我有一个表与以下字段:
id (Unique)
url (Unique)
title
company
site_id
现在，我需要删除具有相同标题、company和site_id的行。一种方法是使用下面的SQL和脚本(PHP):
SELECT title, site_id, location, id, count( * )
FROM jobs
GROUP BY site_id, company, title, location
HAVING count( * ) >1
运行此查询后，可以使用服务器端脚本删除重复项。
但是，我想知道这是否只能使用SQL查询。
当前回答
如果IGNORE语句在我的例子中不起作用，你可以使用下面的语句:
CREATE TABLE your_table_deduped LIKE your_table;
INSERT your_table_deduped
SELECT *
FROM your_table
GROUP BY index1_id,
index2_id;
RENAME TABLE your_table TO your_table_with_dupes;
RENAME TABLE your_table_deduped TO your_table;
#OPTIONAL
ALTER TABLE `your_table` ADD UNIQUE `unique_index` (`index1_id`, `index2_id`);
#OPTIONAL
DROP TABLE your_table_with_dupes;
其他回答
我有这个查询片段的SQLServer，但我认为它可以用在其他DBMS与小的变化:
DELETE
FROM Table
WHERE Table.idTable IN (
SELECT MAX(idTable)
FROM idTable
GROUP BY field1, field2, field3
HAVING COUNT(*) > 1)
我忘了告诉您，这个查询不会删除重复行中id最低的行。如果这对你有用，试试这个查询:
DELETE
FROM jobs
WHERE jobs.id IN (
SELECT MAX(id)
FROM jobs
GROUP BY site_id, company, title, location
HAVING COUNT(*) > 1)
我必须对文本字段执行此操作，并且遇到了索引上100字节的限制。
我通过添加一个列来解决这个问题，对字段进行md5哈希，并进行更改。
ALTER TABLE table ADD `merged` VARCHAR( 40 ) NOT NULL ;
UPDATE TABLE SET merged` = MD5(CONCAT(`col1`, `col2`, `col3`))
ALTER IGNORE TABLE table ADD UNIQUE INDEX idx_name (`merged`);
下面是我用过的方法，它很有效:
create table temp_table like my_table;
T_id是唯一的列
insert into temp_table (id) select id from my_table GROUP by t_id;
delete from my_table where id not in (select id from temp_table);
drop table temp_table;
这个解决方案将把重复的数据移到一个表中，唯一的数据移到另一个表中。
-- speed up creating uniques table if dealing with many rows
CREATE INDEX temp_idx ON jobs(site_id, company, title, location);
-- create the table with unique rows
INSERT jobs_uniques SELECT * FROM
(
SELECT *
FROM jobs
GROUP BY site_id, company, title, location
HAVING count(1) > 1
UNION
SELECT *
FROM jobs
GROUP BY site_id, company, title, location
HAVING count(1) = 1
) x
-- create the table with duplicate rows
INSERT jobs_dupes
SELECT *
FROM jobs
WHERE id NOT IN
(SELECT id FROM jobs_uniques)
-- confirm the difference between uniques and dupes tables
SELECT COUNT(1)
AS jobs,
(SELECT COUNT(1) FROM jobs_dupes) + (SELECT COUNT(1) FROM jobs_uniques)
AS sum
FROM jobs
如果IGNORE语句在我的例子中不起作用，你可以使用下面的语句:
CREATE TABLE your_table_deduped LIKE your_table;
INSERT your_table_deduped
SELECT *
FROM your_table
GROUP BY index1_id,
index2_id;
RENAME TABLE your_table TO your_table_with_dupes;
RENAME TABLE your_table_deduped TO your_table;
#OPTIONAL
ALTER TABLE `your_table` ADD UNIQUE `unique_index` (`index1_id`, `index2_id`);
#OPTIONAL
DROP TABLE your_table_with_dupes;
