我相信以前有人这样做过，但我发现自己经常使用这种方法(和更简单的导数):

public static bool CompareEx(this string strA, string strB, CultureInfo culture, bool ignoreCase)
{
    return string.Compare(strA, strB, ignoreCase, culture) == 0;
}

您可以以多种方式编写它，但我喜欢它，因为它非常快速地统一了比较字符串的方法，同时节省了代码行数(或代码字符)。

无论如何，把它放在codeplex项目中。

将对象序列化/反序列化为XML:

/// <summary>Serializes an object of type T in to an xml string</summary>
/// <typeparam name="T">Any class type</typeparam>
/// <param name="obj">Object to serialize</param>
/// <returns>A string that represents Xml, empty otherwise</returns>
public static string XmlSerialize<T>(this T obj) where T : class, new()
{
    if (obj == null) throw new ArgumentNullException("obj");

    var serializer = new XmlSerializer(typeof(T));
    using (var writer = new StringWriter())
    {
        serializer.Serialize(writer, obj);
        return writer.ToString();
    }
}

/// <summary>Deserializes an xml string in to an object of Type T</summary>
/// <typeparam name="T">Any class type</typeparam>
/// <param name="xml">Xml as string to deserialize from</param>
/// <returns>A new object of type T is successful, null if failed</returns>
public static T XmlDeserialize<T>(this string xml) where T : class, new()
{
    if (xml == null) throw new ArgumentNullException("xml");

    var serializer = new XmlSerializer(typeof(T));
    using (var reader = new StringReader(xml))
    {
        try { return (T)serializer.Deserialize(reader); }
        catch { return null; } // Could not be deserialized to this type.
    }
}

python字典方法:

/// <summary>
/// If a key exists in a dictionary, return its value, 
/// otherwise return the default value for that type.
/// </summary>
public static U GetWithDefault<T, U>(this Dictionary<T, U> dict, T key)
{
    return dict.GetWithDefault(key, default(U));
}

/// <summary>
/// If a key exists in a dictionary, return its value,
/// otherwise return the provided default value.
/// </summary>
public static U GetWithDefault<T, U>(this Dictionary<T, U> dict, T key, U defaultValue)
{
    return dict.ContainsKey(key)
        ? dict[key]
        : defaultValue;
}

当您希望将时间戳附加到文件名以确保唯一性时非常有用。

/// <summary>
/// Format a DateTime as a string that contains no characters
//// that are banned from filenames, such as ':'.
/// </summary>
/// <returns>YYYY-MM-DD_HH.MM.SS</returns>
public static string ToFilenameString(this DateTime dt)
{
    return dt.ToString("s").Replace(":", ".").Replace('T', '_');
}

我喜欢这些NUnit Assert扩展:http://svn.caffeine-it.com/openrasta/trunk/src/Rasta.Testing/AssertExtensions.cs

字符串。格式的快捷方式:

public static class StringExtensions
{
    // Enable quick and more natural string.Format calls
    public static string F(this string s, params object[] args)
    {
        return string.Format(s, args);
    }
}

例子:

var s = "The co-ordinate is ({0}, {1})".F(point.X, point.Y);

要快速复制粘贴，请点击这里。

难道你不觉得输入“一些字符串”. f(“param”)而不是字符串更自然吗?格式(“一些字符串”，“参数”)?

想要一个更容易读懂的名字，试试下面的建议:

s = "Hello {0} world {1}!".Fmt("Stack", "Overflow");
s = "Hello {0} world {1}!".FormatBy("Stack", "Overflow");
s = "Hello {0} world {1}!".FormatWith("Stack", "Overflow");
s = "Hello {0} world {1}!".Display("Stack", "Overflow");
s = "Hello {0} world {1}!".With("Stack", "Overflow");

..

我很失望，. net框架更倾向于将文件和目录表示为字符串而不是对象，而且FileInfo和DirectoryInfo类型并不像我希望的那样强大。因此，我开始根据需要编写流畅的扩展方法，例如:

public static FileInfo SetExtension(this FileInfo fileInfo, string extension)
{
    return new FileInfo(Path.ChangeExtension(fileInfo.FullName, extension));
}

public static FileInfo SetDirectory(this FileInfo fileInfo, string directory)
{
    return new FileInfo(Path.Combine(directory, fileInfo.Name));
}

是的，你可以把这个放进codeplex