让我们把你的优秀和最喜欢的扩展方法列一个列表。

要求是必须发布完整的代码,以及如何使用它的示例和解释。

基于对这个主题的高度兴趣,我在Codeplex上建立了一个名为extensionoverflow的开源项目。

请将您的回答标记为接受,以便将代码放入Codeplex项目。

请张贴完整的源代码,而不是一个链接。

Codeplex上新闻:

24.08.2010 Codeplex页面现在在这里:http://extensionoverflow.codeplex.com/

11.11.2008 XmlSerialize / XmlDeserialize现在是实现和单元测试。

11.11.2008仍有发展空间。;-)现在就加入!

11.11.2008第三位贡献者加入了ExtensionOverflow,欢迎加入BKristensen

11.11.2008 FormatWith现在是实现和单元测试。

09.11.2008第二个贡献者加入ExtensionOverflow。欢迎来到chakrit。

我们需要更多的开发人员。: -)

09.11.2008 ThrowIfArgumentIsNull现已在Codeplex上实现和单元测试。


当前回答

我喜欢下面这些方法来处理带有Flags属性集的枚举:

public static bool AnyOf(this object mask, object flags)
{
    return ((int)mask & (int)flags) != 0;
}
public static bool AllOf(this object mask, object flags)
{
    return ((int)mask & (int)flags) == (int)flags;
}
public static object SetOn(this object mask, object flags)
{
    return (int)mask | (int)flags;
}
etc.

使用示例:

var options = SomeOptions.OptionA;
options = options.SetOn(OptionB);
options = options.SetOn(OptionC);

if (options.AnyOf(SomeOptions.OptionA | SomeOptions.OptionB))
{
etc.

原始方法来自本文:http://www.codeproject.com/KB/cs/masksandflags.aspx?display=Print 我只是把它们转换成扩展方法。

但它们的一个问题是对象类型的参数,这意味着所有对象最终都被这些方法扩展,而理想情况下,它们应该只应用于枚举。

更新 根据评论,你可以绕过“签名污染”,以牺牲性能为代价,如下所示:

public static bool AnyOf(this Enum mask, object flags)
{
    return (Convert.ToInt642(mask) & (int)flags) != 0;
}

其他回答

ThrowIfArgumentIsNull是做空检查的好方法,我们都应该这样做。

public static class Extensions
{
    public static void ThrowIfArgumentIsNull<T>(this T obj, string parameterName) where T : class
    {
        if (obj == null) throw new ArgumentNullException(parameterName + " not allowed to be null");
    }
}

下面是使用它的方法,它适用于您的命名空间中的所有类或任何您使用该命名空间的地方。

internal class Test
{
    public Test(string input1)
    {
        input1.ThrowIfArgumentIsNull("input1");
    }
}

在CodePlex项目上使用这段代码是可以的。

我还没有看到任何关于这个问题的答案…

public static string[] Split(this string value, string regexPattern)
{
    return value.Split(regexPattern, RegexOptions.None);
}

public static string[] Split(this string value, string regexPattern, 
    RegexOptions options)
{
    return Regex.Split(value, regexPattern, options);
}

用法:

var obj = "test1,test2,test3";
string[] arrays = obj.Split(",");

如果您使用财政年度,则有两个有用的扩展

/// <summary>
/// Returns the fiscal year for the passed in date
/// </summary>
/// <param name="value">the date</param>
/// <returns>the fiscal year</returns>
public static int FiscalYear(this DateTime value)
{
  int ret = value.Year;
  if (value.Month >= 7) ret++;
  return ret;
}

/// <summary>
/// Returns the fiscal year for the passed in date
/// </summary>
/// <param name="value">the date</param>
/// <returns>the fiscal year</returns>
public static string FiscalYearString(this DateTime value)
{
  int fy = FiscalYear(value);
  return "{0}/{1}".Format(fy - 1, fy);
}

我最喜欢的是字符串上的IsLike()扩展。IsLike()匹配VB的Like操作符,当你不想写一个完整的正则表达式来解决你的问题时,它很方便。用法是这样的:

"abc".IsLike("a*"); // true
"Abc".IsLike("[A-Z][a-z][a-z]"); // true
"abc123".IsLike("*###"); // true
"hat".IsLike("?at"); // true
"joe".IsLike("[!aeiou]*"); // true

