更快的方法是在临时表中插入不同的行。使用delete，我花了几个小时从一个800万行的表中删除重复项。使用insert和distinct，只花了13分钟。

CREATE TABLE tempTableName LIKE tableName;  
CREATE INDEX ix_all_id ON tableName(cellId,attributeId,entityRowId,value);  
INSERT INTO tempTableName(cellId,attributeId,entityRowId,value) SELECT DISTINCT cellId,attributeId,entityRowId,value FROM tableName;  
TRUNCATE TABLE tableName;
INSERT INTO tableName SELECT * FROM tempTableName; 
DROP TABLE tempTableName;  

简单和快速的所有情况:

CREATE TEMPORARY TABLE IF NOT EXISTS _temp_duplicates AS (SELECT dub.id FROM table_with_duplications dub GROUP BY dub.field_must_be_uniq_1, dub.field_must_be_uniq_2 HAVING COUNT(*)  > 1);

DELETE FROM table_with_duplications WHERE id IN (SELECT id FROM _temp_duplicates);

如果不想更改列属性，那么可以使用下面的查询。

因为你有一个列，它有唯一的id(例如，auto_increment列)，你可以用它来删除重复项:

DELETE `a`
FROM
    `jobs` AS `a`,
    `jobs` AS `b`
WHERE
    -- IMPORTANT: Ensures one version remains
    -- Change "ID" to your unique column's name
    `a`.`ID` < `b`.`ID`

    -- Any duplicates you want to check for
    AND (`a`.`title` = `b`.`title` OR `a`.`title` IS NULL AND `b`.`title` IS NULL)
    AND (`a`.`company` = `b`.`company` OR `a`.`company` IS NULL AND `b`.`company` IS NULL)
    AND (`a`.`site_id` = `b`.`site_id` OR `a`.`site_id` IS NULL AND `b`.`site_id` IS NULL);

在MySQL中，你可以用空安全的相等操作符(又名“宇宙飞船操作符”)来简化它:

DELETE `a`
FROM
    `jobs` AS `a`,
    `jobs` AS `b`
WHERE
    -- IMPORTANT: Ensures one version remains
    -- Change "ID" to your unique column's name
    `a`.`ID` < `b`.`ID`

    -- Any duplicates you want to check for
    AND `a`.`title` <=> `b`.`title`
    AND `a`.`company` <=> `b`.`company`
    AND `a`.`site_id` <=> `b`.`site_id`;

这将删除标题、公司和网站值相同的重复行。最后一个重复项将被保留，其余重复项将被删除(如果你想保留第一个重复项并删除其他重复项，将id的比较项更改为大于t1。Id > t2.id)

DELETE t1 FROM tablename t1
INNER JOIN tablename t2 
WHERE 
    t1.id < t2.id AND
    t1.title = t2.title AND
    t1.company=t2.company AND
    t1.site_ID=t2.site_ID;

我有这个查询片段的SQLServer，但我认为它可以用在其他DBMS与小的变化:

DELETE
FROM Table
WHERE Table.idTable IN  (  
    SELECT MAX(idTable)
    FROM idTable
    GROUP BY field1, field2, field3
    HAVING COUNT(*) > 1)

我忘了告诉您，这个查询不会删除重复行中id最低的行。如果这对你有用，试试这个查询:

DELETE
FROM jobs
WHERE jobs.id IN  (  
    SELECT MAX(id)
    FROM jobs
    GROUP BY site_id, company, title, location
    HAVING COUNT(*) > 1)

还有另一种解决方案:

DELETE t1 FROM my_table t1, my_table t2 WHERE t1.id < t2.id AND t1.my_field = t2.my_field AND t1.my_field_2 = t2.my_field_2 AND ...