让我们把你的优秀和最喜欢的扩展方法列一个列表。
要求是必须发布完整的代码,以及如何使用它的示例和解释。
基于对这个主题的高度兴趣,我在Codeplex上建立了一个名为extensionoverflow的开源项目。
请将您的回答标记为接受,以便将代码放入Codeplex项目。
请张贴完整的源代码,而不是一个链接。
Codeplex上新闻:
24.08.2010 Codeplex页面现在在这里:http://extensionoverflow.codeplex.com/
11.11.2008 XmlSerialize / XmlDeserialize现在是实现和单元测试。
11.11.2008仍有发展空间。;-)现在就加入!
11.11.2008第三位贡献者加入了ExtensionOverflow,欢迎加入BKristensen
11.11.2008 FormatWith现在是实现和单元测试。
09.11.2008第二个贡献者加入ExtensionOverflow。欢迎来到chakrit。
我们需要更多的开发人员。: -)
09.11.2008 ThrowIfArgumentIsNull现已在Codeplex上实现和单元测试。
我喜欢下面这些方法来处理带有Flags属性集的枚举:
public static bool AnyOf(this object mask, object flags)
{
return ((int)mask & (int)flags) != 0;
}
public static bool AllOf(this object mask, object flags)
{
return ((int)mask & (int)flags) == (int)flags;
}
public static object SetOn(this object mask, object flags)
{
return (int)mask | (int)flags;
}
etc.
使用示例:
var options = SomeOptions.OptionA;
options = options.SetOn(OptionB);
options = options.SetOn(OptionC);
if (options.AnyOf(SomeOptions.OptionA | SomeOptions.OptionB))
{
etc.
原始方法来自本文:http://www.codeproject.com/KB/cs/masksandflags.aspx?display=Print
我只是把它们转换成扩展方法。
但它们的一个问题是对象类型的参数,这意味着所有对象最终都被这些方法扩展,而理想情况下,它们应该只应用于枚举。
更新
根据评论,你可以绕过“签名污染”,以牺牲性能为代价,如下所示:
public static bool AnyOf(this Enum mask, object flags)
{
return (Convert.ToInt642(mask) & (int)flags) != 0;
}
ThrowIfArgumentIsNull是做空检查的好方法,我们都应该这样做。
public static class Extensions
{
public static void ThrowIfArgumentIsNull<T>(this T obj, string parameterName) where T : class
{
if (obj == null) throw new ArgumentNullException(parameterName + " not allowed to be null");
}
}
下面是使用它的方法,它适用于您的命名空间中的所有类或任何您使用该命名空间的地方。
internal class Test
{
public Test(string input1)
{
input1.ThrowIfArgumentIsNull("input1");
}
}
在CodePlex项目上使用这段代码是可以的。
我还没有看到任何关于这个问题的答案…
public static string[] Split(this string value, string regexPattern)
{
return value.Split(regexPattern, RegexOptions.None);
}
public static string[] Split(this string value, string regexPattern,
RegexOptions options)
{
return Regex.Split(value, regexPattern, options);
}
用法:
var obj = "test1,test2,test3";
string[] arrays = obj.Split(",");
我最喜欢的是字符串上的IsLike()扩展。IsLike()匹配VB的Like操作符,当你不想写一个完整的正则表达式来解决你的问题时,它很方便。用法是这样的:
"abc".IsLike("a*"); // true
"Abc".IsLike("[A-Z][a-z][a-z]"); // true
"abc123".IsLike("*###"); // true
"hat".IsLike("?at"); // true
"joe".IsLike("[!aeiou]*"); // true
"joe".IsLike("?at"); // false
"joe".IsLike("[A-Z][a-z][a-z]"); // false
下面是代码
public static class StringEntentions {
/// <summary>
/// Indicates whether the current string matches the supplied wildcard pattern. Behaves the same
/// as VB's "Like" Operator.
