如果不想更改列属性，那么可以使用下面的查询。

因为你有一个列，它有唯一的id(例如，auto_increment列)，你可以用它来删除重复项:

DELETE `a`
FROM
    `jobs` AS `a`,
    `jobs` AS `b`
WHERE
    -- IMPORTANT: Ensures one version remains
    -- Change "ID" to your unique column's name
    `a`.`ID` < `b`.`ID`

    -- Any duplicates you want to check for
    AND (`a`.`title` = `b`.`title` OR `a`.`title` IS NULL AND `b`.`title` IS NULL)
    AND (`a`.`company` = `b`.`company` OR `a`.`company` IS NULL AND `b`.`company` IS NULL)
    AND (`a`.`site_id` = `b`.`site_id` OR `a`.`site_id` IS NULL AND `b`.`site_id` IS NULL);

在MySQL中，你可以用空安全的相等操作符(又名“宇宙飞船操作符”)来简化它:

DELETE `a`
FROM
    `jobs` AS `a`,
    `jobs` AS `b`
WHERE
    -- IMPORTANT: Ensures one version remains
    -- Change "ID" to your unique column's name
    `a`.`ID` < `b`.`ID`

    -- Any duplicates you want to check for
    AND `a`.`title` <=> `b`.`title`
    AND `a`.`company` <=> `b`.`company`
    AND `a`.`site_id` <=> `b`.`site_id`;

如果您试图删除其中一个副本并保留另一个副本，那么这是完美的。注意，如果没有子查询，您将得到#1093错误。

DELETE FROM table_name
WHERE id IN (
    SELECT * FROM (SELECT n.id FROM table_name n
    WHERE n.column2 != "value"
    GROUP BY n.column HAVING COUNT(n.column ) > 1) x
)

删除表中重复的记录。

delete from job s 
where rowid < any 
(select rowid from job k 
where s.site_id = k.site_id and 
s.title = k.title and 
s.company = k.company);

or

delete from job s 
where rowid not in 
(select max(rowid) from job k 
where s.site_id = k.site_id and
s.title = k.title and 
s.company = k.company);

这个解决方案将把重复的数据移到一个表中，唯一的数据移到另一个表中。

-- speed up creating uniques table if dealing with many rows
CREATE INDEX temp_idx ON jobs(site_id, company, title, location);

-- create the table with unique rows
INSERT jobs_uniques SELECT * FROM
    (
    SELECT * 
    FROM jobs
    GROUP BY site_id, company, title, location
    HAVING count(1) > 1
    UNION
    SELECT *
    FROM jobs
    GROUP BY site_id, company, title, location
    HAVING count(1) = 1
) x

-- create the table with duplicate rows
INSERT jobs_dupes 
SELECT * 
FROM jobs
WHERE id NOT IN
(SELECT id FROM jobs_uniques)

-- confirm the difference between uniques and dupes tables
SELECT COUNT(1)
AS jobs, 
(SELECT COUNT(1) FROM jobs_dupes) + (SELECT COUNT(1) FROM jobs_uniques)
AS sum
FROM jobs

MySQL对引用要删除的表有限制。你可以用一个临时表来解决这个问题，比如:

create temporary table tmpTable (id int);

insert  into tmpTable
        (id)
select  id
from    YourTable yt
where   exists
        (
        select  *
        from    YourTabe yt2
        where   yt2.title = yt.title
                and yt2.company = yt.company
                and yt2.site_id = yt.site_id
                and yt2.id > yt.id
        );

delete  
from    YourTable
where   ID in (select id from tmpTable);

以下是Kostanos在评论中的建议: 上面唯一缓慢的查询是DELETE，适用于数据库非常大的情况。这个查询可以更快:

DELETE FROM YourTable USING YourTable, tmpTable WHERE YourTable.id=tmpTable.id

如果你有一个有大量记录的大表，那么上述解决方案将不起作用或花费太多时间。然后我们有一个不同的解

-- Create temporary table

CREATE TABLE temp_table LIKE table1;

-- Add constraint
ALTER TABLE temp_table ADD UNIQUE(title, company,site_id);

-- Copy data
INSERT IGNORE INTO temp_table SELECT * FROM table1;

-- Rename and drop
RENAME TABLE table1 TO old_table1, temp_table TO table1;
DROP TABLE old_table1;