为了复制具有唯一列的记录，例如COL1,COL2, COL3不应该被复制(假设我们在表结构中遗漏了3个唯一列，并且在表中添加了多个重复项)

DROP TABLE TABLE_NAME_copy;
CREATE TABLE TABLE_NAME_copy LIKE TABLE_NAME;
INSERT INTO TABLE_NAME_copy
SELECT * FROM TABLE_NAME
GROUP BY COLUMN1, COLUMN2, COLUMN3; 
DROP TABLE TABLE_NAME;
ALTER TABLE TABLE_NAME_copy RENAME TO TABLE_NAME;

希望将有助于开发。

要做到这一点，一个非常简单的方法是在3列上添加UNIQUE索引。在编写ALTER语句时，请包含IGNORE关键字。像这样:

ALTER IGNORE TABLE jobs
ADD UNIQUE INDEX idx_name (site_id, title, company);

这将删除所有重复的行。作为一个额外的好处，将来重复的insert将出错。像往常一样，在运行这样的程序之前，您可能想要进行备份…

编辑:不再工作在MySQL 5.7+

这个特性在MySQL 5.6中已经被弃用，在MySQL 5.7中被移除，所以它不起作用。

我有这个查询片段的SQLServer，但我认为它可以用在其他DBMS与小的变化:

DELETE
FROM Table
WHERE Table.idTable IN  (  
    SELECT MAX(idTable)
    FROM idTable
    GROUP BY field1, field2, field3
    HAVING COUNT(*) > 1)

我忘了告诉您，这个查询不会删除重复行中id最低的行。如果这对你有用，试试这个查询:

DELETE
FROM jobs
WHERE jobs.id IN  (  
    SELECT MAX(id)
    FROM jobs
    GROUP BY site_id, company, title, location
    HAVING COUNT(*) > 1)

一种简单易懂且不需要主键的解决方案:

add a new boolean column alter table mytable add tokeep boolean; add a constraint on the duplicated columns AND the new column alter table mytable add constraint preventdupe unique (mycol1, mycol2, tokeep); set the boolean column to true. This will succeed only on one of the duplicated rows because of the new constraint update ignore mytable set tokeep = true; delete rows that have not been marked as tokeep delete from mytable where tokeep is null; drop the added column alter table mytable drop tokeep;

我建议您保留您添加的约束，以便将来防止出现新的重复。

还有另一种解决方案:

DELETE t1 FROM my_table t1, my_table t2 WHERE t1.id < t2.id AND t1.my_field = t2.my_field AND t1.my_field_2 = t2.my_field_2 AND ...

你可以很容易地从这个代码中删除重复的记录。

$qry = mysql_query("SELECT * from cities");
while($qry_row = mysql_fetch_array($qry))
{
$qry2 = mysql_query("SELECT * from cities2 where city = '".$qry_row['city']."'");

if(mysql_num_rows($qry2) > 1){
    while($row = mysql_fetch_array($qry2)){
        $city_arry[] = $row;

        }

    $total = sizeof($city_arry) - 1;
        for($i=1; $i<=$total; $i++){


            mysql_query( "delete from cities2 where town_id = '".$city_arry[$i][0]."'");

            }
    }
    //exit;
}