MySQL对引用要删除的表有限制。你可以用一个临时表来解决这个问题，比如:

create temporary table tmpTable (id int);

insert  into tmpTable
        (id)
select  id
from    YourTable yt
where   exists
        (
        select  *
        from    YourTabe yt2
        where   yt2.title = yt.title
                and yt2.company = yt.company
                and yt2.site_id = yt.site_id
                and yt2.id > yt.id
        );

delete  
from    YourTable
where   ID in (select id from tmpTable);

以下是Kostanos在评论中的建议: 上面唯一缓慢的查询是DELETE，适用于数据库非常大的情况。这个查询可以更快:

DELETE FROM YourTable USING YourTable, tmpTable WHERE YourTable.id=tmpTable.id

使用Delete JOIN语句删除重复的行 MySQL为您提供了DELETE JOIN语句，您可以使用它快速删除重复的行。

下面的语句删除重复的行并保留最高的id:

DELETE t1 FROM contacts t1
    INNER JOIN
contacts t2 WHERE
t1.id < t2.id AND t1.email = t2.email;

我想更具体地说明我删除了哪些记录，下面是我的解决方案:

delete
from jobs c1
where not c1.location = 'Paris'
and  c1.site_id > 64218
and exists 
(  
select * from jobs c2 
where c2.site_id = c1.site_id
and   c2.company = c1.company
and   c2.location = c1.location
and   c2.title = c1.title
and   c2.site_id > 63412
and   c2.site_id < 64219
)

我找到了一个简单的方法。(保持最新的)

DELETE t1 FROM table_name t1 INNER JOIN table_name t2 
WHERE t1.primary_id < t2.primary_id 
AND t1.check_duplicate_col_1 = t2.check_duplicate_col_1 
AND t1.check_duplicate_col_2 = t2.check_duplicate_col_2
...

这个解决方案将把重复的数据移到一个表中，唯一的数据移到另一个表中。

-- speed up creating uniques table if dealing with many rows
CREATE INDEX temp_idx ON jobs(site_id, company, title, location);

-- create the table with unique rows
INSERT jobs_uniques SELECT * FROM
    (
    SELECT * 
    FROM jobs
    GROUP BY site_id, company, title, location
    HAVING count(1) > 1
    UNION
    SELECT *
    FROM jobs
    GROUP BY site_id, company, title, location
    HAVING count(1) = 1
) x

-- create the table with duplicate rows
INSERT jobs_dupes 
SELECT * 
FROM jobs
WHERE id NOT IN
(SELECT id FROM jobs_uniques)

-- confirm the difference between uniques and dupes tables
SELECT COUNT(1)
AS jobs, 
(SELECT COUNT(1) FROM jobs_dupes) + (SELECT COUNT(1) FROM jobs_uniques)
AS sum
FROM jobs

下面是我用过的方法，它很有效:

create table temp_table like my_table;

T_id是唯一的列

insert into temp_table (id) select id from my_table GROUP by t_id;
delete from my_table where id not in (select id from temp_table);
drop table temp_table;