/// </summary>
/// <param name="s">The string instance where the extension method is called</param>
/// <param name="wildcardPattern">The wildcard pattern to match. Syntax matches VB's Like operator.</param>
/// <returns>true if the string matches the supplied pattern, false otherwise.</returns>
/// <remarks>See http://msdn.microsoft.com/en-us/library/swf8kaxw(v=VS.100).aspx</remarks>
public static bool IsLike(this string s, string wildcardPattern) {
if (s == null || String.IsNullOrEmpty(wildcardPattern)) return false;
// turn into regex pattern, and match the whole string with ^$
var regexPattern = "^" + Regex.Escape(wildcardPattern) + "$";
// add support for ?, #, *, [], and [!]
regexPattern = regexPattern.Replace(@"\[!", "[^")
.Replace(@"\[", "[")
.Replace(@"\]", "]")
.Replace(@"\?", ".")
.Replace(@"\*", ".*")
.Replace(@"\#", @"\d");
var result = false;
try {
result = Regex.IsMatch(s, regexPattern);
}
catch (ArgumentException ex) {
throw new ArgumentException(String.Format("Invalid pattern: {0}", wildcardPattern), ex);
}
return result;
}
}
// This file contains extension methods for generic List<> class to operate on sorted lists.
// Duplicate values are OK.
// O(ln(n)) is still much faster then the O(n) of LINQ's searches/filters.
static partial class SortedList
{
// Return the index of the first element with the key greater then provided.
// If there's no such element within the provided range, it returns iAfterLast.
public static int sortedFirstGreaterIndex<tElt, tKey>( this IList<tElt> list, Func<tElt, tKey, int> comparer, tKey key, int iFirst, int iAfterLast )
{
if( iFirst < 0 || iAfterLast < 0 || iFirst > list.Count || iAfterLast > list.Count )
throw new IndexOutOfRangeException();
if( iFirst > iAfterLast )
throw new ArgumentException();
if( iFirst == iAfterLast )
return iAfterLast;
int low = iFirst, high = iAfterLast;
// The code below is inspired by the following article:
// http://en.wikipedia.org/wiki/Binary_search#Single_comparison_per_iteration
while( low < high )
{
int mid = ( high + low ) / 2;
// 'mid' might be 'iFirst' in case 'iFirst+1 == iAfterLast'.
// 'mid' will never be 'iAfterLast'.
if( comparer( list[ mid ], key ) <= 0 ) // "<=" since we gonna find the first "greater" element
low = mid + 1;
else
high = mid;
}
return low;
}
// Return the index of the first element with the key greater then the provided key.
// If there's no such element, returns list.Count.
public static int sortedFirstGreaterIndex<tElt, tKey>( this IList<tElt> list, Func<tElt, tKey, int> comparer, tKey key )
{
return list.sortedFirstGreaterIndex( comparer, key, 0, list.Count );
}
// Add an element to the sorted array.
// This could be an expensive operation if frequently adding elements that sort firstly.
// This is cheap operation when adding elements that sort near the tail of the list.
public static int sortedAdd<tElt>( this List<tElt> list, Func<tElt, tElt, int> comparer, tElt elt )
{
if( list.Count == 0 || comparer( list[ list.Count - 1 ], elt ) <= 0 )
{
// either the list is empty, or the item is greater then all elements already in the collection.
list.Add( elt );
return list.Count - 1;
}
int ind = list.sortedFirstGreaterIndex( comparer, elt );
list.Insert( ind, elt );
return ind;
}
// Find first exactly equal element, return -1 if not found.
public static int sortedFindFirstIndex<tElt, tKey>( this List<tElt> list, Func<tElt, tKey, int> comparer, tKey elt )
{
int low = 0, high = list.Count - 1;
while( low < high )
{
int mid = ( high + low ) / 2;
if( comparer( list[ mid ], elt ) < 0 )
low = mid + 1;
else
high = mid; // this includes the case when we've found an element exactly matching the key
}
if( high >= 0 && 0 == comparer( list[ high ], elt ) )
return high;
return -1;
}
// Return the IEnumerable that returns array elements in the reverse order.
public static IEnumerable<tElt> sortedReverse<tElt>( this List<tElt> list )
{
for( int i=list.Count - 1; i >= 0; i-- )
yield return list[ i ];
}
}