有没有办法用JavaScript生成指定范围内的随机数?

例如:指定范围从1到6,随机数可以是1、2、3、4、5或6。


当前回答

这已经晚了九年,但randojs.com让这成为了一个简单的一行:

rando(1, 6)

您只需要将其添加到html文档的头部,就可以轻松地使用随机性做任何事情。数组中的随机值、随机jquery元素、对象中的随机财产,甚至在需要时防止重复。

<script src="https://randojs.com/1.0.0.js"></script>

其他回答

重要的

The following code works only if the minimum value is `1`. It does not work for minimum values other than `1`.

如果你想得到一个介于1(且只有1)和6之间的随机整数,你可以计算:

const rndInt=数学地板(Math.random()*6)+1控制台日志(rndInt)

哪里:

1是起始编号6是可能结果的数量(1+start(6)-end(1))

尝试使用:

函数随机(最小值,最大值){return Math.round((Math.random()*(Math.abs(max-min)))+min);}console.log(随机(1,6));

尽管有许多答案,但结果几乎相同。我想补充一下我的答案并解释一下它的作用。因为理解它的工作方式比复制粘贴单行代码更重要。生成随机数只是简单的数学。

代码:

function getR(lower, upper) {

  var percent = (Math.random() * 100);
  // this will return number between 0-99 because Math.random returns decimal number from 0-0.9929292 something like that
  //now you have a percentage, use it find out the number between your INTERVAL :upper-lower 
  var num = ((percent * (upper - lower) / 100));
  //num will now have a number that falls in your INTERVAL simple maths
  num += lower;
  //add lower to make it fall in your INTERVAL
  //but num is still in decimal
  //use Math.floor>downward to its nearest integer you won't get upper value ever
  //use Math.ceil>upward to its nearest integer upper value is possible
  //Math.round>to its nearest integer 2.4>2 2.5>3   both lower and upper value possible
  console.log(Math.floor(num), Math.ceil(num), Math.round(num));
}
var x = 6; // can be any number
var rand = Math.floor(Math.random()*x) + 1;

如果您想覆盖负数和正数,并确保其安全,请使用以下方法:

JS解决方案:

function generateRangom(low, up) {
  const u = Math.max(low, up);
  const l = Math.min(low, up);
  const diff = u - l;
  const r = Math.floor(Math.random() * (diff + 1)); //'+1' because Math.random() returns 0..0.99, it does not include 'diff' value, so we do +1, so 'diff + 1' won't be included, but just 'diff' value will be.
  
  return l + r; //add the random number that was selected within distance between low and up to the lower limit.  
}

Java解决方案:

public static int generateRandom(int low, int up) {
        int l = Math.min(low, up);
        int u = Math.max(low, up);
        int diff = u - l;

        int r = (int) Math.floor(Math.random() * (diff + 1)); // '+1' because Math.random() returns 0..0.99, it does not include 'diff' value, so we do +1, so 'diff + 1' won't be included, but just 'diff' value will be.
  
        return l + r;//add the random number that was selected within distance between low and up to the lower limit.      
}