避免参数的解析模式:

public static bool TryParseInt32(this string input, Action<int> action)
{
    int result;
    if (Int32.TryParse(input, out result))
    {
        action(result);
        return true;
    }
    return false;
}

用法:

if (!textBox.Text.TryParseInt32(number => label.Text = SomeMathFunction(number)))
    label.Text = "Please enter a valid integer";

这可以放在codeplex项目中，如果需要的话

到目前为止，我刚刚浏览了所有4页，我很惊讶，我没有看到这种方式来缩短检查InvokeRequired:

using System;
using System.Windows.Forms;

/// <summary>
/// Extension methods acting on Control objects.
/// </summary>
internal static class ControlExtensionMethods
{
    /// <summary>
    /// Invokes the given action on the given control's UI thread, if invocation is needed.
    /// </summary>
    /// <param name="control">Control on whose UI thread to possibly invoke.</param>
    /// <param name="action">Action to be invoked on the given control.</param>
    public static void MaybeInvoke(this Control control, Action action)
    {
        if (control != null && control.InvokeRequired)
        {
            control.Invoke(action);
        }
        else
        {
            action();
        }
    }

    /// <summary>
    /// Maybe Invoke a Func that returns a value.
    /// </summary>
    /// <typeparam name="T">Return type of func.</typeparam>
    /// <param name="control">Control on which to maybe invoke.</param>
    /// <param name="func">Function returning a value, to invoke.</param>
    /// <returns>The result of the call to func.</returns>
    public static T MaybeInvoke<T>(this Control control, Func<T> func)
    {
        if (control != null && control.InvokeRequired)
        {
            return (T)(control.Invoke(func));
        }
        else
        {
            return func();
        }
    }
}

用法:

myForm.MaybeInvoke(() => this.Text = "Hello world");

// Sometimes the control might be null, but that's okay.
var dialogResult = this.Parent.MaybeInvoke(() => MessageBox.Show(this, "Yes or no?", "Choice", MessageBoxButtons.YesNo));

我在我的Silverlight项目中使用这些:

public static void Show(this UIElement element)
{
    element.Visibility = Visibility.Visible;
}

public static void Hide(this UIElement element)
{
    element.Visibility = Visibility.Collapsed;
}

public static class StringExtensions {

    /// <summary>
    /// Parses a string into an Enum
    /// </summary>
    /// <typeparam name="T">The type of the Enum</typeparam>
    /// <param name="value">String value to parse</param>
    /// <returns>The Enum corresponding to the stringExtensions</returns>
    public static T EnumParse<T>(this string value) {
        return StringExtensions.EnumParse<T>(value, false);
    }

    public static T EnumParse<T>(this string value, bool ignorecase) {

        if (value == null) {
            throw new ArgumentNullException("value");
        }

        value = value.Trim();

        if (value.Length == 0) {
            throw new ArgumentException("Must specify valid information for parsing in the string.", "value");
        }

        Type t = typeof(T);

        if (!t.IsEnum) {
            throw new ArgumentException("Type provided must be an Enum.", "T");
        }

        return (T)Enum.Parse(t, value, ignorecase);
    }
}

将字符串解析为Enum很有用。

public enum TestEnum
{
    Bar,
    Test
}

public class Test
{
    public void Test()
    {
        TestEnum foo = "Test".EnumParse<TestEnum>();
    }
 }

这要归功于斯科特·多尔曼

——编辑Codeplex项目——

我问过Scott Dorman，他是否介意我们在Codeplex项目中发布他的代码。我从他那里得到的回答是:

感谢你对SO帖子和CodePlex项目的提醒。我赞成你对这个问题的回答。是的，代码目前在CodeProject开放许可证(http://www.codeproject.com/info/cpol10.aspx)下有效地处于公共领域。 我没有问题，这被包括在CodePlex项目，如果你想把我添加到项目(用户名是sdorman)，我会添加该方法加上一些额外的枚举助手方法。

将double类型转换为使用指定区域性格式化的字符串:

public static class ExtensionMethods 
{
  public static string ToCurrency(this double value, string cultureName)
  {
    CultureInfo currentCulture = new CultureInfo(cultureName);
    return (string.Format(currentCulture, "{0:C}", value));
  }
}

例子:

double test = 154.20;
string testString = test.ToCurrency("en-US"); // $154.20

在这里找到更多的例子:www.extensionmethod.net