让我们把你的优秀和最喜欢的扩展方法列一个列表。

要求是必须发布完整的代码,以及如何使用它的示例和解释。

基于对这个主题的高度兴趣,我在Codeplex上建立了一个名为extensionoverflow的开源项目。

请将您的回答标记为接受,以便将代码放入Codeplex项目。

请张贴完整的源代码,而不是一个链接。

Codeplex上新闻:

24.08.2010 Codeplex页面现在在这里:http://extensionoverflow.codeplex.com/

11.11.2008 XmlSerialize / XmlDeserialize现在是实现和单元测试。

11.11.2008仍有发展空间。;-)现在就加入!

11.11.2008第三位贡献者加入了ExtensionOverflow,欢迎加入BKristensen

11.11.2008 FormatWith现在是实现和单元测试。

09.11.2008第二个贡献者加入ExtensionOverflow。欢迎来到chakrit。

我们需要更多的开发人员。: -)

09.11.2008 ThrowIfArgumentIsNull现已在Codeplex上实现和单元测试。


当前回答

public static class EnumerableExtensions
{
    [Pure]
    public static U MapReduce<T, U>(this IEnumerable<T> enumerable, Func<T, U> map, Func<U, U, U> reduce)
    {
        CodeContract.RequiresAlways(enumerable != null);
        CodeContract.RequiresAlways(enumerable.Skip(1).Any());
        CodeContract.RequiresAlways(map != null);
        CodeContract.RequiresAlways(reduce != null);
        return enumerable.AsParallel().Select(map).Aggregate(reduce);
    }
    [Pure]
    public static U MapReduce<T, U>(this IList<T> list, Func<T, U> map, Func<U, U, U> reduce)
    {
        CodeContract.RequiresAlways(list != null);
        CodeContract.RequiresAlways(list.Count >= 2);
        CodeContract.RequiresAlways(map != null);
        CodeContract.RequiresAlways(reduce != null);
        U result = map(list[0]);
        for (int i = 1; i < list.Count; i++)
        {
            result = reduce(result,map(list[i]));
        }
        return result;
    }

    //Parallel version; creates garbage
    [Pure]
    public static U MapReduce<T, U>(this IList<T> list, Func<T, U> map, Func<U, U, U> reduce)
    {
        CodeContract.RequiresAlways(list != null);
        CodeContract.RequiresAlways(list.Skip(1).Any());
        CodeContract.RequiresAlways(map != null);
        CodeContract.RequiresAlways(reduce != null);

        U[] mapped = new U[list.Count];
        Parallel.For(0, mapped.Length, i =>
            {
                mapped[i] = map(list[i]);
            });
        U result = mapped[0];
        for (int i = 1; i < list.Count; i++)
        {
            result = reduce(result, mapped[i]);
        }
        return result;
    }

}

其他回答

这是我今天刚创建的一个。

// requires .NET 4

public static TReturn NullOr<TIn, TReturn>(this TIn obj, Func<TIn, TReturn> func,
        TReturn elseValue = default(TReturn)) where TIn : class
    { return obj != null ? func(obj) : elseValue; }

// versions for CLR 2, which doesn't support optional params

public static TReturn NullOr<TIn, TReturn>(this TIn obj, Func<TIn, TReturn> func,
        TReturn elseValue) where TIn : class
    { return obj != null ? func(obj) : elseValue; }
public static TReturn NullOr<TIn, TReturn>(this TIn obj, Func<TIn, TReturn> func)
        where TIn : class
    { return obj != null ? func(obj) : default(TReturn); }

它让你这样做:

var lname = thingy.NullOr(t => t.Name).NullOr(n => n.ToLower());

哪个比这个更流畅,(依我看)更容易阅读:

var lname = (thingy != null ? thingy.Name : null) != null
    ? thingy.Name.ToLower() : null;

在序列化和配置上,最好使用长DateTime,因此:

    public static readonly DateTime Epoch = new DateTime(1970, 1, 1, 0, 0, 0);

    public static long ToUnixTimestamp(this DateTime dateTime)
    {
        return (long) (dateTime - Epoch).TotalSeconds;
    }

    public static long ToUnixUltraTimestamp(this DateTime dateTime)
    {
        return (long) (dateTime - Epoch).TotalMilliseconds;
    }

和向后

    public static DateTime ToDateTime(this long unixDateTime)
    {
        return Epoch.AddSeconds(unixDateTime);
    }

    public static DateTime ToDateTimeUltra(this long unixUltraDateTime)
    {
        return Epoch.AddMilliseconds(unixUltraDateTime);
    }

空格规范化非常有用,特别是在处理用户输入时:

namespace Extensions.String
{
    using System.Text.RegularExpressions;

    public static class Extensions
    {
        /// <summary>
        /// Normalizes whitespace in a string.
        /// Leading/Trailing whitespace is eliminated and
        /// all sequences of internal whitespace are reduced to
        /// a single SP (ASCII 0x20) character.
        /// </summary>
        /// <param name="s">The string whose whitespace is to be normalized</param>
        /// <returns>a normalized string</returns>
        public static string NormalizeWS( this string @this )
        {
            string src        = @this ?? "" ;
            string normalized = rxWS.Replace( src , m =>{
                  bool isLeadingTrailingWS = ( m.Index == 0 || m.Index+m.Length == src.Length ? true : false ) ;
                  string p                 = ( isLeadingTrailingWS ? "" : " " ) ;
                  return p ;
                }) ;

            return normalized ;

        }
        private static Regex rxWS = new Regex( @"\s+" ) ;
    }
}

我已经实现了一个扩展方法包(在http://foop.codeplex.com/上可用),其中一些是我日常使用的:

// the most beloved extension method for me is Pipe:
<%= variable.Pipe(x => this.SomeFunction(x)).Pipe(y =>
{
    ...;
    return this.SomeOtherFunction(y);
}) %>

var d = 28.December(2009); // some extension methods for creating DateTime
DateTime justDatePart = d.JustDate();
TimeSpan justTimePart = d.JustTime();
var nextTime = d.Add(5.Hours());

using(StreamReader reader = new StreamReader("lines-of-data-file-for-example")) {
    ...
    // for reading streams line by line and usable in LINQ
    var query = from line in reader.Lines(); 
                where line.Contains(_today)
                select new { Parts = PartsOf(line), Time = _now };
}

500.Sleep();

XmlSerialize and XmlDeserialize

IsNull and IsNotNull

IfTrue, IfFalse and Iff:
true.IfTrue(() => Console.WriteLine("it is true then!");

IfNull and IfNotNull

如果你需要检查字符串的Is All char为0:

 static public bool   IsAllZero            (this string input)
        {
            if(string.IsNullOrEmpty(input))
                return true;
            foreach (char ch in input)
            {
                if(ch != '0')
                    return false;
            }
            return true;
        }