另一种理解它的好方法是:

var foo = {}

/* 
foo.constructor is Object, so foo.constructor.prototype is actually 
Object.prototype; Object.prototype in return is what foo.__proto__ links to. 
*/
console.log(foo.constructor.prototype === foo.__proto__);
// this proves what the above comment proclaims: Both statements evaluate to true.
console.log(foo.__proto__ === Object.prototype);
console.log(foo.constructor.prototype === Object.prototype);

仅当支持IE11 __proto__后。在那个版本之前，比如IE9，你可以使用构造函数来获取__proto__. dll。

在JavaScript中，函数可以用作构造函数。这意味着我们可以使用new关键字从它们中创建对象。每个构造函数都带有一个内置对象。这个内置对象称为原型。构造函数的实例使用__proto__来访问其构造函数的prototype属性。

First we created a constructor: function Foo(){}. To be clear, Foo is just another function. But we can create an object from it with the new keyword. That's why we call it the constructor function Every function has a unique property which is called the prototype property. So, Constructor function Foo has a prototype property which points to its prototype, which is Foo.prototype (see image). Constructor functions are themselves a function which is an instance of a system constructor called the [[Function]] constructor. So we can say that function Foo is constructed by a [[Function]] constructor. So, __proto__ of our Foo function will point to the prototype of its constructor, which is Function.prototype. Function.prototype is itself is nothing but an object which is constructed from another system constructor called [[Object]]. So, [[Object]] is the constructor of Function.prototype. So, we can say Function.prototype is an instance of [[Object]]. So __proto__ of Function.prototype points to Object.prototype. Object.prototype is the last man standing in the prototype chain. I mean it has not been constructed. It's already there in the system. So its __proto__ points to null. Now we come to instances of Foo. When we create an instance using new Foo(), it creates a new object which is an instance of Foo. That means Foo is the constructor of these instances. Here we created two instances (x and y). __proto__ of x and y thus points to Foo.prototype.

一种很好的思考方式是……

Prototype用于构造函数。它真的应该被称为“prototypeToInstall”，因为它就是这样的。

__proto__是对象上的“已安装原型”(由上述构造函数()函数创建/安装在对象上)

原型

prototype是一个函数的属性。它是通过使用带有new关键字的that(构造函数)函数创建对象的蓝图。

__proto__

__proto__在查找链中用于解析方法、属性。当创建对象时(使用构造函数函数和new关键字)，__proto__被设置为(构造函数)function .prototype

function Robot(name) {
    this.name = name;
}
var robot = new Robot();

// the following are true   
robot.__proto__ == Robot.prototype
robot.__proto__.__proto__ == Object.prototype

以下是我的(假想的)解释，以消除困惑:

假设有一个与函数相关的假想类(blueprint/ cookie cutter)。那个假想类用于实例化对象。prototype是一种扩展机制(c#或Swift Extension中的扩展方法)，用于向虚类中添加内容。

function Robot(name) {
    this.name = name;
}

以上可以想象为:

// imaginary class
class Robot extends Object{

    static prototype = Robot.class  
    // Robot.prototype is the way to add things to Robot class
    // since Robot extends Object, therefore Robot.prototype.__proto__ == Object.prototype

    var __proto__;

    var name = "";

    // constructor
    function Robot(name) {

        this.__proto__ = prototype;
        prototype = undefined;

        this.name = name;
    }

} 

So,

var robot = new Robot();

robot.__proto__ == Robot.prototype
robot.prototype == undefined
robot.__proto__.__proto__ == Object.prototype

现在为Robot的原型添加方法:

Robot.prototype.move(x, y) = function(x, y){ Robot.position.x = x; Robot.position.y = y};
// Robot.prototype.move(x, y) ===(imagining)===> Robot.class.move(x, y)

以上可以想象为Robot类的扩展:

// Swift way of extention
extension Robot{
    function move(x, y){    
        Robot.position.x = x; Robot.position.y = y
    }
}

反过来，

// imaginary class
class Robot{

    static prototype = Robot.class // Robot.prototype way to extend Robot class
    var __proto__;

    var name = "";

    // constructor
    function Robot(name) {

        this.__proto__ = prototype;
        prototype = undefined;

        this.name = name;
    }

    // added by prototype (as like C# extension method)
    function move(x, y){ 
        Robot.position.x = x; Robot.position.y = y
    };
}

对于任何想要了解原型继承的人来说，这都是一个非常重要的问题。根据我的理解，默认情况下，当从函数中使用new创建对象时，prototype会被赋值，因为function定义了prototype对象:

function protofoo(){
}
var protofoo1 = new protofoo();
console.log(protofoo.prototype.toString()); //[object Object]

当我们创建一个普通的对象，没有new，即显式地从一个函数，它没有原型，但它有一个空的原型，可以分配一个原型。

var foo={
  check: 10
};
console.log(foo.__proto__); // empty
console.log(bar.prototype); //  TypeError
foo.__proto__ = protofoo1; // assigned
console.log(foo.__proto__); //protofoo

我们可以使用Object。创建以显式链接对象。

// we can create `bar` and link it to `foo`
var bar = Object.create( foo );
bar.fooprops= "We checking prototypes";
console.log(bar.__proto__); // "foo"
console.log(bar.fooprops); // "We checking prototypes"
console.log(bar.check); // 10 is delegated to `foo`

prototype是Function对象的一个属性。它是由该函数构造的对象的原型。

__proto__是一个对象的内部属性，指向它的原型。当前标准提供了等效的Object.getPrototypeOf(obj)方法，尽管事实上的标准__proto__更快。

你可以通过比较函数的原型和对象的__proto__链来找到instanceof关系，你也可以通过改变prototype来打破这些关系。

function Point(x, y) {
    this.x = x;
    this.y = y;
}

var myPoint = new Point();

// the following are all true
myPoint.__proto__ == Point.prototype
myPoint.__proto__.__proto__ == Object.prototype
myPoint instanceof Point;
myPoint instanceof Object;

这里Point是一个构造函数，它程序化地构建一个对象(数据结构)。myPoint是一个由Point()构造的对象，所以Point。原型保存到myPoint。解析:句意:在那个时候。