
  return l + r; //add the random number that was selected within distance between low and up to the lower limit.  
}

Java解决方案：

public static int generateRandom(int low, int up) {
        int l = Math.min(low, up);
        int u = Math.max(low, up);
        int diff = u - l;

        int r = (int) Math.floor(Math.random() * (diff + 1)); // '+1' because Math.random() returns 0..0.99, it does not include 'diff' value, so we do +1, so 'diff + 1' won't be included, but just 'diff' value will be.
  
        return l + r;//add the random number that was selected within distance between low and up to the lower limit.      
}

这应该是有效的：

const getRandomNum = (min, max) => Math.floor(Math.random() * (max - min + 1)) + min

使用可重用的随机函数。

function randomNum(min, max) {
  return Math.floor(Math.random() * (max - min + 1)) + min;
}
randomNum(1, 6);

根据@Francisc的答案中的int版本添加具有固定精度版本的float：

function randomFloatFromInterval (min, max, fractionDigits) {
  const fractionMultiplier = Math.pow(10, fractionDigits)
  return Math.round(
    (Math.random() * (max - min) + min) * fractionMultiplier,
  ) / fractionMultiplier
}

so:

randomFloatFromInterval(1,3,4) // => 2.2679, 1.509, 1.8863, 2.9741, ...

对于int答案

randomFloatFromInterval(1,3,0) // => 1, 2, 3