"joe".IsLike("?at"); // false
"joe".IsLike("[A-Z][a-z][a-z]"); // false

下面是代码

public static class StringEntentions {
    /// <summary>
    /// Indicates whether the current string matches the supplied wildcard pattern.  Behaves the same
    /// as VB's "Like" Operator.
    /// </summary>
    /// <param name="s">The string instance where the extension method is called</param>
    /// <param name="wildcardPattern">The wildcard pattern to match.  Syntax matches VB's Like operator.</param>
    /// <returns>true if the string matches the supplied pattern, false otherwise.</returns>
    /// <remarks>See http://msdn.microsoft.com/en-us/library/swf8kaxw(v=VS.100).aspx</remarks>
    public static bool IsLike(this string s, string wildcardPattern) {
        if (s == null || String.IsNullOrEmpty(wildcardPattern)) return false;
        // turn into regex pattern, and match the whole string with ^$
        var regexPattern = "^" + Regex.Escape(wildcardPattern) + "$";

        // add support for ?, #, *, [], and [!]
        regexPattern = regexPattern.Replace(@"\[!", "[^")
                                   .Replace(@"\[", "[")
                                   .Replace(@"\]", "]")
                                   .Replace(@"\?", ".")
                                   .Replace(@"\*", ".*")
                                   .Replace(@"\#", @"\d");

        var result = false;
        try {
            result = Regex.IsMatch(s, regexPattern);
        }
        catch (ArgumentException ex) {
            throw new ArgumentException(String.Format("Invalid pattern: {0}", wildcardPattern), ex);
        }
        return result;
    }
}
// This file contains extension methods for generic List<> class to operate on sorted lists.
// Duplicate values are OK.
// O(ln(n)) is still much faster then the O(n) of LINQ's searches/filters.
static partial class SortedList
{
    // Return the index of the first element with the key greater then provided.
    // If there's no such element within the provided range, it returns iAfterLast.
    public static int sortedFirstGreaterIndex<tElt, tKey>( this IList<tElt> list, Func<tElt, tKey, int> comparer, tKey key, int iFirst, int iAfterLast )
    {
        if( iFirst < 0 || iAfterLast < 0 || iFirst > list.Count || iAfterLast > list.Count )
            throw new IndexOutOfRangeException();
        if( iFirst > iAfterLast )
            throw new ArgumentException();
        if( iFirst == iAfterLast )
            return iAfterLast;

        int low = iFirst, high = iAfterLast;
        // The code below is inspired by the following article:
        // http://en.wikipedia.org/wiki/Binary_search#Single_comparison_per_iteration
        while( low < high )
        {
            int mid = ( high + low ) / 2;
            // 'mid' might be 'iFirst' in case 'iFirst+1 == iAfterLast'.
            // 'mid' will never be 'iAfterLast'.
            if( comparer( list[ mid ], key ) <= 0 ) // "<=" since we gonna find the first "greater" element
                low = mid + 1;
            else
                high = mid;
        }
        return low;
    }

    // Return the index of the first element with the key greater then the provided key.
    // If there's no such element, returns list.Count.
    public static int sortedFirstGreaterIndex<tElt, tKey>( this IList<tElt> list, Func<tElt, tKey, int> comparer, tKey key )
    {
        return list.sortedFirstGreaterIndex( comparer, key, 0, list.Count );
    }

    // Add an element to the sorted array.
    // This could be an expensive operation if frequently adding elements that sort firstly.
    // This is cheap operation when adding elements that sort near the tail of the list.
    public static int sortedAdd<tElt>( this List<tElt> list, Func<tElt, tElt, int> comparer, tElt elt )
    {
        if( list.Count == 0 || comparer( list[ list.Count - 1 ], elt ) <= 0 )
        {
            // either the list is empty, or the item is greater then all elements already in the collection.
            list.Add( elt );
            return list.Count - 1;
        }
        int ind = list.sortedFirstGreaterIndex( comparer, elt );
        list.Insert( ind, elt );
        return ind;
    }

    // Find first exactly equal element, return -1 if not found.
    public static int sortedFindFirstIndex<tElt, tKey>( this List<tElt> list, Func<tElt, tKey, int> comparer, tKey elt )
    {
        int low = 0, high = list.Count - 1;

        while( low < high )
        {
            int mid = ( high + low ) / 2;
            if( comparer( list[ mid ], elt ) < 0 )
                low = mid + 1;
            else
                high = mid; // this includes the case when we've found an element exactly matching the key
        }
        if( high >= 0 && 0 == comparer( list[ high ], elt ) )
            return high;
        return -1;
    }

    // Return the IEnumerable that returns array elements in the reverse order.
    public static IEnumerable<tElt> sortedReverse<tElt>( this List<tElt> list )
    {
        for( int i=list.Count - 1; i >= 0; i-- )
            yield return list[ i ];
    }
}