我有一个表与以下字段:
id (Unique)
url (Unique)
title
company
site_id
现在，我需要删除具有相同标题、company和site_id的行。一种方法是使用下面的SQL和脚本(PHP):
SELECT title, site_id, location, id, count( * )
FROM jobs
GROUP BY site_id, company, title, location
HAVING count( * ) >1
运行此查询后，可以使用服务器端脚本删除重复项。
但是，我想知道这是否只能使用SQL查询。
当前回答
我有这个查询片段的SQLServer，但我认为它可以用在其他DBMS与小的变化:
DELETE
FROM Table
WHERE Table.idTable IN (
SELECT MAX(idTable)
FROM idTable
GROUP BY field1, field2, field3
HAVING COUNT(*) > 1)
我忘了告诉您，这个查询不会删除重复行中id最低的行。如果这对你有用，试试这个查询:
DELETE
FROM jobs
WHERE jobs.id IN (
SELECT MAX(id)
FROM jobs
GROUP BY site_id, company, title, location
HAVING COUNT(*) > 1)
其他回答
简单和快速的所有情况:
CREATE TEMPORARY TABLE IF NOT EXISTS _temp_duplicates AS (SELECT dub.id FROM table_with_duplications dub GROUP BY dub.field_must_be_uniq_1, dub.field_must_be_uniq_2 HAVING COUNT(*) > 1);
DELETE FROM table_with_duplications WHERE id IN (SELECT id FROM _temp_duplicates);
如果不想更改列属性，那么可以使用下面的查询。
因为你有一个列，它有唯一的id(例如，auto_increment列)，你可以用它来删除重复项:
DELETE `a`
FROM
`jobs` AS `a`,
`jobs` AS `b`
WHERE
-- IMPORTANT: Ensures one version remains
-- Change "ID" to your unique column's name
`a`.`ID` < `b`.`ID`
-- Any duplicates you want to check for
AND (`a`.`title` = `b`.`title` OR `a`.`title` IS NULL AND `b`.`title` IS NULL)
AND (`a`.`company` = `b`.`company` OR `a`.`company` IS NULL AND `b`.`company` IS NULL)
AND (`a`.`site_id` = `b`.`site_id` OR `a`.`site_id` IS NULL AND `b`.`site_id` IS NULL);
在MySQL中，你可以用空安全的相等操作符(又名“宇宙飞船操作符”)来简化它:
DELETE `a`
FROM
`jobs` AS `a`,
`jobs` AS `b`
WHERE
-- IMPORTANT: Ensures one version remains
-- Change "ID" to your unique column's name
`a`.`ID` < `b`.`ID`
-- Any duplicates you want to check for
AND `a`.`title` <=> `b`.`title`
AND `a`.`company` <=> `b`.`company`
AND `a`.`site_id` <=> `b`.`site_id`;
这将删除标题、公司和网站值相同的重复行。最后一个重复项将被保留，其余重复项将被删除(如果你想保留第一个重复项并删除其他重复项，将id的比较项更改为大于t1。Id > t2.id)
DELETE t1 FROM tablename t1
INNER JOIN tablename t2
WHERE
t1.id < t2.id AND
t1.title = t2.title AND
t1.company=t2.company AND
t1.site_ID=t2.site_ID;
你可以很容易地从这个代码中删除重复的记录。
$qry = mysql_query("SELECT * from cities");
while($qry_row = mysql_fetch_array($qry))
{
$qry2 = mysql_query("SELECT * from cities2 where city = '".$qry_row['city']."'");
if(mysql_num_rows($qry2) > 1){
while($row = mysql_fetch_array($qry2)){
$city_arry[] = $row;
}
$total = sizeof($city_arry) - 1;
for($i=1; $i<=$total; $i++){
mysql_query( "delete from cities2 where town_id = '".$city_arry[$i][0]."'");
}
}
//exit;
}
我想更具体地说明我删除了哪些记录，下面是我的解决方案:
delete
from jobs c1
where not c1.location = 'Paris'
and c1.site_id > 64218
and exists
(
select * from jobs c2
where c2.site_id = c1.site_id
and c2.company = c1.company
and c2.location = c1.location
and c2.title = c1.title
and c2.site_id > 63412
and c2.site_id < 64219
)
