将List转换为数据表

public static class DataTableConverter
{
    /// <summary>
    /// Convert a List{T} to a DataTable.
    /// </summary>
    public static DataTable ToDataTable<T>(this IList<T> items)
    {
        var tb = new DataTable(typeof(T).Name);

        PropertyInfo[] props = typeof(T).GetProperties(BindingFlags.Public | BindingFlags.Instance);

        foreach (PropertyInfo prop in props)
        {
            Type t = GetCoreType(prop.PropertyType);
            tb.Columns.Add(prop.Name, t);
        }

        foreach (T item in items)
        {
            var values = new object[props.Length];

            for (int i = 0; i < props.Length; i++)
            {
                values[i] = props[i].GetValue(item, null);
            }

            tb.Rows.Add(values);
        }

        return tb;
    }

    /// <summary>
    /// Determine of specified type is nullable
    /// </summary>
    public static bool IsNullable(Type t)
    {
        return !t.IsValueType || (t.IsGenericType && t.GetGenericTypeDefinition() == typeof(Nullable<>));
    }

    /// <summary>
    /// Return underlying type if type is Nullable otherwise return the type
    /// </summary>
    public static Type GetCoreType(Type t)
    {
        if (t != null && IsNullable(t))
        {
            if (!t.IsValueType)
            {
                return t;
            }
            else
            {
                return Nullable.GetUnderlyingType(t);
            }
        }
        else
        {
            return t;
        }
    }
}

用法:

    IList<MyClass> myClassList = new List<MyClass>();
    DataTable myClassDataTable = myClassList.ToDataTable();

我很失望，. net框架更倾向于将文件和目录表示为字符串而不是对象，而且FileInfo和DirectoryInfo类型并不像我希望的那样强大。因此，我开始根据需要编写流畅的扩展方法，例如:

public static FileInfo SetExtension(this FileInfo fileInfo, string extension)
{
    return new FileInfo(Path.ChangeExtension(fileInfo.FullName, extension));
}

public static FileInfo SetDirectory(this FileInfo fileInfo, string directory)
{
    return new FileInfo(Path.Combine(directory, fileInfo.Name));
}

是的，你可以把这个放进codeplex

使用反射查找TryParse方法并在字符串目标上调用它。可选参数指定转换失败时应返回的内容。我发现这个方法在大多数时候都很有用。很清楚皈依者。ChangeType选项，但我发现这更有用的什么与默认结果方便和什么。请注意，找到的方法保存在字典中，尽管我确实怀疑装箱最终会降低一点速度。

这种方法是我最喜欢的，因为它合理地使用了许多语言特性。

private static readonly Dictionary<Type, MethodInfo> Parsers = new Dictionary<Type, MethodInfo>();

public static T Parse<T>(this string value, T defaultValue = default(T))
{
    if (string.IsNullOrEmpty(value)) return defaultValue;

    if (!Parsers.ContainsKey(typeof(T)))
        Parsers[typeof (T)] = typeof (T).GetMethods(BindingFlags.Public | BindingFlags.Static)
            .Where(mi => mi.Name == "TryParse")
            .Single(mi =>
                        {
                            var parameters = mi.GetParameters();
                            if (parameters.Length != 2) return false;
                            return parameters[0].ParameterType == typeof (string) &&
                                   parameters[1].ParameterType == typeof (T).MakeByRefType();
                        });

    var @params = new object[] {value, default(T)};
    return (bool) Parsers[typeof (T)].Invoke(null, @params) ?
        (T) @params[1] : defaultValue;
}

用法:

var hundredTwentyThree = "123".Parse(0);
var badnumber = "test".Parse(-1);
var date = "01/01/01".Parse<DateTime>();

相当于Python的Join方法:

/// <summary>
/// same as python 'join'
/// </summary>
/// <typeparam name="T">list type</typeparam>
/// <param name="separator">string separator </param>
/// <param name="list">list of objects to be ToString'd</param>
/// <returns>a concatenated list interleaved with separators</returns>
static public string Join<T>(this string separator, IEnumerable<T> list)
{
    var sb = new StringBuilder();
    bool first = true;

    foreach (T v in list)
    {
        if (!first)
            sb.Append(separator);
        first = false;

        if (v != null)
            sb.Append(v.ToString());
    }

    return sb.ToString();
}

避免参数的解析模式:

public static bool TryParseInt32(this string input, Action<int> action)
{
    int result;
    if (Int32.TryParse(input, out result))
    {
        action(result);
        return true;
    }
    return false;
}

用法:

if (!textBox.Text.TryParseInt32(number => label.Text = SomeMathFunction(number)))
    label.Text = "Please enter a valid integer";

这可以放在codeplex项目中，如果需要的话

另一个对我有用的是:

/// <summary>
/// Converts any type in to an Int32
/// </summary>
/// <typeparam name="T">Any Object</typeparam>
/// <param name="value">Value to convert</param>
/// <returns>The integer, 0 if unsuccessful</returns>
public static int ToInt32<T>(this T value)
{
  int result;
  if (int.TryParse(value.ToString(), out result))
  {
    return result;
  }
  return 0;
}

/// <summary>
/// Converts any type in to an Int32 but if null then returns the default
/// </summary>
/// <param name="value">Value to convert</param>
/// <typeparam name="T">Any Object</typeparam>
/// <param name="defaultValue">Default to use</param>
/// <returns>The defaultValue if unsuccessful</returns>
public static int ToInt32<T>(this T value, int defaultValue)
{
  int result;
  if (int.TryParse(value.ToString(), out result))
  {
    return result;
  }
  return defaultValue;
}

例子:

int number = "123".ToInt32();

or:

int badNumber = "a".ToInt32(100); // Returns 100 since a is nan